Explanation Procedure used: “To find the amplitude and period of a function in the form y = A sin B x or y = A cos B x where A represents the amplitude and B represents the coefficient of x. 2. Divide 360 ° or 2 π radians by the coefficient of x which is B. P = 360 ° B for degrees or P = 2 π B for radians . ” “To find the phase shift for the function y = A sin ( B x + C ) or y = A cos ( B x + C ) 1. Find the value C B . 2. If C B is positive, shift the graph C B units to the left . 3. If C B is negative, shift the graph C B units to the right .” Calculation: The given function is y = 3 sin ( 2 x − 240 ° ) . Compare the given function with y = A sin B x and obtain the value of A and B as shown below: Note that on comparing, A = 3 and B = 2 . Thus, the amplitude of the given function is 3

College Mathematics for Trades and Technologies (10th Edition) (What's New in Trade Math)

10th Edition

ISBN: 9780134690339

Author: Cheryl Cleaves, Margie Hobbs

Publisher: PEARSON

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Chapter 20, Problem 17CPT

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The amplitude, period and phase shift for the function y=3sin(2x−240°).

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Chapter 20, Problem 16CPT

Chapter 20, Problem 18CPT

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y"-9y+20y= 80t-156 y(0) = −6, y'(0) = 5 y(t) =

Chapter 20 Solutions

College Mathematics for Trades and Technologies (10th Edition) (What's New in Trade Math)

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The amplitude, period and phase shift for the function y = 3 sin ( 2 x − 240 ° ) .

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The amplitude, period and phase shift for the function y=3sin(2x−240°).

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Chapter 20 Solutions