CONNECT WITH LEARNSMART FOR COWAN: MICR
3rd Edition
ISBN: 2818440123740
Author: Cowan
Publisher: MCG
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Chapter 20, Problem 8Q
Summary Introduction
To determine:
The regions where anaerobes colonize the mouth for their survival.
Introduction:
Dental caries which is also called tooth decay is most common infectious disease of human being. It involves dissolution of solid tooth surface because of
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Chapter 20 Solutions
CONNECT WITH LEARNSMART FOR COWAN: MICR
Ch. 20.1 - Prob. 1AYPCh. 20.1 - List the natural defenses present in the...Ch. 20.1 - Prob. 1NPCh. 20.2 - List the types of normal biota presently known to...Ch. 20.2 - Describe how our view has changed of normal biota...Ch. 20.3 - List the possible causative agents, modes of...Ch. 20.3 - Prob. 6AYPCh. 20.3 - Prob. 7AYPCh. 20.3 - Identify the most important features of mumps,...Ch. 20.3 - Differentiate among the main types of hepatitis,...
Ch. 20.3 - Prob. 1MMCh. 20.3 - Prob. 2NPCh. 20.3 - Prob. 3NPCh. 20.3 - Q. Why are the effects of jaundice so widespread...Ch. 20.3 - Prob. 4NPCh. 20.4 - Prob. 10AYPCh. 20.4 - Prob. 11AYPCh. 20.4 - Prob. 12AYPCh. 20.4 - Prob. 5NPCh. 20 - Prob. 1QCh. 20 - Healthy teeth are important for good nutrition and...Ch. 20 - Prob. 3QCh. 20 - Prob. 4QCh. 20 - Why is heating food contaminated with...Ch. 20 - Prob. 6QCh. 20 - Prob. 7QCh. 20 - Prob. 8QCh. 20 - Prob. 9QCh. 20 - Prob. 10QCh. 20 - Why is it thought that the Shiga toxin in...Ch. 20 - Prob. 12QCh. 20 - Prob. 13QCh. 20 - Prob. 14QCh. 20 - Prob. 15QCh. 20 - Prob. 16QCh. 20 - Describe the populations that are most at risk for...Ch. 20 - Prob. 18QCh. 20 - Prob. 19QCh. 20 - Prob. 20QCh. 20 - Prob. 21QCh. 20 - From chapter 11, figure 11.2a. Imagine for a...
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- A sample of blood was taken from the above individual and prepared for haemoglobin analysis. However, when water was added the cells did not lyse and looked normal in size and shape. The technician suspected that they had may have made an error in the protocol – what is the most likely explanation? The cell membranes are more resistant than normal. An isotonic solution had been added instead of water. A solution of 0.1 M NaCl had been added instead of water. Not enough water had been added to the red blood cell pellet. The man had sickle-cell anaemia.arrow_forwardA sample of blood was taken from the above individual and prepared for haemoglobin analysis. However, when water was added the cells did not lyse and looked normal in size and shape. The technician suspected that they had may have made an error in the protocol – what is the most likely explanation? The cell membranes are more resistant than normal. An isotonic solution had been added instead of water. A solution of 0.1 M NaCl had been added instead of water. Not enough water had been added to the red blood cell pellet. The man had sickle-cell anaemia.arrow_forwardWith reference to their absorption spectra of the oxy haemoglobin intact line) and deoxyhemoglobin (broken line) shown in Figure 2 below, how would you best explain the reason why there are differences in the major peaks of the spectra? Figure 2. SPECTRA OF OXYGENATED AND DEOXYGENATED HAEMOGLOBIN OBTAINED WITH THE RECORDING SPECTROPHOTOMETER 1.4 Abs < 0.8 06 0.4 400 420 440 460 480 500 520 540 560 580 600 nm 1. The difference in the spectra is due to a pH change in the deoxy-haemoglobin due to uptake of CO2- 2. There is more oxygen-carrying plasma in the oxy-haemoglobin sample. 3. The change in Mr due to oxygen binding causes the oxy haemoglobin to have a higher absorbance peak. 4. Oxy-haemoglobin is contaminated by carbaminohemoglobin, and therefore has a higher absorbance peak 5. Oxy-haemoglobin absorbs more light of blue wavelengths and less of red wavelengths than deoxy-haemoglobinarrow_forward
- With reference to their absorption spectra of the oxy haemoglobin intact line) and deoxyhemoglobin (broken line) shown in Figure 2 below, how would you best explain the reason why there are differences in the major peaks of the spectra? Figure 2. SPECTRA OF OXYGENATED AND DEOXYGENATED HAEMOGLOBIN OBTAINED WITH THE RECORDING SPECTROPHOTOMETER 1.4 Abs < 0.8 06 0.4 400 420 440 460 480 500 520 540 560 580 600 nm 1. The difference in the spectra is due to a pH change in the deoxy-haemoglobin due to uptake of CO2- 2. There is more oxygen-carrying plasma in the oxy-haemoglobin sample. 3. The change in Mr due to oxygen binding causes the oxy haemoglobin to have a higher absorbance peak. 4. Oxy-haemoglobin is contaminated by carbaminohemoglobin, and therefore has a higher absorbance peak 5. Oxy-haemoglobin absorbs more light of blue wavelengths and less of red wavelengths than deoxy-haemoglobinarrow_forwardWhich ONE of the following is FALSE regarding haemoglobin? It has two alpha subunits and two beta subunits. The subunits are joined by disulphide bonds. Each subunit covalently binds a haem group. Conformational change in one subunit can be transmitted to another. There are many variant ("mutant") forms of haemoglobin that are not harmful.arrow_forwardWhich ONE of the following is FALSE regarding haemoglobin? It has two alpha subunits and two beta subunits. The subunits are joined by disulphide bonds. Each subunit covalently binds a haem group. Conformational change in one subunit can be transmitted to another. There are many variant ("mutant") forms of haemoglobin that are not harmful.arrow_forward
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