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Chapter 20, Problem 10PQ

(a)

To determine

The average speed of the 12 atoms in the cylinder.

(a)

Expert Solution
Check Mark

Answer to Problem 10PQ

The average speed of the 12 atoms in the cylinder is 4.30km/s_.

Explanation of Solution

Write the expression for average speed.

vavg=iNviN

Here, vi is the velocity and N is the number of observations.

Conclusion:

Substitute 1.50km/s for v1, 5.00km/s for v2, 8.00km/s for v3, 1.25km/s for v4, 2.95km/s for v5, 4.40km/s for v6, 5.60km/s for v7, 3.50km/s for v8, 7.80km/s for v9, 2.70km/s for v10, 2.90km/s for v11, 6.00km/s for v12 and 12 for N in the above equation.

    vavg=112(1.50km/s+5.00km/s+8.00km/s+1.25km/s+2.95km/s+4.40km/s+5.60km/s+3.50km/s+7.80km/s+2.70km/s+2.90km/s+6.00km/s)=4.30km/s

Therefore, the average speed of the 12 atoms in the cylinder is 4.30km/s_.

(b)

To determine

The rms speed of the 12 atoms in the cylinder.

(b)

Expert Solution
Check Mark

Answer to Problem 10PQ

The rms speed of the 12 atoms in the cylinder is 4.80km/s_.

Explanation of Solution

Write the expression for rms speed.

vrms=iNvi2N

Here, vi is the velocity and N is the number of observations.

Conclusion:

Substitute 1.50km/s for v1, 5.00km/s for v2, 8.00km/s for v3, 1.25km/s for v4, 2.95km/s for v5, 4.40km/s for v6, 5.60km/s for v7, 3.50km/s for v8, 7.80km/s for v9, 2.70km/s for v10, 2.90km/s for v11, 6.00km/s for v12 and 12 for N in the above equation.

    vrms=112((1.50km/s)2+(5.00km/s)2+(8.00km/s)2+(1.25km/s)2+(2.95km/s)2+(4.40km/s)2+(5.60km/s)2+(3.50km/s)2+(7.80km/s)2+(2.70km/s)2+(2.90km/s)2+(6.00km/s)2)=4.80km/s

Therefore, the rms speed of the 12 atoms in the cylinder is 4.80km/s_.

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Chapter 20 Solutions

Webassign Printed Access Card For Katz's Physics For Scientists And Engineers: Foundations And Connections, 1st Edition, Single-term

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