Concept explainers
(a)
Interpretation:
The relationship between restriction enzymes, hybridization, electrophoresis, and gene cloning has to be explained.
Concept Introduction:
The recombinant gene technology involves the synthesis of DNA hybrids with the use of restriction enzymes or endonucleases. After digestion with endonucleases, the fragments thus separated are analyzed by electrophoresis. The DNA cloning tools are essential for gene cloning and are developed during the recombinant DNA studies.
(b)
Interpretation:
The relationship between the components of DNA (nitrogenous bases, 2′-deoxyribose, and phosphoryl groups) and the three-dimensional structure of the DNA molecules have to be explained.
Concept Introduction:
Each nucleotide consists of sugar that is either ribose or deoxyribose, one of the nitrogenous bases, and one or more phosphoryl groups. The only difference is the presence of hydrogen atom at the 2’ position in case of deoxyribose compared to ribose.
The nucleotide that contains the ribose sugar is termed as ribonucleotide while the one that has deoxyribose sugar is termed as deoxyribonucleotide. DNA is a
(c)
Interpretation:
The relationship of the sequences of nucleotides in a DNA molecule and the sequence of amino acids in a protein has to be explained.
Concept Introduction:
Proteins are considered the most abundant macromolecules in the cell. Proteins, carbohydrate, and fat are an energy source in the diet. They can be oxidized to provide energy to the body. Also, amino acids are generated in the digestion process of proteins. These amino acids are used in the biosynthesis of new cellular protein and many important nitrogen compounds such as heme group, DNA, RNA.
DNA is a polymer of nucleotides and consist of deoxyribose sugar unit. Each nucleotide consists of sugar that is either ribose or deoxyribose, one of the nitrogenous bases, and one or more phosphoryl groups. The genetic code illustrates all the possible codons along with the amino acids they code for.
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Chapter 20 Solutions
GENERAL, ORGANIC,BIO CHP.10-23-ACCESS>I
- Could you please solve the first problem in this way and present it similarly but color-coded or step by step so I can understand it better? Thank you!arrow_forwardCould you please solve the first problem in this way and present it similarly but color-coded or step by step so I can understand it better? Thank you!arrow_forwardCould you please solve the first problem in this way and present it similarly but (color-coded) and step by step so I can understand it better? Thank you! I want to see what they are doingarrow_forward
- Can you please help mne with this problem. Im a visual person, so can you redraw it, potentislly color code and then as well explain it. I know im given CO2 use that to explain to me, as well as maybe give me a second example just to clarify even more with drawings (visuals) and explanations.arrow_forwardPart 1. Aqueous 0.010M AgNO 3 is slowly added to a 50-ml solution containing both carbonate [co32-] = 0.105 M and sulfate [soy] = 0.164 M anions. Given the ksp of Ag2CO3 and Ag₂ soy below. Answer the ff: Ag₂ CO3 = 2 Ag+ caq) + co} (aq) ksp = 8.10 × 10-12 Ag₂SO4 = 2Ag+(aq) + soy² (aq) ksp = 1.20 × 10-5 a) which salt will precipitate first? (b) What % of the first anion precipitated will remain in the solution. by the time the second anion starts to precipitate? (c) What is the effect of low pH (more acidic) condition on the separate of the carbonate and sulfate anions via silver precipitation? What is the effect of high pH (more basic)? Provide appropriate explanation per answerarrow_forwardPart 4. Butanoic acid (ka= 1.52× 10-5) has a partition coefficient of 3.0 (favors benzene) when distributed bet. water and benzene. What is the formal concentration of butanoic acid in each phase when 0.10M aqueous butanoic acid is extracted w❘ 25 mL of benzene 100 mL of a) at pit 5.00 b) at pH 9.00arrow_forward
- Calculate activation energy (Ea) from the following kinetic data: Temp (oC) Time (s) 23.0 180. 32.1 131 40.0 101 51.8 86.0 Group of answer choices 0.0269 kJ/mole 2610 kJ/mole 27.6 kJ/mole 0.215 kJ/mole 20.8 kJ/molearrow_forwardCalculate activation energy (Ea) from the following kinetic data: Temp (oC) Time (s) 23.0 180. 32.1 131 40.0 101 51.8 86.0 choices: 0.0269 kJ/mole 2610 kJ/mole 27.6 kJ/mole 0.215 kJ/mole 20.8 kJ/molearrow_forwardCalculate activation energy (Ea) from the following kinetic data: Temp (oC) Time (s) 23.0 180. 32.1 131 40.0 101 51.8 86.0arrow_forward
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