Ancient meat eating . The amount of meat in prehistoric diets can be determined by measuring the ratio of the isotopes nitrogen-15 to nitrogen-14 in bone from human remains. Carnivores concentrate 15 N, so this ratio tells archaeologists how much meat was consumed by ancient people. Suppose you use a velocity selector to obtain singly ionized (missing one electron) nitrogen atoms of speed 8.50 km/s and bend them along a semicircle within a uniform magnetic field If the 14 N atoms travel along a semicircle with a diameter of 29.2 cm, find the separation of the 14 N and 15 N isotopes at the detector. The measured masses of these isotopes are 2.32 × 10 −26 kg ( 14 N) and 2.49 × 10 −26 kg ( 15 N).
Ancient meat eating . The amount of meat in prehistoric diets can be determined by measuring the ratio of the isotopes nitrogen-15 to nitrogen-14 in bone from human remains. Carnivores concentrate 15 N, so this ratio tells archaeologists how much meat was consumed by ancient people. Suppose you use a velocity selector to obtain singly ionized (missing one electron) nitrogen atoms of speed 8.50 km/s and bend them along a semicircle within a uniform magnetic field If the 14 N atoms travel along a semicircle with a diameter of 29.2 cm, find the separation of the 14 N and 15 N isotopes at the detector. The measured masses of these isotopes are 2.32 × 10 −26 kg ( 14 N) and 2.49 × 10 −26 kg ( 15 N).
Ancient meat eating. The amount of meat in prehistoric diets can be determined by measuring the ratio of the isotopes nitrogen-15 to nitrogen-14 in bone from human remains. Carnivores concentrate 15N, so this ratio tells archaeologists how much meat was consumed by ancient people. Suppose you use a velocity selector to obtain singly ionized (missing one electron) nitrogen atoms of speed 8.50 km/s and bend them along a semicircle within a uniform magnetic field If the 14N atoms travel along a semicircle with a diameter of 29.2 cm, find the separation of the 14N and 15N isotopes at the detector. The measured masses of these isotopes are 2.32 × 10−26 kg (14N) and 2.49 × 10−26 kg (15N).
Use the following information to answer the next question.
Two mirrors meet an angle, a, of 105°. A ray of light is incident upon mirror A at an angle, i, of
42°. The ray of light reflects off mirror B and then enters water, as shown below:
A
Incident
ray at A
Note: This diagram is not to
scale.
Air (n = 1.00)
Water (n = 1.34)
B
Use the following information to answer the next question.
Two mirrors meet an angle, a, of 105°. A ray of light is incident upon mirror A at an angle, i, of
42°. The ray of light reflects off mirror B and then enters water, as shown below:
A
Incident
ray at A
Note: This diagram is not to
scale.
Air (n = 1.00)
Water (n = 1.34)
B
Good explanation it sure experts solve it.
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