Chapter 20, Problem 144CP

Interpretation Introduction

(a)

Interpretation:

The systematic names of the given unsaturated hydrocarbon should be determined.

Concept Introduction:

The hydrocarbon compounds that is compound containing only hydrogen and carbon atoms that contains multiple bond(s) are said to be unsaturated hydrocarbon. Compounds containing double bonds are said to be alkene whereas compounds containing triple bonds are said to be alkyne.

In order to give the name to the unsaturated hydrocarbon following steps are followed:

1. The parent (longest) continuous carbon chain containing multiple bonds between the carbon atoms is selected.

2. While writing the name of alkene, the suffix “ane” of the corresponding alkane is replaced by “ene”.

3. Name should be written in alphabetical order and numbering should be done in such a way that the multiple bond and substituent group gets lowest number.

4. Hyphen is used to connect the number to the name.

For number of carbons atoms in alkane chain, the prefix is given as:

Carbon-1meth

Carbon-2eth

Carbon-3prop

Carbon-4but

Carbon-5pent

Carbon-6hex

Carbon-7hept

Carbon-8oct

Carbon-9non

Carbon-10dec.

Answer to Problem 144CP

2-methylbut-1-ene.

Explanation of Solution

The given structure is:

The parent chain in the given structure is of 4-carbon atoms so, prefix will be but. Numbering is done in such a way that the multiple bond that is double bond gets lower number that is 1 for double bond and the substituent on 2 position is methyl.

So, the IUPAC name will be: 2-methylbut-1-ene.

Interpretation Introduction

(b)

Interpretation:

The systematic names of the given unsaturated hydrocarbon should be determined.

Concept Introduction:

The hydrocarbon compounds that is compound containing only hydrogen and carbon atoms that contains multiple bond(s) are said to be unsaturated hydrocarbon. Compounds containing double bonds are said to be alkene whereas compounds containing triple bonds are said to be alkyne.

In order to give the name to the unsaturated hydrocarbon following steps are followed:

1. The parent (longest) continuous carbon chain containing multiple bonds between the carbon atoms is selected.

2. While writing the name of alkene, the suffix “ane” of the corresponding alkane is replaced by “ene”.

3. Name should be written in alphabetical order and numbering should be done in such a way that the multiple bond and substituent group gets lowest number.

4. Hyphen is used to connect the number to the name.

For number of carbons atoms in alkane chain, the prefix is given as:

Carbon-1meth

Carbon-2eth

Carbon-3prop

Carbon-4but

Carbon-5pent

Carbon-6hex

Carbon-7hept

Carbon-8oct

Carbon-9non

Carbon-10dec.

Answer to Problem 144CP

2, 4-dimethylpent-1, 4-diene.

Explanation of Solution

The given structure is:

The parent chain in the given structure is of 5-carbon atoms so, prefix will be pent. Numbering is done in such a way that the multiple bond that is double bond gets lower number that is 1 and 4 for double bond and the substituent on 2 and 4 position is methyl.

So, the IUPAC name will be: 2, 4-dimethylpent-1, 4-diene.

Interpretation Introduction

(c)

Interpretation:

The systematic names of the given unsaturated hydrocarbon should be determined.

Concept Introduction:

The hydrocarbon compounds that is compound containing only hydrogen and carbon atoms that contains multiple bond(s) are said to be unsaturated hydrocarbon. Compounds containing double bonds are said to be alkene whereas compounds containing triple bonds are said to be alkyne.

In order to give the name to the unsaturated hydrocarbon following steps are followed:

1. The parent (longest) continuous carbon chain containing multiple bonds between the carbon atoms is selected.

2. While writing the name of alkene, the suffix “ane” of the corresponding alkane is replaced by “ene”.

3. Name should be written in alphabetical order and numbering should be done in such a way that the multiple bond and substituent group gets lowest number.

4. Hyphen is used to connect the number to the name.

For number of carbons atoms in alkane chain, the prefix is given as:

Carbon-1meth

Carbon-2eth

Carbon-3prop

Carbon-4but

Carbon-5pent

Carbon-6hex

Carbon-7hept

Carbon-8oct

Carbon-9non

Carbon-10dec.

Answer to Problem 144CP

6-ethyl-2-methyloct-4-ene.

Explanation of Solution

The given structure is:

The parent chain in the given structure is of 5-carbon atoms so, prefix will be oct. Numbering is done in such a way that the multiple bond that is double bond gets lower number that is 4 for double bond and the substituent on 2 position is methyl and on 6 position is ethyl.

So, the IUPAC name will be: 6-ethyl-2-methyloct-4-ene.

Interpretation Introduction

(d)

Interpretation:

The systematic names of the given unsaturated hydrocarbon should be determined.

Concept Introduction:

The hydrocarbon compounds that is compound containing only hydrogen and carbon atoms that contains multiple bond(s) are said to be unsaturated hydrocarbon. Compounds containing double bonds are said to be alkene whereas compounds containing triple bonds are said to be alkyne.

In order to give the name to the unsaturated hydrocarbon following steps are followed:

1. The parent (longest) continuous carbon chain containing multiple bonds between the carbon atoms is selected.

2. While writing the name of alkyne, the suffix “ane” of the corresponding alkane is replaced by “yne”.

3. Name should be written in alphabetical order and numbering should be done in such a way that the multiple bond and substituent group gets lowest number.

4. Hyphen is used to connect the number to the name.

For number of carbons atoms in alkane chain, the prefix is given as:

Carbon-1meth

Carbon-2eth

Carbon-3prop

Carbon-4but

Carbon-5pent

Carbon-6hex

Carbon-7hept

Carbon-8oct

Carbon-9non

Carbon-10dec.

Answer to Problem 144CP

3-bromohept-1-yne.

Explanation of Solution

The given structure is:

The parent chain in the given structure is of 7-carbon atoms so, prefix will be hept. Numbering is done in such a way that the multiple bond that is triple bond gets lower number that is 1 for triple bond. The substituent on 3 position is bromo.

So, the IUPAC name will be: 3-bromohept-1-yne.

Interpretation Introduction

(e)

Interpretation:

The systematic names of the given unsaturated hydrocarbon should be determined.

Concept Introduction:

The hydrocarbon compounds that is compound containing only hydrogen and carbon atoms that contains multiple bond(s) are said to be unsaturated hydrocarbon. Compounds containing double bonds are said to be alkene whereas compounds containing triple bonds are said to be alkyne.

In order to give the name to the unsaturated hydrocarbon following steps are followed:

1. The parent (longest) continuous carbon chain containing multiple bonds between the carbon atoms is selected.

2. While writing the name of alkyne, the suffix “ane” of the corresponding alkane is replaced by “yne”.

3. Name should be written in alphabetical order and numbering should be done in such a way that the multiple bond and substituent group gets lowest number.

4. Hyphen is used to connect the number to the name.

For number of carbons atoms in alkane chain, the prefix is given as:

Carbon-1meth

Carbon-2eth

Carbon-3prop

Carbon-4but

Carbon-5pent

Carbon-6hex

Carbon-7hept

Carbon-8oct

Carbon-9non

Carbon-10dec.

Answer to Problem 144CP

7-chloro-2, 5, 5-trimethylhept-3-yne.

Explanation of Solution

The given structure is:

The parent chain in the given structure is of 7-carbon atoms so, prefix will be hept. Numbering is done in such a way that the multiple bond that is triple bond gets lower number that is 3 for triple bond. The substituent on 2 and 5 position is methyl and on 7 position is chloro.

So, the IUPAC name will be: 7-chloro-2, 5, 5-trimethylhept-3-yne.

Interpretation Introduction

(f)

Interpretation:

The systematic names of the given unsaturated hydrocarbon should be determined.

Concept Introduction:

The hydrocarbon compounds that is compound containing only hydrogen and carbon atoms that contains multiple bond(s) are said to be unsaturated hydrocarbon. Compounds containing double bonds are said to be alkene whereas compounds containing triple bonds are said to be alkyne.

In order to give the name to the unsaturated hydrocarbon following steps are followed:

1. The parent (longest) continuous carbon chain containing multiple bonds between the carbon atoms is selected.

2. While writing the name of alkyne, the suffix “ane” of the corresponding alkane is replaced by “yne”.

3. Name should be written in alphabetical order and numbering should be done in such a way that the multiple bond and substituent group gets lowest number.

4. Hyphen is used to connect the number to the name.

For number of carbons atoms in alkane chain, the prefix is given as:

Carbon-1meth

Carbon-2eth

Carbon-3prop

Carbon-4but

Carbon-5pent

Carbon-6hex

Carbon-7hept

Carbon-8oct

Carbon-9non

Carbon-10dec.

Answer to Problem 144CP

4-ethyl-3-methyloct-1-yne.

Explanation of Solution

The given structure is:

The parent chain in the given structure is of 8-carbon atoms so, prefix will be oct. Numbering is done in such a way that the multiple bond that is triple bond gets lower number that is 1 for triple bond. The substituent on 3 position is methyl and on 4 position is ethyl.

So, the IUPAC name will be: 4-ethyl-3-methyloct-1-yne.