Explanation Given info: The power of the heater is 1000 W , mass of the ice is 1.00 kg and the initial temperature of the ice is − 20.0 ° C . All the energy from the heater is absorbed by the ice. The formula to calculate the heat energy required to increase the temperature of the ice is, Q 1 = m ice c ice ( T f − T i ) Here, T i is the initial temperature of the ice. m ice is the mass of the ice. c ice is the specific heat of the ice. Q 1 is the amount of heat required to raise the temperature of the ice. T f is the final temperature of the ice. Substitute 1.00 kg for m ice , − 20.0 ° C for T i , 0 ° C for T f and 290 J / kg ⋅ ° C for c ice in the above equation. Q 1 = ( 1.00 kg ) ( 290 J / kg ⋅ ° C ) ( 0 ° C − ( − 20.0 ° C ) ) = 41800 J When the ice absorbs the heat from the heater the state of the ice changes into water and that heat is known as latent heat. The formula to calculate the heat required to change the state of the ice ia, Q 2 = m ice L f Here, L f is the latent heat of fusion of ice. Q 2 is the amount of energy required to change the state of ice. Substitute 1.00 kg for m ice and 3.33 × 10 5 J / kg for c ice in the above equation. Q 2 = 1.00 kg ( 3.33 × 10 5 J / kg ) = 3.33 × 10 5 J The amount of heat energy required to melt ice is, Q = Q 1 + Q 2 Here, Q is the total amount of heat required

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ISBN: 9780100460300

Author: SERWAY

Publisher: YUZU

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Question

Chapter 20, Problem 20.15OQ

To determine

The time taken by the heater to melt the ice at −20.0 °C .

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Chapter 20 Solutions

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The time taken by the heater to melt the ice at − 20.0 ° C .

Solution Summary: The author explains the formula to calculate the heat energy required to increase the temperature of the ice.

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The time taken by the heater to melt the ice at −20.0 °C .

Chapter 20 Solutions