PHYSICS
PHYSICS
5th Edition
ISBN: 2818440038631
Author: GIAMBATTISTA
Publisher: MCG
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Chapter 2, Problem 55P

(a)

To determine

The vx versus t graph.

(a)

Expert Solution
Check Mark

Answer to Problem 55P

PHYSICS, Chapter 2, Problem 55P , additional homework tip  1

Explanation of Solution

Write an expression to calculate the acceleration.

ax=vfxvixtfti (I)

Here, the acceleration is a, the final velocity is vfx, the initial velocity is vix, the final time is tf and the initial time is ti.

Write an expression to calculate the slope of the vx versus t graph.

m=vfxvixtfti (II)

Here, the slope is m.

Thus, the slope of vx versus t graph is equal to the acceleration of the train.

Conclusion:

The vx versus t graph is plot on figure 1.

PHYSICS, Chapter 2, Problem 55P , additional homework tip  2

Figure 1

The vx versus t graph is a straight line with a slope of 1.40m/s2.

(b)

To determine

The speed of the graph after 8.0 s on the incline.

(b)

Expert Solution
Check Mark

Answer to Problem 55P

The speed of the graph after 8.0 s on the incline is 11m/s.

Explanation of Solution

Write an expression to find the speed of the graph after 8.0 s on the incline.

vfx=vix+axΔt (III)

Here, Δt is the time.

Conclusion:

Substitute 22m/s for vix, 1.40m/s2 for ax, and 8.0s for Δt in equation (III) to find vfx.

vfx=22m/s+(1.40m/s2)(8.0s)=22m/s11m/s=11m/s

Speed of the graph after 8.0 s on the incline is 11m/s.

(c)

To determine

The distance travelled by the train up the incline after 8.0 s.

(c)

Expert Solution
Check Mark

Answer to Problem 55P

The distance travelled by the train up the incline after 8.0 s is 130m.

Explanation of Solution

Write an expression to calculate the distance travelled by the train up the incline after 8.0 s

xf=xi+vixΔt+12ax(Δt)2 (IV)

Here, xf is the final position, and xi is the initial position.

Conclusion:

Substitute 0m for xi, 22m/s for vix, 1.40m/s2 for ax, and 8.0s in equation (IV) to find xf.

xf=(0m)+(22m/s)(8.0s)+12(1.40m/s2)(8.0s)2=(22m/s)(8.0s)+12(1.40m/s2)(8.0s)2=130m

Thus, the distance travelled by the train up the incline after 8.0 s is 130m.

(d)

To determine

Motion diagram to show the position of the train at 2.0 s.

(d)

Expert Solution
Check Mark

Answer to Problem 55P

PHYSICS, Chapter 2, Problem 55P , additional homework tip  3

Explanation of Solution

Motion diagram is used to determine the position of the train. The motion diagram is drawn by marking the position of train at different time. The motion diagram is illustrative model for motion of the particle.

The trains velocity and time can be used to find the position of the train at various spots. The position can be marked against the time. The position of the object at any time can be determined from motion diagram.

Conclusion:

The motion diagram is shown in figure 2. The position of object at 2.0 s is 40 m as marked in the motion diagram.

PHYSICS, Chapter 2, Problem 55P , additional homework tip  4

Figure 2

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Chapter 2 Solutions

PHYSICS

Ch. 2.4 - Prob. 2.4CPCh. 2.5 - Prob. 2.5CPCh. 2.5 - Prob. 2.6PPCh. 2.5 - Prob. 2.7PPCh. 2.5 - Prob. 2.8PPCh. 2.5 - Prob. 2.9PPCh. 2.6 - Prob. 2.6CPCh. 2.6 - Prob. 2.10PPCh. 2 - Prob. 1CQCh. 2 - Prob. 2CQCh. 2 - Prob. 3CQCh. 2 - Prob. 4CQCh. 2 - Prob. 5CQCh. 2 - Prob. 6CQCh. 2 - Prob. 7CQCh. 2 - Prob. 8CQCh. 2 - Prob. 9CQCh. 2 - Prob. 10CQCh. 2 - Prob. 11CQCh. 2 - Prob. 1MCQCh. 2 - Prob. 2MCQCh. 2 - Prob. 3MCQCh. 2 - Prob. 4MCQCh. 2 - Prob. 5MCQCh. 2 - Multiple-Choice Questions 6–15. A jogger is...Ch. 2 - 7. What is the displacement of the jogger for the...Ch. 2 - Prob. 8MCQCh. 2 - Prob. 9MCQCh. 2 - Multiple-Choice Questions 6–15. A jogger is...Ch. 2 - Prob. 11MCQCh. 2 - Prob. 12MCQCh. 2 - Prob. 13MCQCh. 2 - Prob. 14MCQCh. 2 - Prob. 15MCQCh. 2 - Prob. 16MCQCh. 2 - Prob. 17MCQCh. 2 - Prob. 18MCQCh. 2 - Prob. 19MCQCh. 2 - 20. Which graph shows a changing ax that is always...Ch. 2 - Prob. 21MCQCh. 2 - Prob. 22MCQCh. 2 - Prob. 23MCQCh. 2 - Prob. 24MCQCh. 2 - Prob. 25MCQCh. 2 - Prob. 26MCQCh. 2 - Prob. 27MCQCh. 2 - Prob. 28MCQCh. 2 - Prob. 29MCQCh. 2 - Prob. 30MCQCh. 2 - Prob. 1PCh. 2 - Prob. 2PCh. 2 - Prob. 3PCh. 2 - Prob. 4PCh. 2 - Prob. 5PCh. 2 - Prob. 6PCh. 2 - Prob. 7PCh. 2 - Prob. 8PCh. 2 - Prob. 9PCh. 2 - Prob. 10PCh. 2 - Prob. 16PCh. 2 - Prob. 11PCh. 2 - Prob. 12PCh. 2 - Prob. 13PCh. 2 - Prob. 14PCh. 2 - Prob. 15PCh. 2 - Prob. 17PCh. 2 - Prob. 18PCh. 2 - Prob. 22PCh. 2 - Prob. 19PCh. 2 - 21. The graph shows x(t) for a skater traveling...Ch. 2 - 22. The graph shows x(t) for an object traveling...Ch. 2 - Prob. 23PCh. 2 - Prob. 24PCh. 2 - Prob. 25PCh. 2 - Prob. 26PCh. 2 - Prob. 27PCh. 2 - Prob. 28PCh. 2 - Prob. 29PCh. 2 - Prob. 30PCh. 2 - Prob. 31PCh. 2 - Prob. 35PCh. 2 - Prob. 33PCh. 2 - Prob. 34PCh. 2 - Prob. 32PCh. 2 - 36. The graph with Problem 10 shows speedometer...Ch. 2 - Prob. 37PCh. 2 - Prob. 38PCh. 2 - Prob. 39PCh. 2 - Prob. 40PCh. 2 - Prob. 41PCh. 2 - Prob. 42PCh. 2 - Prob. 43PCh. 2 - Prob. 44PCh. 2 - Prob. 45PCh. 2 - Prob. 46PCh. 2 - Prob. 47PCh. 2 - Prob. 48PCh. 2 - Prob. 49PCh. 2 - Prob. 50PCh. 2 - Prob. 51PCh. 2 - Prob. 52PCh. 2 - Prob. 53PCh. 2 - Prob. 54PCh. 2 - Prob. 55PCh. 2 - Prob. 56PCh. 2 - Prob. 57PCh. 2 - Prob. 58PCh. 2 - Prob. 59PCh. 2 - Prob. 60PCh. 2 - Prob. 61PCh. 2 - Prob. 62PCh. 2 - Prob. 63PCh. 2 - Prob. 64PCh. 2 - Prob. 65PCh. 2 - Prob. 71PCh. 2 - Prob. 66PCh. 2 - Prob. 67PCh. 2 - Prob. 68PCh. 2 - Prob. 69PCh. 2 - Prob. 70PCh. 2 - Prob. 72PCh. 2 - Prob. 73PCh. 2 - Prob. 74PCh. 2 - Prob. 75PCh. 2 - Prob. 76PCh. 2 - Prob. 77PCh. 2 - Prob. 78PCh. 2 - Prob. 79PCh. 2 - Prob. 80PCh. 2 - Prob. 81PCh. 2 - Prob. 82PCh. 2 - Prob. 83PCh. 2 - Prob. 84PCh. 2 - Prob. 85PCh. 2 - Prob. 86P
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Position/Velocity/Acceleration Part 1: Definitions; Author: Professor Dave explains;https://www.youtube.com/watch?v=4dCrkp8qgLU;License: Standard YouTube License, CC-BY