Principles of Physics: A Calculus-Based Text, Hybrid (with Enhanced WebAssign Printed Access Card)
Principles of Physics: A Calculus-Based Text, Hybrid (with Enhanced WebAssign Printed Access Card)
5th Edition
ISBN: 9781305586871
Author: Raymond A. Serway, John W. Jewett
Publisher: Cengage Learning
bartleby

Concept explainers

bartleby

Videos

Question
Book Icon
Chapter 20, Problem 18P

(a)

To determine

The location of the particle and the charges on them.

(a)

Expert Solution
Check Mark

Answer to Problem 18P

The location on first particle is 7.00cm at 70.0°_ and the charge on the particle is 7.00nC_.

The location on second particle is 3.00cm at 90.0°_ and the charge on the particle is 8.00nC_.

Explanation of Solution

Write the expression of standard equation for the potential difference.

  V=kqr        (I)

Here, V is the potential difference for distance, k is Coulomb’s constant, q is charge and r is distance.

Write the expression of standard equation for the electric filed.

  E=kqr2        (II)

Here, E is the electric field.

Write the expression for the given potential difference.

Vgiven=(8.99×109N-m2/C2)[(7.00×109C(0.070m))(8.00×109C(0.030m))]        (III)

Here, Vgiven is the given potential difference.

Write the expression for the given electric field.

Egiven=(8.99×109N-m2/C2)[(7.00×109C(0.070m)2cos(70.0°))i^(7.00×109C(0.070m)2sin(70.0°))j^+(8.00×109C(0.030m))j^]        (IV)

Here, Egiven is the given electric field.

Conclusion:

Comparing equation (II) and (IV), the first particle is having charge with magnitude

Q1=7.00×106C=(7.00×106C)(1μC1×106C)=7μC

The location of the first particle is

r1=0.070m=(0.070m)(1cm1×102m)=7cm

Thus, The location on first particle is 7.00cm at 70.0°_ and the charge on the particle is 7.00nC_.

Comparing equation (II) and (IV), the second particle is having charge with magnitude

Q2=8.00×106C=(8.00×106C)(1μC1×106C)=8μC

The location of the second particle is

r2=0.030m=(0.030m)(1cm1×102m)=3cm

Thus, the location on second particle is 3.00cm at 90.0°_ and the charge on the particle is 8.00nC_.

(b)

To determine

The force acting on charge -16.0 nC.

(b)

Expert Solution
Check Mark

Answer to Problem 18P

The force acting on charge -16.0 nC is (7.03i^109j^)×105N_.

Explanation of Solution

Rewrite the expression for the given electric field from equation (IV).

Egiven=(4.39×103N/C)i^+(67.8×103N/C)j^        (V)

Write the expression for the force action on the charge.

F=qEgiven        (VI)

Here, F is the force, q is charge.

Conclusion:

Substitute (4.39×103N/C)i^+(67.8×103N/C)j^ for Egiven, (16nC) for q in Equation (VI) to find F.

F=[(16nC)(1×109C1nC)][(4.39×103N/C)i^+(67.8×103N/C)j^]=(16×109C)[(4.39×103N/C)i^+(67.8×103N/C)j^]=(7.03i^109j^)×105N

Thus, the force acting on charge -16.0 nC is (7.03i^109j^)×105N_.

(c)

To determine

The work done required to move the charge.

(c)

Expert Solution
Check Mark

Answer to Problem 18P

The work done required to move the charge is 2.40×105J_.

Explanation of Solution

Rewrite the expression for the given potential difference by using equation (III).

Vgiven=(8.99×109N-m2/C2)[(7.00×109C(0.070m))(8.00×109C(0.030m))]=1.50×103V        (VII)

Write the expression for the required work done.

W=qV        (VIII)

Here, W is the work done and q is the charge.

Conclusion:

Substitute (1.50×103)V for Vgiven, (16nC) for q in Equation (VIII) to find W.

  W=[(16nC)(1×109C1nC)](1.50×103)V=2.40×105J

Thus, the work done required to move the charge is 2.40×105J_.

Want to see more full solutions like this?

Subscribe now to access step-by-step solutions to millions of textbook problems written by subject matter experts!
Students have asked these similar questions
No chatgpt pls will upvote
No chatgpt pls will upvote
air is pushed steadily though a forced air pipe at a steady speed of 4.0 m/s. the pipe measures 56 cm by 22 cm. how fast will air move though a narrower portion of the pipe that is also rectangular and measures 32 cm by 22 cm

Chapter 20 Solutions

Principles of Physics: A Calculus-Based Text, Hybrid (with Enhanced WebAssign Printed Access Card)

Ch. 20 - Prob. 2OQCh. 20 - A proton is released from rest at the origin in a...Ch. 20 - By what factor is the capacitance of a metal...Ch. 20 - Prob. 5OQCh. 20 - Rank the potential energies of the four systems of...Ch. 20 - Prob. 7OQCh. 20 - In a certain region of space, a uniform electric...Ch. 20 - Prob. 9OQCh. 20 - Prob. 10OQCh. 20 - Prob. 11OQCh. 20 - A parallel-plate capacitor is connected to a...Ch. 20 - Rank the electric potential energies of the...Ch. 20 - Four particles are positioned on the rim of a...Ch. 20 - Prob. 15OQCh. 20 - A filament running along the x axis from the...Ch. 20 - An electronics technician wishes to construct a...Ch. 20 - Prob. 18OQCh. 20 - Prob. 19OQCh. 20 - A parallel-plate capacitor filled with air carries...Ch. 20 - Prob. 21OQCh. 20 - Prob. 1CQCh. 20 - Prob. 2CQCh. 20 - Prob. 3CQCh. 20 - Prob. 4CQCh. 20 - Prob. 5CQCh. 20 - Prob. 6CQCh. 20 - Prob. 7CQCh. 20 - Prob. 8CQCh. 20 - Why is it dangerous to touch the terminals of a...Ch. 20 - Prob. 10CQCh. 20 - Prob. 11CQCh. 20 - Prob. 12CQCh. 20 - A uniform electric field of magnitude 325 V/m is...Ch. 20 - Prob. 2PCh. 20 - Calculate the speed of a proton that is...Ch. 20 - Prob. 4PCh. 20 - An electron moving parallel to the x axis has an...Ch. 20 - (a) Find the potential at a distance of 1.00 cm...Ch. 20 - Prob. 8PCh. 20 - Given two particles with 2.00-C charges as shown...Ch. 20 - Three particles with equal positive charges q are...Ch. 20 - The three charged particles in Figure P20.11 are...Ch. 20 - Prob. 12PCh. 20 - Prob. 13PCh. 20 - Review. A light, unstressed spring has length d....Ch. 20 - Review. Two insulating spheres have radii 0.300 cm...Ch. 20 - Review. Two insulating spheres have radii r1 and...Ch. 20 - Two particles each with charge +2.00 C are located...Ch. 20 - Prob. 18PCh. 20 - Two particles, with charges of 20.0 nC and 20.0...Ch. 20 - At a certain distance from a charged particle, the...Ch. 20 - A particle with charge +q is at the origin. A...Ch. 20 - Prob. 22PCh. 20 - Prob. 23PCh. 20 - Prob. 24PCh. 20 - Prob. 25PCh. 20 - A rod of length L (Fig. P20.26) lies along the x...Ch. 20 - For the arrangement described in Problem 26,...Ch. 20 - A wire having a uniform linear charge density is...Ch. 20 - A uniformly charged insulating rod of length 14.0...Ch. 20 - How many electrons should be removed from an...Ch. 20 - Prob. 31PCh. 20 - Prob. 32PCh. 20 - (a) How much charge is on each plate of a 4.00-F...Ch. 20 - Two conductors having net charges of +10.0 C and...Ch. 20 - Prob. 35PCh. 20 - A spherical capacitor consists of a spherical...Ch. 20 - Prob. 37PCh. 20 - A variable air capacitor used in a radio tuning...Ch. 20 - Prob. 39PCh. 20 - Prob. 40PCh. 20 - (a) Regarding the Earth and a cloud layer 800 m...Ch. 20 - Prob. 42PCh. 20 - Prob. 43PCh. 20 - (a) Find the equivalent capacitance between points...Ch. 20 - Four capacitors are connected as shown in Figure...Ch. 20 - Prob. 46PCh. 20 - According to its design specification, the timer...Ch. 20 - Prob. 48PCh. 20 - Prob. 49PCh. 20 - Three capacitors are connected to a battery as...Ch. 20 - Find the equivalent capacitance between points a...Ch. 20 - Consider the circuit shown in Figure P20.52, where...Ch. 20 - Prob. 53PCh. 20 - A parallel-plate capacitor has a charge Q and...Ch. 20 - Prob. 55PCh. 20 - Prob. 56PCh. 20 - Prob. 57PCh. 20 - Prob. 58PCh. 20 - Prob. 59PCh. 20 - Prob. 60PCh. 20 - A uniform electric field E = 3 000 V/m exists...Ch. 20 - Prob. 62PCh. 20 - Prob. 63PCh. 20 - Prob. 64PCh. 20 - Prob. 65PCh. 20 - A parallel-plate capacitor in air has a plate...Ch. 20 - Lightning can be studied with a Van de Graaff...Ch. 20 - Prob. 68PCh. 20 - Prob. 69PCh. 20 - Prob. 70PCh. 20 - Prob. 71PCh. 20 - Prob. 72PCh. 20 - Prob. 73PCh. 20 - Prob. 74PCh. 20 - Prob. 75PCh. 20 - Prob. 76PCh. 20 - Prob. 77PCh. 20 - Prob. 78PCh. 20 - Prob. 79PCh. 20 - Prob. 80PCh. 20 - Prob. 81PCh. 20 - Prob. 82PCh. 20 - A 10.0-F capacitor is charged to 15.0 V. It is...Ch. 20 - Two large, parallel metal plates, each of area A,...Ch. 20 - A capacitor is constructed from two square,...Ch. 20 - Two square plates of sides are placed parallel to...Ch. 20 - Determine the equivalent capacitance of the...
Knowledge Booster
Background pattern image
Physics
Learn more about
Need a deep-dive on the concept behind this application? Look no further. Learn more about this topic, physics and related others by exploring similar questions and additional content below.
Similar questions
SEE MORE QUESTIONS
Recommended textbooks for you
Text book image
Principles of Physics: A Calculus-Based Text
Physics
ISBN:9781133104261
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
Text book image
Physics for Scientists and Engineers, Technology ...
Physics
ISBN:9781305116399
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
Text book image
Physics for Scientists and Engineers: Foundations...
Physics
ISBN:9781133939146
Author:Katz, Debora M.
Publisher:Cengage Learning
Text book image
Physics for Scientists and Engineers with Modern ...
Physics
ISBN:9781337553292
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
Text book image
Physics for Scientists and Engineers
Physics
ISBN:9781337553278
Author:Raymond A. Serway, John W. Jewett
Publisher:Cengage Learning
Text book image
College Physics
Physics
ISBN:9781938168000
Author:Paul Peter Urone, Roger Hinrichs
Publisher:OpenStax College
Electric Fields: Crash Course Physics #26; Author: CrashCourse;https://www.youtube.com/watch?v=mdulzEfQXDE;License: Standard YouTube License, CC-BY