The counts per minute per gram of carbon from a 15,000-year-old sample are to be measured. Radioactive dating work will well for small samples of 10 mg or less is to be determined. Concept Introduction : The probability of decay per unit time of radioactive nuclei is called Decay constant. The decay constant is related to the half-life of the nuclide T 1 / 2 by the following relation: T 1 / 2 = ln 2 / λ

Question

Want to see the full answer?

Answer 1

Question

Chapter 20, Problem 28E

Interpretation Introduction

Interpretation: The counts per minute per gram of carbon from a 15,000-year-old sample are to be measured. Radioactive dating work will well for small samples of 10 mg or less is to be determined.

Concept Introduction:The probability of decay per unit time of radioactive nuclei is called Decay constant. The decay constant is related to the half-life of the nuclide T ₁_/₂ by the following relation:

T 1/2 = ln 2/λ

Expert Solution & Answer

Want to see the full answer?

Check out a sample textbook solution

See solution

Students have asked these similar questions

In the spectroscopic technique known as photoelectron spectroscopy (PES), ultraviolet radiation is directed at an atom or molecule. Electrons are ejected from the valence shell and their kinetic energies are measured. Since the energy of the incident ultraviolet photons is known and the kinetic energy of the ejected electron is measured, the ionization energy, I, can be deduced because total energy is conserved. (a) Show that the velocity, v, of the ejected electron and the frequency, n, of the incident radiation are related by hv = I + (1/2)mv^2? (b) Use this relation to calculate the ionization energy of a rubidium atom, knowing that light of wavelength 58.4 nm produces electrons with a velocity of 2,450 km/s Recall that 1 J = 1 kg.m^2/s^2

I) In Millikan's experiment, each droplet observed by the technicians contained an even number of electrons. If they had been unaware of this limitation, how would it have affected their report of an electron's charge?II) Millikan measured the charge of an electron in electrostatic units, esu. The data he collected included the following series of charges found on oil drops: 9.60 X 10^-10 esu, 1.92 X 10^-9 esu; 2.40 X 10^-9 esu; 2.88 X 10^-9 esu; and 4.80 X 10^-9 esu. (a) From this series, find the probable charge of the electron in electrostatic units. (b) Estimate the number of electrons in an oil drop with a charge of 6.72 X 10^-9 esu. The actual charge (in Coulombs) of an electron is 1.602 X 10^-19 C. What is the relationship between esu and Coulombs?

my ccc edu - Search X Quick Access X D2L Homepage - Spring 2025 x N Netflix X Dimensional Analysis - A x+ pp.aktiv.com Q ☆ X Question 59 of 70 The volume of 1 unit of plasma is 200.0 mL If the recommended dosage for adult patients is 10.0 mL per kg of body mass, how many units are needed for a patient with a body mass of 80.0 kg ? 80.0 kg 10.0 DAL 1 units X X 4.00 units 1 1 Jeg 200.0 DAL L 1 units X 200.0 mL = 4.00 units ADD FACTOR *( ) DELETE ANSWER RESET D 200.0 2.00 1.60 × 10³ 80.0 4.00 0.0400 0.250 10.0 8.00 & mL mL/kg kg units/mL L unit Q Search delete prt sc 111 110 19