Chapter 20, Problem 20.83QP

Interpretation Introduction

Interpretation: The energy released by ${}_{\text{92}}^{\text{235}}\text{U}$ isotope decay to ${}_{\text{90}}^{\text{234}}\text{Th}$ should be calculated. &determine the rate of ejected particle.

Concept Introduction:

• Half-life period: The time required to reduce the half of its original value.
• This is denoted by: ${\text{t}}_{\text{1/2}}$
• This term is popularly use in nuclear chemistry, to describe the stability & unstability of atoms or radioactive decay.
• For determination of first order rate constant K in half –life period we use

  $\text{K=}\frac{\text{0}\text{.693}}{{\text{t}}_{\text{1/2}}}$ Equation.

• The half-life in first order does not depends upon the initial concentration.

To determine: The energy released by ${}_{\text{92}}^{\text{235}}\text{U}$ isotope decay to ${}_{\text{90}}^{\text{234}}\text{Th}$ be calculated.

Formula:

First order rate constant: $\text{K=}\frac{\text{0}\text{.693}}{{\text{t}}_{\text{1/2}}}$

Given:

The atomic masses are is given by as follows ${}_{\text{92}}^{\text{235}}\text{U}$: 238.05078amu.

${\text{He}}^{\text{4}}$: 4.002603amu.