MATERIALS SCI + ENGR: INT W/ACCESS
10th Edition
ISBN: 9781119808084
Author: Callister
Publisher: WILEY
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Chapter 2, Problem 6QAP
To determine
(A). The two important Quantum-
(B). The two important additional retirements that resulted from the wave mechanical atomic model.
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Problem (11): A pipe discharges an unknown fluid into the
atmosphere from a tank of depth (h) through a pipe of length
(L), and diameter (d).
Given the values of L [m], d [cm], and (h) [cm], calculate the
discharge rate (Q) [lit/s] that would maintain Laminar flow in
the pipe with a Reynolds number of Re-1500. Ignore minor
losses.
Givens:
L =
139.364 m
d = 12.614 cm
h = 76.609 cm
Answers:
( 1 ) 6.911 lit/s
(2) 8.179 lit/s
( 3 ) 4.244 lit/s
(4) 4.987 lit/s
h
d
Problem (17): water flowing in an open channel of a rectangular cross-section with width (b) transitions from a
mild slope to a steep slope (i.e., from subcritical to supercritical flow) with normal water depths of (y₁) and
(y2), respectively.
Given the values of y₁ [m], y₂ [m], and b [m], calculate the discharge in the channel (Q) in [Lit/s].
Givens:
y1 = 4.112 m
y2 =
0.387 m
b = 0.942 m
Answers:
( 1 ) 1880.186 lit/s
( 2 ) 4042.945 lit/s
( 3 ) 2553.11 lit/s
( 4 ) 3130.448 lit/s
Problem (14): A pump is being used to lift water from an underground
tank through a pipe of diameter (d) at discharge (Q). The total head
loss until the pump entrance can be calculated as (h₁ = K[V²/2g]), h
where (V) is the flow velocity in the pipe. The elevation difference
between the pump and tank surface is (h).
Given the values of h [cm], d [cm], and K [-], calculate the maximum
discharge Q [Lit/s] beyond which cavitation would take place at the
pump entrance. Assume Turbulent flow conditions.
Givens:
h = 120.31 cm
d = 14.455 cm
K = 8.976
Q
Answers:
(1) 94.917 lit/s
(2) 49.048 lit/s
( 3 ) 80.722 lit/s
68.588 lit/s
4
Chapter 2 Solutions
MATERIALS SCI + ENGR: INT W/ACCESS
Ch. 2 - Prob. 1QAPCh. 2 - Prob. 2QAPCh. 2 - Prob. 3QAPCh. 2 - Prob. 4QAPCh. 2 - Prob. 5QAPCh. 2 - Prob. 6QAPCh. 2 - Prob. 7QAPCh. 2 - Prob. 8QAPCh. 2 - Prob. 9QAPCh. 2 - Prob. 10QAP
Ch. 2 - Prob. 11QAPCh. 2 - Prob. 12QAPCh. 2 - Prob. 13QAPCh. 2 - Prob. 14QAPCh. 2 - Prob. 15QAPCh. 2 - Prob. 17QAPCh. 2 - Prob. 19QAPCh. 2 - Prob. 20QAPCh. 2 - Prob. 22QAPCh. 2 - Prob. 24QAPCh. 2 - Prob. 25QAPCh. 2 - Prob. 26QAPCh. 2 - Prob. 27QAPCh. 2 - Prob. 1SSPCh. 2 - Prob. 2SSPCh. 2 - Prob. 1FEQPCh. 2 - Prob. 2FEQPCh. 2 - Prob. 3FEQP
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