Explanation Given: The given figure is, Figure (1) Formula used: The position of the subway train is given by, x f − x i = u t + 1 2 a t 2 The acceleration of the subway train is given by, a = v − u t Calculation: The acceleration of the subway train is calculated as, a = v − u t = ( 30 km / h − 0 km / h ) 20 s = ( 30 km / h × 1 h 3600 s ) 20 s = 4.166 × 10 − 4 km / s The position of the subway train is calculated as, x f − x i = u t + 1 2 a t 2 x f − 0 = ( 0 ) t + 1 2 ( 4.166 × 10 − 4 km / s ) t 2 = 1 2 ( 4.166 × 10 − 4 km / s ) t 2 The table for position of position and time is shown below. t ( s ) x f ( km ) 0 4

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Chapter 2, Problem 63PE

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The displacement graph for the subway shuttle train.

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5.97 Block A, with weight 3w, slides down an inclined plane S of slope angle 36.9° at a constant speed while plank B, with weight w, rests on top of A. The plank is attached by a cord to the wall (Fig. P5.97). (a) Draw a diagram of all the forces acting on block A. (b) If the coefficient of kinetic friction is the same between A and B and between S and A, determine its value. Figure P5.97 B A S 36.9°

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The displacement graph for the subway shuttle train.

Solution Summary: The author illustrates the displacement graph for the subway shuttle train in figure (2).

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