Pearson eText for Essentials of Systems Analysis and Design -- Instant Access (Pearson+)
Pearson eText for Essentials of Systems Analysis and Design -- Instant Access (Pearson+)
6th Edition
ISBN: 9780137612420
Author: Joseph Valacich, Joey George
Publisher: PEARSON+
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Chapter 2, Problem 8RQ
Program Plan Intro

Cloud Computing:

  • Cloud computing is a type of computing that relies on computer resources sharing rather than the application running local computing devices like servers, computers, tablet, smart phones and many others.
  • It includes three types of service categories
    • Infrastructure as a service (IaaS)
    • Software as a service (SaaS)
    • Platform as a service (PaaS)

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7. Long-Distance CallsA long-distance provider charges the following rates for telephone calls: Rate Category    Rate per MinuteDaytime (6:00 a.m. through 5:59 p.m.)    $0.07Evening (6:00 p.m. through 11:59 p.m.)    $0.12Off-Peak (midnight through 5:59 a.m.)    $0.05Write a GUI application that allows the user to select a rate category (from a set of radio buttons), and enter the number of minutes of the call into an Entry widget. An info dialog box should display the charge for the call.
Name and Address The Name and Address Problem Write a GUI program that displays your name and address when a button is clicked. The program’s window should appear as the sketch on the left side of Figure 13-61 when it runs. When the user clicks the Show Info button, the program should display your name and address, as shown in the sketch on the right of the figure.
Exercise 1 Function and Structure [30 pts] Please debug the following program and answer the following questions. There is a cycle in a linked list if some node in the list can be reached again by continuously following the next pointer. #include typedef struct node { int value; struct node *next; } node; int 11_has_cycle (node *first) if (first == node *head = { NULL) return 0; first; while (head->next != NULL) { } if (head first) { return 1; } head = head->next; return 0; void test ll_has_cycle () { int i; node nodes [6]; for (i = 0; i < 6; i++) { nodes [i] .next = NULL; nodes [i].value = i; } nodes [0] .next = &nodes [1]; nodes [1] .next = &nodes [2]; nodes [2] .next = &nodes [3]; nodes [3] .next nodes [4] .next &nodes [4]; NULL; nodes [5] .next = &nodes [0]; printf("1. Checking first list for cycles. \n Function 11_has_cycle says it has s cycle\n\n", 11_has_cycle (&nodes [0])?"a":"no"); printf("2. Checking length-zero list for cycles. \n Function 11_has_cycle says it has %s…
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