In one region of space the electric potential has a positive constant value. In another region of space the potential has a negative constant value. What can be said about the electric field within each of these two regions of space?
In one region of space the electric potential has a positive constant value. In another region of space the potential has a negative constant value. What can be said about the electric field within each of these two regions of space?
In one region of space the electric potential has a positive constant value. In another region of space the potential has a negative constant value. What can be said about the electric field within each of these two regions of space?
Expert Solution & Answer
To determine
The electric field in each of the two given region of space.
Answer to Problem 1CQ
The electric field in both of the region is zero because the electric potential is constant in both the regions and the gradient of any constant quantity is zero.
Explanation of Solution
Write the expression for the electric field.
E=−ΔVΔs
Here,
E is the electric field at any point.
ΔV is the change in electric potential.
Δs is the change in the distance.
The gradient of a constant quantity is zero. So, when the electric potential in a region is constant then the electric field at that region is zero.
It is given that the electric potential in one region is positive constant value and in another region is negative constant value. So, the gradient of the electric potential is zero in both the region. Thus the electric field is zero in both the region.
Conclusion:
Therefore, the electric field in both of the region is zero because the electric potential is constant in both the regions and the gradient of any constant quantity is zero.
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Four capacitors are connected as shown in the figure below. (Let C = 12.0 μF.)
a
C
3.00 με
Hh.
6.00 με
20.0 με
HE
(a) Find the equivalent capacitance between points a and b.
5.92
HF
(b) Calculate the charge on each capacitor, taking AV ab = 16.0 V.
20.0 uF capacitor 94.7
6.00 uF capacitor 67.6
32.14
3.00 µF capacitor
capacitor C
☑
με
με
The 3 µF and 12.0 uF capacitors are in series and that combination is in parallel with the 6 μF capacitor. What quantity is the same for capacitors in parallel? μC
32.14
☑
You are correct that the charge on this capacitor will be the same as the charge on the 3 μF capacitor. μC
Four capacitors are connected as shown in the figure below. (Let C = 12.0 µF.)
A circuit consists of four capacitors. It begins at point a before the wire splits in two directions. On the upper split, there is a capacitor C followed by a 3.00 µF capacitor. On the lower split, there is a 6.00 µF capacitor. The two splits reconnect and are followed by a 20.0 µF capacitor, which is then followed by point b.
(a) Find the equivalent capacitance between points a and b. µF(b) Calculate the charge on each capacitor, taking ΔVab = 16.0 V.
20.0 µF capacitor
µC
6.00 µF capacitor
µC
3.00 µF capacitor
µC
capacitor C
µC
Campbell Essential Biology with Physiology (5th Edition)
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