
Concept explainers
(a)
Interpretation:
For the given atoms, the number of electrons, protons and neutrons has to be determined.
Concept introduction:
The
The number of protons and number of electrons for an atom is equal.
(b)
Interpretation:
For the given atoms, the number of electrons, protons and neutrons has to be determined.
Concept introduction:
The atomic number of Tin atom is 50, thereby has 50 protons; if the mass number of tin is 119 then the number of neutron is 69.
The number of protons and number of electrons for an atom is equal.
(c)
Interpretation:
For the given atoms, the number of electrons, protons and neutrons has to be determined.
Concept introduction:
The atomic number of Thorium atom is 90, thereby it has 90 protons; if the mass number of thorium is 232 then the number of neutron is 142.
The number of protons and number of electrons for an atom is equal.
(d)
Interpretation:
For the given atoms, the number of electrons, protons and neutrons has to be determined.
Concept introduction:
The atomic number of Carbon atom is 6, thereby it has 6 protons; if the mass number of carbon is 13 then the number of neutron is 7.
The number of protons and number of electrons for an atom is equal.
(e)
Interpretation:
For the given atoms, the number of electrons, protons and neutrons has to be determined.
Concept introduction:
The atomic number of Copper atom is 29, thereby it has 29 protons; if the mass number of copper is 63 then the number of neutron is 34.
The number of protons and number of electrons for an atom is equal.
(f)
Interpretation:
For the given atoms, the number of electrons, protons and neutrons has to be determined.
Concept introduction:
The atomic number of Magnesium atom is 12, thereby it has 12 protons; if the mass number of magnesium is 24 then the number of neutron is 12.
The atomic number of Tin atom is 50, thereby has 50 protons; if the mass number of tin is 119 then the number of neutron is 69.
The atomic number of Thorium atom is 90, thereby it has 90 protons; if the mass number of thorium is 232 then the number of neutron is 142.
The atomic number of Carbon atom is 6, thereby it has 6 protons; if the mass number of carbon is 13 then the number of neutron is 7.
The atomic number of Copper atom is 29, thereby it has 29 protons; if the mass number of copper is 63 then the number of neutron is 34.
The atomic number of Bismuth atom is 83, thereby it has 83 protons; if the mass number of bismuth is 205 then the number of neutron is 122.
The number of protons and number of electrons for an atom is equal.

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Chapter 2 Solutions
Owlv2 With Ebook, 1 Term (6 Months) Printed Access Card For Kotz/treichel/townsend/treichel's Chemistry & Chemical Reactivity, 10th
- 4. For the following complexes, draw the structures and give a d-electron count of the metal: a) Tris(acetylacetonato)iron(III) b) Hexabromoplatinate(2-) c) Potassium diamminetetrabromocobaltate(III) (6 points)arrow_forward2. Calculate the overall formation constant for [Fe(CN)6]³, given that the overall formation constant for [Fe(CN)6] 4 is ~1032, and that: Fe3+ (aq) + e = Fe²+ (aq) E° = +0.77 V [Fe(CN)6]³ (aq) + e¯ = [Fe(CN)6] (aq) E° = +0.36 V (4 points)arrow_forward5. Consider the compounds shown below as ligands in coordination chemistry and identify their denticity; comment on their ability to form chelate complexes. (6 points) N N A B N N N IN N Carrow_forward
- 1. Use standard reduction potentials to rationalize quantitatively why: (6 points) (a) Al liberates H2 from dilute HCl, but Ag does not; (b) Cl2 liberates Br2 from aqueous KBr solution, but does not liberate C12 from aqueous KCl solution; c) a method of growing Ag crystals is to immerse a zinc foil in an aqueous solution of AgNO3.arrow_forwardWhat would be the best choices for the missing reagents 1 and 3 in this synthesis? 1 1. PPh3 2. n-BuLi 3 2 • Draw the missing reagents in the drawing area below. You can draw them in any arrangement you like. • Do not draw the missing reagent 2. If you draw 1 correctly, we'll know what it is. • Note: if one of your reagents needs to contain a halogen, use bromine. Click and drag to start drawing a structure. Xarrow_forwardWhat is the missing reactant R in this organic reaction? N N H3O+ +R + • Draw the structure of R in the drawing area below. • Be sure to use wedge and dash bonds if it's necessary to draw one particular enantiomer. Click and drag to start drawing a structure. fmarrow_forward
- The product on the right-hand side of this reaction can be prepared from two organic reactants, under the conditions shown above and below the arrow. Draw 1 and 2 below, in any arrangement you like. 1+2 NaBH3CN H+ N Click and drag to start drawing a structure. 5arrow_forwardAssign this HSQC Spectrum ( please editing clearly on the image)arrow_forward(a 4 shows scanning electron microscope (SEM) images of extruded actions of packing bed for two capillary columns of different diameters, al 750 (bottom image) and b) 30-μm-i.d. Both columns are packed with the same stationary phase, spherical particles with 1-um diameter. A) When the columns were prepared, the figure shows that the column with the larger diameter has more packing irregularities. Explain this observation. B) Predict what affect this should have on band broadening and discuss your prediction using the van Deemter terms. C) Does this figure support your explanations in application question 33? Explain why or why not and make any changes in your answers in light of this figure. Figure 4 SEM images of sections of packed columns for a) 750 and b) 30-um-i.d. capillary columns.³arrow_forward
- fcrip = ↓ bandwidth Il temp 32. What impact (increase, decrease, or no change) does each of the following conditions have on the individual components of the van Deemter equation and consequently, band broadening? Increase temperature Longer column Using a gas mobile phase instead of liquid Smaller particle stationary phase Multiple Paths Diffusion Mass Transferarrow_forward34. Figure 3 shows Van Deemter plots for a solute molecule using different column inner diameters (i.d.). A) Predict whether decreasing the column inner diameters increase or decrease bandwidth. B) Predict which van Deemter equation coefficient (A, B, or C) has the greatest effect on increasing or decreasing bandwidth as a function of i.d. and justify your answer. Figure 3 Van Deemter plots for hydroquinone using different column inner diameters (i.d. in μm). The data was obtained from liquid chromatography experiments using fused-silica capillary columns packed with 1.0-μm particles. 35 20 H(um) 큰 20 15 90 0+ 1500 100 75 550 01 02 594 05 μ(cm/sec) 30 15 10arrow_forwardelow are experimentally determined van Deemter plots of column efficiency, H, vs. flow rate. H is a quantitative measurement of band broadening. The left plot is for a liquid chromatography application and the night is for gas chromatography. Compare and contrast these two plots in terms of the three band broadening mechanisms presented in this activity. How are they similar? How do they differ? Justify your answers.? 0.4 H (mm) 0.2 0.1- 0.3- 0 0.5 H (mm) 8.0 7.0 6.0 5.0 4.0- 3.0 T +++ 1.0 1.5 0 2.0 4.0 Flow Rate, u (cm/s) 6.0 8.0 Flow Rate, u (cm/s)arrow_forward
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