Answer the question with each of the following code segments. If an error will occur, write ERROR and explain what caused the error. a. What is stored in Count by the following code? b. What is displayed on the screen by the following code? c. What is displayed on the screen by the following code? d. What is stored in P and C after the following code executes?

Question

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Answer 1

Textbook Question

Chapter 20, Problem 1ICA

Answer the question with each of the following code segments. If an error will occur, write ERROR and explain what caused the error.

a. What is stored in Count by the following code?

Chapter 20, Problem 1ICA, Answer the question with each of the following code segments. If an error will occur, write ERROR , example 1

b. What is displayed on the screen by the following code?

Chapter 20, Problem 1ICA, Answer the question with each of the following code segments. If an error will occur, write ERROR , example 2

c. What is displayed on the screen by the following code?

Chapter 20, Problem 1ICA, Answer the question with each of the following code segments. If an error will occur, write ERROR , example 3

d. What is stored in P and C after the following code executes?

Chapter 20, Problem 1ICA, Answer the question with each of the following code segments. If an error will occur, write ERROR , example 4

a.

Expert Solution

To determine

What variable is stored in Count.

Answer to Problem 1ICA

The variable stored in Count is 8.

Explanation of Solution

Given data:

Count =0;

for N=10:-0.2:8.5;

Count=Count+1;

end

Program execution:

Steps to execute the MATLAB program:

1. Open the command window and paste the given program.
2. Press enter.
3. Output is displayed in command window.

Enter Count in the command window and execute the program.

>> Count

Count =

8

Conclusion:

Thus, the variable stored in Count is 8.

b.

Expert Solution

To determine

What is displayed on the screen after executing the given program.

Answer to Problem 1ICA

The output displayed on the screen:

6

12

20

30

42

56

Explanation of Solution

Given data:

for m=3:8

fprintf('%0.0f\n',m^2-m)

end

Program execution:

Steps to execute the MATLAB program:

1. Open the command window and paste the given program.
2. Press enter.
3. Output is displayed in command window.

MATLAB Output after execution of program is displayed as follows.

6

12

20

30

42

56

Conclusion:

Thus, the Output displayed on the screen:

6

12

20

30

42

56

c.

Expert Solution

To determine

What is displayed on the screen after executing the given program.

Answer to Problem 1ICA

The output displayed in the screen is 56.

Explanation of Solution

Given data:

for m=3:8;

M2=m^2-m;

end

fprintf('%0.0f\n',M2)

Program execution:

Steps to execute the MATLAB program:

1. Open the command window and paste the given program.
2. Press enter.
3. Output is displayed in command window.

MATLAB Output after execution of program is displayed as follows.

56

Conclusion:

Thus, the output displayed in the screen is 56.

d.

Expert Solution

To determine

What variables are stored in p and C.

Answer to Problem 1ICA

The variables stored in in p and C are p=945 and C=4.

Explanation of Solution

Given data:

S=3;

I=2;

P=1;

C=0;

for K=S:I:S^I

P=P*K;

C=C+1;

end

Program execution:

Steps to execute the MATLAB program:

1. Open the command window and paste the given program.
2. Press enter.
3. Output is displayed in command window.

Enter P and C in the command window and execute the program.

>> P

P =

945

>> C

C =

4

Conclusion:

Thus, the variables stored in in p and C are p=945 and C=4.

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Students have asked these similar questions

As shown in the figure below, moist air at T₁ = 36°C, 1 bar, and 35% relative humidity enters a heat exchanger operating at steady state with a volumetric flow rate of 10 m³/min and is cooled at constant pressure to 22°C. Ignoring kinetic and potential energy effects, determine: (a) the dew point temperature at the inlet, in °C. (b) the mass flow rate of moist air at the exit, in kg/min. (c) the relative humidity at the exit. (d) the rate of heat transfer from the moist air stream, in kW. (AV)1, T1 P₁ = 1 bar 11 = 35% 120 T₂=22°C P2 = 1 bar

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Answer 2

Textbook Question

Chapter 20, Problem 1ICA

Answer the question with each of the following code segments. If an error will occur, write ERROR and explain what caused the error.

a. What is stored in Count by the following code?

Chapter 20, Problem 1ICA, Answer the question with each of the following code segments. If an error will occur, write ERROR , example 1

b. What is displayed on the screen by the following code?

Chapter 20, Problem 1ICA, Answer the question with each of the following code segments. If an error will occur, write ERROR , example 2

c. What is displayed on the screen by the following code?

Chapter 20, Problem 1ICA, Answer the question with each of the following code segments. If an error will occur, write ERROR , example 3

d. What is stored in P and C after the following code executes?

Chapter 20, Problem 1ICA, Answer the question with each of the following code segments. If an error will occur, write ERROR , example 4

a.

Expert Solution

To determine

What variable is stored in Count.

Answer to Problem 1ICA

The variable stored in Count is 8.

Explanation of Solution

Given data:

Count =0;

for N=10:-0.2:8.5;

Count=Count+1;

end

Program execution:

Steps to execute the MATLAB program:

1. Open the command window and paste the given program.
2. Press enter.
3. Output is displayed in command window.

Enter Count in the command window and execute the program.

>> Count

Count =

8

Conclusion:

Thus, the variable stored in Count is 8.

b.

Expert Solution

To determine

What is displayed on the screen after executing the given program.

Answer to Problem 1ICA

The output displayed on the screen:

6

12

20

30

42

56

Explanation of Solution

Given data:

for m=3:8

fprintf('%0.0f\n',m^2-m)

end

Program execution:

Steps to execute the MATLAB program:

1. Open the command window and paste the given program.
2. Press enter.
3. Output is displayed in command window.

MATLAB Output after execution of program is displayed as follows.

6

12

20

30

42

56

Conclusion:

Thus, the Output displayed on the screen:

6

12

20

30

42

56

c.

Expert Solution

To determine

What is displayed on the screen after executing the given program.

Answer to Problem 1ICA

The output displayed in the screen is 56.

Explanation of Solution

Given data:

for m=3:8;

M2=m^2-m;

end

fprintf('%0.0f\n',M2)

Program execution:

Steps to execute the MATLAB program:

1. Open the command window and paste the given program.
2. Press enter.
3. Output is displayed in command window.

MATLAB Output after execution of program is displayed as follows.

56

Conclusion:

Thus, the output displayed in the screen is 56.

d.

Expert Solution

To determine

What variables are stored in p and C.

Answer to Problem 1ICA

The variables stored in in p and C are p=945 and C=4.

Explanation of Solution

Given data:

S=3;

I=2;

P=1;

C=0;

for K=S:I:S^I

P=P*K;

C=C+1;

end

Program execution:

Steps to execute the MATLAB program:

1. Open the command window and paste the given program.
2. Press enter.
3. Output is displayed in command window.

Enter P and C in the command window and execute the program.

>> P

P =

945

>> C

C =

4

Conclusion:

Thus, the variables stored in in p and C are p=945 and C=4.

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Answer 3

Textbook Question

Chapter 20, Problem 1ICA

Answer the question with each of the following code segments. If an error will occur, write ERROR and explain what caused the error.

a. What is stored in Count by the following code?

Chapter 20, Problem 1ICA, Answer the question with each of the following code segments. If an error will occur, write ERROR , example 1

b. What is displayed on the screen by the following code?

Chapter 20, Problem 1ICA, Answer the question with each of the following code segments. If an error will occur, write ERROR , example 2

c. What is displayed on the screen by the following code?

Chapter 20, Problem 1ICA, Answer the question with each of the following code segments. If an error will occur, write ERROR , example 3

d. What is stored in P and C after the following code executes?

Chapter 20, Problem 1ICA, Answer the question with each of the following code segments. If an error will occur, write ERROR , example 4

a.

Expert Solution

To determine

What variable is stored in Count.

Answer to Problem 1ICA

The variable stored in Count is 8.

Explanation of Solution

Given data:

Count =0;

for N=10:-0.2:8.5;

Count=Count+1;

end

Program execution:

Steps to execute the MATLAB program:

1. Open the command window and paste the given program.
2. Press enter.
3. Output is displayed in command window.

Enter Count in the command window and execute the program.

>> Count

Count =

8

Conclusion:

Thus, the variable stored in Count is 8.

b.

Expert Solution

To determine

What is displayed on the screen after executing the given program.

Answer to Problem 1ICA

The output displayed on the screen:

6

12

20

30

42

56

Explanation of Solution

Given data:

for m=3:8

fprintf('%0.0f\n',m^2-m)

end

Program execution:

Steps to execute the MATLAB program:

1. Open the command window and paste the given program.
2. Press enter.
3. Output is displayed in command window.

MATLAB Output after execution of program is displayed as follows.

6

12

20

30

42

56

Conclusion:

Thus, the Output displayed on the screen:

6

12

20

30

42

56

c.

Expert Solution

To determine

What is displayed on the screen after executing the given program.

Answer to Problem 1ICA

The output displayed in the screen is 56.

Explanation of Solution

Given data:

for m=3:8;

M2=m^2-m;

end

fprintf('%0.0f\n',M2)

Program execution:

Steps to execute the MATLAB program:

1. Open the command window and paste the given program.
2. Press enter.
3. Output is displayed in command window.

MATLAB Output after execution of program is displayed as follows.

56

Conclusion:

Thus, the output displayed in the screen is 56.

d.

Expert Solution

To determine

What variables are stored in p and C.

Answer to Problem 1ICA

The variables stored in in p and C are p=945 and C=4.

Explanation of Solution

Given data:

S=3;

I=2;

P=1;

C=0;

for K=S:I:S^I

P=P*K;

C=C+1;

end

Program execution:

Steps to execute the MATLAB program:

1. Open the command window and paste the given program.
2. Press enter.
3. Output is displayed in command window.

Enter P and C in the command window and execute the program.

>> P

P =

945

>> C

C =

4

Conclusion:

Thus, the variables stored in in p and C are p=945 and C=4.

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Answer 4

Textbook Question

Chapter 20, Problem 1ICA

Answer the question with each of the following code segments. If an error will occur, write ERROR and explain what caused the error.

a. What is stored in Count by the following code?

Chapter 20, Problem 1ICA, Answer the question with each of the following code segments. If an error will occur, write ERROR , example 1

b. What is displayed on the screen by the following code?

Chapter 20, Problem 1ICA, Answer the question with each of the following code segments. If an error will occur, write ERROR , example 2

c. What is displayed on the screen by the following code?

Chapter 20, Problem 1ICA, Answer the question with each of the following code segments. If an error will occur, write ERROR , example 3

d. What is stored in P and C after the following code executes?

Chapter 20, Problem 1ICA, Answer the question with each of the following code segments. If an error will occur, write ERROR , example 4

a.

Expert Solution

To determine

What variable is stored in Count.

Answer to Problem 1ICA

The variable stored in Count is 8.

Explanation of Solution

Given data:

Count =0;

for N=10:-0.2:8.5;

Count=Count+1;

end

Program execution:

Steps to execute the MATLAB program:

1. Open the command window and paste the given program.
2. Press enter.
3. Output is displayed in command window.

Enter Count in the command window and execute the program.

>> Count

Count =

8

Conclusion:

Thus, the variable stored in Count is 8.

b.

Expert Solution

To determine

What is displayed on the screen after executing the given program.

Answer to Problem 1ICA

The output displayed on the screen:

6

12

20

30

42

56

Explanation of Solution

Given data:

for m=3:8

fprintf('%0.0f\n',m^2-m)

end

Program execution:

Steps to execute the MATLAB program:

1. Open the command window and paste the given program.
2. Press enter.
3. Output is displayed in command window.

MATLAB Output after execution of program is displayed as follows.

6

12

20

30

42

56

Conclusion:

Thus, the Output displayed on the screen:

6

12

20

30

42

56

c.

Expert Solution

To determine

What is displayed on the screen after executing the given program.

Answer to Problem 1ICA

The output displayed in the screen is 56.

Explanation of Solution

Given data:

for m=3:8;

M2=m^2-m;

end

fprintf('%0.0f\n',M2)

Program execution:

Steps to execute the MATLAB program:

1. Open the command window and paste the given program.
2. Press enter.
3. Output is displayed in command window.

MATLAB Output after execution of program is displayed as follows.

56

Conclusion:

Thus, the output displayed in the screen is 56.

d.

Expert Solution

To determine

What variables are stored in p and C.

Answer to Problem 1ICA

The variables stored in in p and C are p=945 and C=4.

Explanation of Solution

Given data:

S=3;

I=2;

P=1;

C=0;

for K=S:I:S^I

P=P*K;

C=C+1;

end

Program execution:

Steps to execute the MATLAB program:

1. Open the command window and paste the given program.
2. Press enter.
3. Output is displayed in command window.

Enter P and C in the command window and execute the program.

>> P

P =

945

>> C

C =

4

Conclusion:

Thus, the variables stored in in p and C are p=945 and C=4.

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Answer 5

Textbook Question

Answer 6

Textbook Question

Answer 7

a.

Expert Solution

To determine

What variable is stored in Count.

Answer to Problem 1ICA

The variable stored in Count is 8.

Explanation of Solution

Given data:

Count =0;

for N=10:-0.2:8.5;

Count=Count+1;

end

Program execution:

Steps to execute the MATLAB program:

1. Open the command window and paste the given program.
2. Press enter.
3. Output is displayed in command window.

Enter Count in the command window and execute the program.

>> Count

Count =

8

Conclusion:

Thus, the variable stored in Count is 8.

b.

Expert Solution

To determine

What is displayed on the screen after executing the given program.

Answer to Problem 1ICA

The output displayed on the screen:

6

12

20

30

42

56

Explanation of Solution

Given data:

for m=3:8

fprintf('%0.0f\n',m^2-m)

end

Program execution:

Steps to execute the MATLAB program:

1. Open the command window and paste the given program.
2. Press enter.
3. Output is displayed in command window.

MATLAB Output after execution of program is displayed as follows.

6

12

20

30

42

56

Conclusion:

Thus, the Output displayed on the screen:

6

12

20

30

42

56

c.

Expert Solution

To determine

What is displayed on the screen after executing the given program.

Answer to Problem 1ICA

The output displayed in the screen is 56.

Explanation of Solution

Given data:

for m=3:8;

M2=m^2-m;

end

fprintf('%0.0f\n',M2)

Program execution:

Steps to execute the MATLAB program:

1. Open the command window and paste the given program.
2. Press enter.
3. Output is displayed in command window.

MATLAB Output after execution of program is displayed as follows.

56

Conclusion:

Thus, the output displayed in the screen is 56.

d.

Expert Solution

To determine

What variables are stored in p and C.

Answer to Problem 1ICA

The variables stored in in p and C are p=945 and C=4.

Explanation of Solution

Given data:

S=3;

I=2;

P=1;

C=0;

for K=S:I:S^I

P=P*K;

C=C+1;

end

Program execution:

Steps to execute the MATLAB program:

1. Open the command window and paste the given program.
2. Press enter.
3. Output is displayed in command window.

Enter P and C in the command window and execute the program.

>> P

P =

945

>> C

C =

4

Conclusion:

Thus, the variables stored in in p and C are p=945 and C=4.

Answer 8

a.

Expert Solution

To determine

What variable is stored in Count.

Answer to Problem 1ICA

The variable stored in Count is 8.

Explanation of Solution

Given data:

Count =0;

for N=10:-0.2:8.5;

Count=Count+1;

end

Program execution:

Steps to execute the MATLAB program:

1. Open the command window and paste the given program.
2. Press enter.
3. Output is displayed in command window.

Enter Count in the command window and execute the program.

>> Count

Count =

8

Conclusion:

Thus, the variable stored in Count is 8.

Answer 9

a.

Expert Solution

Answer 10

a.

Expert Solution

Answer 11

Expert Solution

Answer 12

To determine

What variable is stored in Count.

Answer 13

Answer to Problem 1ICA

The variable stored in Count is 8.

Answer 14

Explanation of Solution

Given data:

Count =0;

for N=10:-0.2:8.5;

Count=Count+1;

end

Program execution:

Steps to execute the MATLAB program:

1. Open the command window and paste the given program.
2. Press enter.
3. Output is displayed in command window.

Enter Count in the command window and execute the program.

>> Count

Count =

8

Conclusion:

Thus, the variable stored in Count is 8.

Answer 15

b.

Expert Solution

To determine

What is displayed on the screen after executing the given program.

Answer to Problem 1ICA

The output displayed on the screen:

6

12

20

30

42

56

Explanation of Solution

Given data:

for m=3:8

fprintf('%0.0f\n',m^2-m)

end

Program execution:

Steps to execute the MATLAB program:

1. Open the command window and paste the given program.
2. Press enter.
3. Output is displayed in command window.

MATLAB Output after execution of program is displayed as follows.

6

12

20

30

42

56

Conclusion:

Thus, the Output displayed on the screen:

6

12

20

30

42

56

Answer 16

b.

Expert Solution

Answer 17

b.

Expert Solution

Answer 18

Expert Solution

Answer 19

To determine

What is displayed on the screen after executing the given program.

Answer 20

Answer to Problem 1ICA

The output displayed on the screen:

6

12

20

30

42

56

Answer 21

Explanation of Solution

Given data:

for m=3:8

fprintf('%0.0f\n',m^2-m)

end

Program execution:

Steps to execute the MATLAB program:

1. Open the command window and paste the given program.
2. Press enter.
3. Output is displayed in command window.

MATLAB Output after execution of program is displayed as follows.

6

12

20

30

42

56

Conclusion:

Thus, the Output displayed on the screen:

6

12

20

30

42

56

Answer 22

c.

Expert Solution

To determine

What is displayed on the screen after executing the given program.

Answer to Problem 1ICA

The output displayed in the screen is 56.

Explanation of Solution

Given data:

for m=3:8;

M2=m^2-m;

end

fprintf('%0.0f\n',M2)

Program execution:

Steps to execute the MATLAB program:

1. Open the command window and paste the given program.
2. Press enter.
3. Output is displayed in command window.

MATLAB Output after execution of program is displayed as follows.

56

Conclusion:

Thus, the output displayed in the screen is 56.

Answer 23

c.

Expert Solution

Answer 24

c.

Expert Solution

Answer 25

Expert Solution

Answer 26

To determine

What is displayed on the screen after executing the given program.

Answer 27

Answer to Problem 1ICA

The output displayed in the screen is 56.

Answer 28

Explanation of Solution

Given data:

for m=3:8;

M2=m^2-m;

end

fprintf('%0.0f\n',M2)

Program execution:

Steps to execute the MATLAB program:

1. Open the command window and paste the given program.
2. Press enter.
3. Output is displayed in command window.

MATLAB Output after execution of program is displayed as follows.

56

Conclusion:

Thus, the output displayed in the screen is 56.

Answer 29

d.

Expert Solution

To determine

What variables are stored in p and C.

Answer to Problem 1ICA

The variables stored in in p and C are p=945 and C=4.

Explanation of Solution

Given data:

S=3;

I=2;

P=1;

C=0;

for K=S:I:S^I

P=P*K;

C=C+1;

end

Program execution:

Steps to execute the MATLAB program:

1. Open the command window and paste the given program.
2. Press enter.
3. Output is displayed in command window.

Enter P and C in the command window and execute the program.

>> P

P =

945

>> C

C =

4

Conclusion:

Thus, the variables stored in in p and C are p=945 and C=4.

Answer 30

d.

Expert Solution

Answer 31

d.

Expert Solution

Answer 32

Expert Solution

Answer 33

To determine

What variables are stored in p and C.

Answer 34

Answer to Problem 1ICA

The variables stored in in p and C are p=945 and C=4.

Answer 35

Explanation of Solution

Given data:

S=3;

I=2;

P=1;

C=0;

for K=S:I:S^I

P=P*K;

C=C+1;

end

Program execution:

Steps to execute the MATLAB program:

1. Open the command window and paste the given program.
2. Press enter.
3. Output is displayed in command window.

Enter P and C in the command window and execute the program.

>> P

P =

945

>> C

C =

4

Conclusion:

Thus, the variables stored in in p and C are p=945 and C=4.

Answer 36

Ch. 20.1 - Write a for loop to display every even number from...Ch. 20.1 - Write a for loop to display every multiple of 5...Ch. 20.1 - Write a for loop to display every odd number from...Ch. 20.1 - Assume a vector Vals has already been defined....Ch. 20.1 - Consider the following table of values. Determine...Ch. 20.1 - Write two nested for loops to determine how many...Ch. 20.1 - Assume a matrix MZ has already been defined. Write...Ch. 20.2 - Write a while loop that requires the user to input...Ch. 20.2 - Assume a vector v2 has already been defined and...Ch. 20 - Answer the question with each of the following...

Solution Summary: The author analyzes the output displayed on the screen after executing the MATLAB program.

Concept explainers

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Answer to Problem 1ICA

Explanation of Solution

Answer to Problem 1ICA

Explanation of Solution

Answer to Problem 1ICA

Explanation of Solution

Answer to Problem 1ICA

Explanation of Solution

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Chapter 20 Solutions