Chapter 2, Problem 8CP

a. num1 = 35;

Explanation of Solution

num1 = 35; is a valid assignment as integer 35 is be...

b. newNum = num1 – num2;

Explanation of Solution

newNum = num1 – num2; is a valid assignment although the variables num1 and num2 have not been initialized. If a variable is used in an expression, the expression would yield a meaningf...

c. num1 = 5; num2 = 2 + num1; num1 = num2 / 3;

Explanation of Solution

num1 = 5; num2 = 2 + num1; num1 = num2 / 3; are valid assignments. num1 =5; declares and initializes the variable num1. num2 = 2 + num1; assigns the value of the expression 2 + num1 to num2. Since num1 has been declared and assigned a value, the right-hand expression value is 2 + 5 = 7...

d. num1 * num2 = newNum;

Explanation of Solution

num1 * num2 = newNum; is not a valid assignment as the left hand of a valid assignment is a variable and not an expression...

e. x = 12 * num1 - 15.3;

Explanation of Solution

x = 12 * num1 - 15.3; is a valid assignment although the variable num1 in the expression on the right-hand side has been declared but not initialized before being used in the expression. If a variable is used in an expression, the expression would yield a meaningful value only if the variable has first been initialized...

f. num1 * 2 = newNum + num2;

Explanation of Solution

num1 * 2 = newNum + num2; is not a valid assignment as the left hand of a valid assignment is a variable and not an expression...

g. x / y = x * y;

Explanation of Solution

x / y = x * y; is not a valid assignment as the left hand of a valid assignment is a variable and not an expression...

h. num2 = num1 % 2.0;

Explanation of Solution

num2 = num1 % 2.0; is not a valid assignment as the expression on the right-hand side would not evaluate. The expression on the right-hand si...

i. newNum = static_cast<int> (x) % 5;

Explanation of Solution

newNum = static_cast<int> (x) % 5; is a valid assignment. The double variable is explicitly cast to an int type before it participates as an oper...

j. x = x + y - 5;

Explanation of Solution

x = x + y - 5; is a valid assignment although the variables x and y have not been initialized before being used in the expression. The expression on the right side...

k. newNum = num1 + static_cast<int> (4.6 / 2);

Explanation of Solution

newNum = num1 + static_cast<int> (4.6 / 2); is a valid assignment. The expression on the right-hand side evaluates an unpredictable but int type value. The expression inside the parentheses is evaluated first where the denominator is implicitly casted to floating-point type (as the numerator is floating-point type)...