
Interpretation:
The given solvent capable of dissolving ionic compounds is to be identified.
Concept Introduction:
▸ A general rule of solubility is: like dissolves like.
▸ Polar and ionic solids are dissolved in polar solvents.
▸ Nonpolar solids are dissolved in nonpolar solvents.
▸ If a molecule has dipole moment, it is termed as polar molecule. The symmetrical molecules are non-polar because the dipole moment cancel each other.
▸ The species resistant to water or the species that are incompatible with water are termed as hydrophobic.
▸ The water loving species or the species compatible with water are termed as hydrophilic species.
▸ If the compound contains one hydrophilic group and more than six carbon atoms, then the compound is insoluble in water.
▸ Alkyl chains with high molecular weight are hydrophobic in nature.
▸ The hydroxyl group is hydrophilic in nature because it forms hydrogen bonding with water molecules.
▸ The carbonyl oxygen and hydroxyl group of
▸ A hydrogen bond is a partially electrostatic force of attraction between a hydrogen atom which is bound to more electronegative atom such as nitrogen, oxygen or fluorine and another atom bearing a lone pair of electron.
▸ The liquid
▸ The liquid
▸ In benzene, the bonds are polar due to the presence of electronegativity difference between carbon and hydrogen but the dipole moment cancel out due to the symmetrical structure of benzene. The net dipole moment is zero which makes the molecule non-polar.

Want to see the full answer?
Check out a sample textbook solution
Chapter 2 Solutions
ORGANIC CHEMISTRY-ETEXT REG ACCESS
- LTS Solid: AT=Te-Ti Trial 1 Trial 2 Trial 3 Average ΔΗ Mass water, g 24.096 23.976 23.975 Moles of solid, mol 0.01763 001767 0101781 Temp. change, °C 2.9°C 11700 2.0°C Heat of reaction, J -292.37J -170.473 -193.26J AH, kJ/mole 16.58K 9.647 kJ 10.85 kr 16.58K59.64701 KJ mol 12.35k Minimum AS, J/mol K 41.582 mol-k Remember: q = mCsAT (m = mass of water, Cs=4.184J/g°C) & qsin =-qrxn & Show your calculations for: AH in J and then in kJ/mole for Trial 1: qa (24.0969)(4.1845/g) (-2.9°C)=-292.37J qsin = qrxn = 292.35 292.37J AH in J = 292.375 0.2923kJ 0.01763m01 =1.65×107 AH in kJ/mol = = 16.58K 0.01763mol mol qrx Minimum AS in J/mol K (Hint: use the average initial temperature of the three trials, con Kelvin.) AS=AHIT (1.65×10(9.64×103) + (1.0 Jimaiarrow_forwardFor the compound: C8H17NO2 Use the following information to come up with a plausible structure: 8 This compound has "carboxylic acid amide" and ether functional groups. The peaks at 1.2ppm are two signals that are overlapping one another. One of the two signals is a doublet that represents 6 hydrogens; the other signal is a quartet that represents 3 hydrogens.arrow_forwardVnk the elements or compounds in the table below in decreasing order of their boiling points. That is, choose 1 next to the substance with the highest bolling point, choose 2 next to the substance with the next highest boiling point, and so on. substance C D chemical symbol, chemical formula or Lewis structure. CH,-N-CH, CH, H H 10: H C-C-H H H H Cale H 10: H-C-C-N-CH, Bri CH, boiling point (C) Сен (C) B (Choosearrow_forward
- Please help me find the 1/Time, Log [I^-] Log [S2O8^2-], Log(time) on the data table. With calculation steps. And the average for runs 1a-1b. Please help me thanks in advance. Will up vote!arrow_forwardQ1: Answer the questions for the reaction below: ..!! Br OH a) Predict the product(s) of the reaction. b) Is the substrate optically active? Are the product(s) optically active as a mix? c) Draw the curved arrow mechanism for the reaction. d) What happens to the SN1 reaction rate in each of these instances: 1. Change the substrate to Br "CI 2. Change the substrate to 3. Change the solvent from 100% CH3CH2OH to 10% CH3CH2OH + 90% DMF 4. Increase the substrate concentration by 3-fold.arrow_forwardExperiment 27 hates & Mechanisms of Reations Method I visual Clock Reaction A. Concentration effects on reaction Rates Iodine Run [I] mol/L [S₂082] | Time mo/L (SCC) 0.04 54.7 Log 1/ Time Temp Log [ ] 13,20] (time) / [I] 199 20.06 23.0 30.04 0.04 0.04 80.0 22.8 45 40.02 0.04 79.0 21.6 50.08 0.03 51.0 22.4 60-080-02 95.0 23.4 7 0.08 0-01 1970 23.4 8 0.08 0.04 16.1 22.6arrow_forward
- (15 pts) Consider the molecule B2H6. Generate a molecular orbital diagram but this time using a different approach that draws on your knowledge and ability to put concepts together. First use VSEPR or some other method to make sure you know the ground state structure of the molecule. Next, generate an MO diagram for BH2. Sketch the highest occupied and lowest unoccupied MOs of the BH2 fragment. These are called frontier orbitals. Now use these frontier orbitals as your basis set for producing LGO's for B2H6. Since the BH2 frontier orbitals become the LGOS, you will have to think about what is in the middle of the molecule and treat its basis as well. Do you arrive at the same qualitative MO diagram as is discussed in the book? Sketch the new highest occupied and lowest unoccupied MOs for the molecule (B2H6).arrow_forwardQ8: Propose an efficient synthesis of cyclopentene from cyclopentane.arrow_forwardQ7: Use compound A-D, design two different ways to synthesize E. Which way is preferred? Please explain. CH3I ONa NaOCH 3 A B C D E OCH3arrow_forward
- Predict major product(s) for the following reactions. Note the mechanism(s) of the reactions (SN1, E1, SN2 or E2).arrow_forward(10 pts) The density of metallic copper is 8.92 g cm³. The structure of this metal is cubic close-packed. What is the atomic radius of copper in copper metal?arrow_forwardPredict major product(s) for the following reactions. Note the mechanism(s) of the reactions (SN1, E1, SN2 or E2).arrow_forward
- Chemistry: The Molecular ScienceChemistryISBN:9781285199047Author:John W. Moore, Conrad L. StanitskiPublisher:Cengage Learning
