Concept explainers
The possible cause of the indication of tester (120 volts) between ungrounded (short) slot and grounded (long) slot, and also the same indication between grounded (long) slot and grounding slot (U-shaped).
Answer to Problem 1RQ
Reversed polarity at the receptacle
Explanation of Solution
In residential wiring, the duplex receptacle is the most common receptacle type. On one strap, there are two receptacles. Each receptacle can control an electrical load that is connected by a cord and plug.
A voltage tester is a device that displays estimated voltage values or simply demonstrates whether or not a voltage exists.
A voltage tester is used to evaluate a 15-ampere, 125-volt rated duplex receptacle. Between the short ungrounded and long grounded slots, the tester shows 120 volts. Between the long grounded slot and the U-shaped grounding slot, the tester shows 120 volts.
The likely cause of the indication of tester (120 volts) between ungrounded (short) slot and grounded (long) slot and also the same indication between grounded (long) slot and grounding slot (U-shaped) is Reversed polarity at the receptacle.
Conclusion:
The likely cause of the indication of tester (120 volts) between ungrounded (short) slot and grounded (long) slot and also the same indication between grounded (long) slot and grounding slot (U-shaped) is reversed polarity at the receptacle.
Want to see more full solutions like this?
Chapter 20 Solutions
Residential Construction Academy: House Wiring (MindTap Course List)
- Please solve with stepsarrow_forwardQ.2 a. Determine the net area along route ABCDEF for C15x33.9(Ag=10in2) as shown in Fig. Holes are for %- in bolts. b. compute the design strength if A36 is used 0.650 in 14in 3in 0.400 in 9 in C15 x 33.9 3 in 14 in 2 in 0.650 in (b) (c) 141 3+2-040arrow_forwarda. Determine the net area of the W12x16(Ag=4.71in2) shown in Fig. Assuming that the holes are for 1-in bolts. b. compute the design strength if A36 is used W12 x 16 d-12.00 in -0.220 in 3 in HE -by-3.99 in 3 in 3 in DO 2 in 2 inarrow_forward
- a. Determine the net area of the W12x16(Ag=4.71in2) shown in Fig. Assuming that the holes are for 1-in bolts. b. compute the design strength if A36 is used W12 x 16 d-12.00 in 4-0.220 in 3 in 3 in BO HO by-3.99 in 3 in 3 in DO E 2 in 2 inarrow_forward止 Q.1 Using the lightest W section shape to design the compression member AB shown in Fig. below, the concentrated service dead load and live load is PD-40kips and PL 150kips respectively. The beams and columns are oriented about the major axis and the columns are braced at each story level for out-of-plan buckling. Assume that the same section is used for columns. Use Fy-50 ksi. 32456 Aarrow_forward02. Design a W shape beam is used to support the loads for plastered floor, shown in Figure. Lateral bracing is supplied only at the ends. Depend LRFD and Steel Fy=50ksi. Note: The solution includes compute C, Check deflection at center of beam as well as shear capacity) B P10.5 P=140 W C Hing Hing 159 A 15.ftarrow_forward
Residential Construction Academy: House Wiring (M...Civil EngineeringISBN:9781337402415Author:Gregory W FletcherPublisher:Cengage Learning