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To graph: the inequality.
![Check Mark](/static/check-mark.png)
Explanation of Solution
Given:
Calculation:
To graph inequalities, locate the number opposite the variable of the inequality ona number line. If the inequality is either
From here, shade the line going to the left if the inequality is either
The number opposite the variable is 2, look for this in the number line. Since the inequality is
Conclusion:
Therefore, the required graph is drawn.
Chapter 2 Solutions
BIG IDEAS MATH Integrated Math 1: Student Edition 2016
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- The second solution I got is incorrect. What is the correct solution? The other thrree with checkmarks are correct Question 19 Score on last try: 0.75 of 1 pts. See Details for more. Get a similar question You can retry this question below Solve 3 sin 2 for the four smallest positive solutions 0.75/1 pt 81 99 Details T= 1.393,24.666,13.393,16.606 Give your answers accurate to at least two decimal places, as a list separated by commas Question Help: Message instructor Post to forum Submit Questionarrow_forwardTwo cables tied together at C are loaded as shown. Given: Q = 130 lb. 8 30° C B Q 3 4 Draw the free-body diagram needed to determine the range of values of P for which both cables remain taut.arrow_forwardCable AB is 103 ft long and the tension in the cable is 3900 lb. 56 ft A 50° 20° B x C Identify the angles 0.0, and 8, that define the direction of force. 1 By N 2 Match each of the options above to the items below. 142.1° 57.1° 73.3° 3 8.arrow_forward
- In the given figure, P = 51 lb . 65° C 25° 35° 75 lb P Determine the corresponding magnitude of the resultant. The corresponding magnitude of the resultant is| lb.arrow_forwardCable AB is 103 ft long and the tension in the cable is 3900 lb. 56 ft D y A B 20° 50° x C Identify the x, y, and z components of the force exerted by the cable on the anchor B. 1 F. FI 3 Fy 2 Match each of the options above to the items below. 2,120 lb 1,120 lb -3,076 lbarrow_forwardIn the given figure, P = 51 lb. 65° 25° 35° 75 lb P B Determine the required tension in cable AC, knowing that the resultant of the three forces exerted at point C of boom BC must be directed along BC. The required tension in cable AC is lb.arrow_forward
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