CHEMISTRY-MASTERINGCHEMISTRY W/ETEXT
CHEMISTRY-MASTERINGCHEMISTRY W/ETEXT
8th Edition
ISBN: 9780135204634
Author: Robinson
Publisher: PEARSON
Question
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Chapter 20, Problem 20.1P
Interpretation Introduction

(a)

Interpretation:

The balanced nuclear reaction of the beta emission of R44106u needs to be determined.

R44106e-10  +  ?

Concept introduction:

The nuclear reactions are a type of chemical process which leads to the formation of some new nuclei with the emission of certain particles. Usually, alpha or beta particles or gamma rays are emitted as a side product with some new daughter nuclei. The nuclear reactions follow the conservation of atomic number and mass number of nuclei. It means the sum of the mass number on both sides should be the same and the sum of the atomic number of nuclei should be the same on both sides.

Expert Solution
Check Mark

Answer to Problem 20.1P

R44106e-10  +  R45106h

Explanation of Solution

In the given nuclear reaction, R44106 is involved in beta decay and emit one beta particle. The beta particle is a negatively charged particle with -1 charge and 0 mass number, hence the daughter nuclei must have one atomic numberless and same mass number as of R44106. The element one atomic number less from R45106h, therefore, the balance nuclear reaction must be:

R44106e-10  +  R45106h

Interpretation Introduction

(b)

Interpretation:

The balanced nuclear reaction of the alpha emission of B83189i :

B83189H24e  +  ?

Concept introduction:

The nuclear reactions are a type of chemical process which leads to the formation of some new nuclei with the emission of certain particles. Usually, alpha or beta particles or gamma rays are emitted as a side product with some new daughter nuclei. The nuclear reactions follow the conservation of atomic number and mass number of nuclei. It means the sum of the mass number on both sides should be the same and the sum of the atomic number of nuclei should be the same on both sides.

Expert Solution
Check Mark

Answer to Problem 20.1P

B83189H24e  +  T81185l

Explanation of Solution

In the given nuclear reaction, B83189i is involved in alpha emission and emit one alpha particle. Alpha particle is a positively charged particle with +2 charge and 4 mass number, hence the daughter nuclei must have two atomic numberless and 4 mass numberless as of B83189i. Therefore, the balance of nuclear reaction must be:

B83189H24e  +  T81185l

Interpretation Introduction

(c)

Interpretation:

The balanced nuclear reaction of the electron capture of P84204o needs to be determined.

P84204o +  e-10   ?

Concept introduction:

The nuclear reactions are a type of chemical process which leads to the formation of some new nuclei with the emission of certain particles. Usually, alpha or beta particles or gamma rays are emitted as a side product with some new daughter nuclei. The nuclear reactions follow the conservation of atomic number and mass number of nuclei. It means the sum of the mass number on both sides should be the same and the sum of the atomic number of nuclei should be the same on both sides.

Expert Solution
Check Mark

Answer to Problem 20.1P

P84204o +  e-10   B83204i

Explanation of Solution

In the given nuclear reaction, P84204o is involved in electron caption and captures one electron. Electron is a negatively charged particle with -1 charge and 0 mass number, hence the daughter nuclei must have one atomic numberless and same mass number as of P84204o. Therefore, the balance of nuclear reaction must be:

P84204o +  e-10   B83204i

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Chapter 20 Solutions

CHEMISTRY-MASTERINGCHEMISTRY W/ETEXT

Ch. 20 - Prob. 20.11PCh. 20 - Prob. 20.12ACh. 20 - Prob. 20.13PCh. 20 - Prob. 20.14ACh. 20 - Prob. 20.15PCh. 20 - Prob. 20.16ACh. 20 - Prob. 20.17PCh. 20 - Prob. 20.18ACh. 20 - Prob. 20.19PCh. 20 - Prob. 20.20PCh. 20 - Prob. 20.21PCh. 20 - Prob. 20.22PCh. 20 - Prob. 20.23PCh. 20 - Prob. 20.24PCh. 20 - Prob. 20.25CPCh. 20 - Prob. 20.26SPCh. 20 - Prob. 20.27SPCh. 20 - Prob. 20.28SPCh. 20 - Prob. 20.29SPCh. 20 - Prob. 20.30SPCh. 20 - Prob. 20.31SPCh. 20 - Prob. 20.32SPCh. 20 - Prob. 20.33SPCh. 20 - Prob. 20.34SPCh. 20 - Prob. 20.35SPCh. 20 - Prob. 20.36SPCh. 20 - Prob. 20.37SPCh. 20 - Prob. 20.38SPCh. 20 - Prob. 20.39SPCh. 20 - Prob. 20.40SPCh. 20 - Prob. 20.41SPCh. 20 - Prob. 20.42SPCh. 20 - Prob. 20.43SPCh. 20 - Prob. 20.44SPCh. 20 - Prob. 20.45SPCh. 20 - Prob. 20.46SPCh. 20 - Prob. 20.47SPCh. 20 - Prob. 20.48SPCh. 20 - Prob. 20.49SPCh. 20 - The half-life of indium 111, a radioisotope used...Ch. 20 - The decay constant of plutonium 239 , a waste...Ch. 20 - Prob. 20.52SPCh. 20 - Plutonium 239 has a decay constant of 2.88105 year...Ch. 20 - Prob. 20.54SPCh. 20 - Prob. 20.55SPCh. 20 - A 1.0 mgsampleof79Sedecays initially atarate of...Ch. 20 - Prob. 20.57SPCh. 20 - A sample of 37Ar undergoes 8540...Ch. 20 - Prob. 20.59SPCh. 20 - Prob. 20.60SPCh. 20 - Prob. 20.61SPCh. 20 - Prob. 20.62SPCh. 20 - Prob. 20.63SPCh. 20 - Prob. 20.64SPCh. 20 - Prob. 20.65SPCh. 20 - Prob. 20.66SPCh. 20 - Prob. 20.67SPCh. 20 - Prob. 20.68SPCh. 20 - Prob. 20.69SPCh. 20 - Prob. 20.70SPCh. 20 - Prob. 20.71SPCh. 20 - Prob. 20.72SPCh. 20 - Prob. 20.73SPCh. 20 - Prob. 20.74SPCh. 20 - Prob. 20.75SPCh. 20 - Prob. 20.76SPCh. 20 - Prob. 20.77SPCh. 20 - Prob. 20.78SPCh. 20 - Prob. 20.79SPCh. 20 - Prob. 20.80SPCh. 20 - Prob. 20.81SPCh. 20 - Prob. 20.82SPCh. 20 - Prob. 20.83SPCh. 20 - Prob. 20.84SPCh. 20 - Prob. 20.85SPCh. 20 - Prob. 20.86SPCh. 20 - Prob. 20.87SPCh. 20 - Prob. 20.88SPCh. 20 - Prob. 20.89SPCh. 20 - Prob. 20.90SPCh. 20 - Prob. 20.91SPCh. 20 - Prob. 20.92SPCh. 20 - Prob. 20.93SPCh. 20 - Prob. 20.94SPCh. 20 - Prob. 20.95SPCh. 20 - Prob. 20.96SPCh. 20 - Prob. 20.97SPCh. 20 - Prob. 20.98SPCh. 20 - Prob. 20.99SPCh. 20 - Prob. 20.100SPCh. 20 - Prob. 20.101SPCh. 20 - Prob. 20.102SPCh. 20 - Prob. 20.103SPCh. 20 - Prob. 20.104SPCh. 20 - Prob. 20.105SPCh. 20 - Prob. 20.106SPCh. 20 - Prob. 20.107SPCh. 20 - Prob. 20.108SPCh. 20 - Prob. 20.109SPCh. 20 - Prob. 20.110SPCh. 20 - Prob. 20.111SPCh. 20 - Prob. 20.112SPCh. 20 - Prob. 20.113SPCh. 20 - Prob. 20.114MPCh. 20 - Prob. 20.115MPCh. 20 - Prob. 20.116MPCh. 20 - Prob. 20.117MPCh. 20 - Prob. 20.118MPCh. 20 - Prob. 20.119MPCh. 20 - Prob. 20.120MP
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