(a) Explanation Write the expression from kinematics equation of motion. v 2 = v 0 2 + 2 a x (I) Here, v is the peak speed of the elevator moves upward, v 0 is the initial speed of the elevator, a is the acceleration of the accelerator, and x is the distance of the elevator reaches at the midpoint. Rewrite the equation (I) for upward acceleration of the elevator. v 2 − v 0 2 = 2 a up x a up = v 2 − v 0 2 2 x (II) Here, a up is the upward acceleration of the elevator runs. Rewrite the equation (I) for downward acceleration of the elevator. a down = v ′ 2 − v 0 2 2 x (III) Here, a down is the downward acceleration of the elevator runs and v ′ is the peak speed of the elevator moves downward. Conclusion: The height of the each floor of the 101 Taipei Tower building is, h ′ = 509 m 101 = 5.04 m The height of the 89 floor of Tower building is, h 89 = 89 h ′ = 89 ( 5.04 m ) = 448.6 m The height of the midpoint of the elevator runs is, h = 448.6 m 2 = 224.3 m Substitute 1008 m/min for v , 0 m/s for v 0 , and 224.3 m for x in equation (II) to find a up (b) To determine The time period of escalator trip runs up and down.

7th Edition

ISBN: 9780321601834

Author: Jerry D. Wilson, Anthony J. Buffa, Bo Lou

Publisher: Addison-Wesley

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Question

Chapter 2, Problem 80E

(a)

To determine

The acceleration of the elevator runs up and down.

(b)

To determine

The time period of escalator trip runs up and down.

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Chapter 2, Problem 79E

Chapter 2, Problem 81E

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