undefined Solution The maximum charging voltage across the capacitor when the applied input pulse is increased to 2 00 μ s . V t t = 200 μ s = 8.64 V Given information: Fig: Given circuit Calculation: Although in the given circuit at t=0 capacitor acts as short circuit Draw the modified circuit diagram at t=0 Fig: circuit diagram at t=0 Calculate the current at t=0+ i 0 + = 10 100 × 10 3 i 0 + = 0.1 m A Draw the circuit at t = ∞ At t = ∞ , capacitor acts as open circuit Fig: circuit diagram at t = ∞ Hence, i ∞ = 0 m A Now calculate time constant of the given circuit τ = R C τ = 100 × 10 3 × 0.001 × 10 − 6 τ = 0.1 ms Hence current flowing through capacitor is i t = i ∞ + i 0 + − i ∞ e − t τ plugging values i t = 0 + 0.1 × 10 − 3 − 0 e − t 0.1 × 10 − 3 i t = 0.1 e − t 0.1 × 10 − 3 m A Although expression of charging voltage across capacitor is given by v t = 1 C ∫ t 1 t 2 i t d t Hence, v t = 1 0.001 × 10 − 6 ∫ 0 200 × 10 − 6 0.1 e − t 0.1 × 10 − 3 × 10 − 3 d t v t = 10 − 4 0.001 × 10 − 6 ∫ 0 200 × 10 − 6 e − t 0.1 × 10 − 3 d t v t = 1 0.001 × 10 − 2 ∫ 0 200 × 10 − 6 e − t 0.1 × 10 − 3 d t v t = 10 5 ∫ 0 200 × 10 − 6 e − t 0.1 × 10 − 3 d t solve above integral v t = 10 5 × 0.864 × 10 − 4 v t = 8.64 V Hence, maximum charging voltage when input pulse is increased to 2 00 μ s is V t t = 200 μ s = 8.64 V

10th Edition

ISBN: 9780134880068

Author: Buchla

Publisher: VST

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Ch. 20 - If the input pulse width in Figure 208 is...

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If the input pulse width in Figure 20–8 is increased to 200 μ s, to what maximum voltage will the capacitor charge? Figure 20–8

Solution Summary: The author calculates the maximum charging voltage across the capacitor when the applied input pulse is increased to 200mu s.

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