Materials Science And Engineering Properties
1st Edition
ISBN: 9781111988609
Author: Charles Gilmore
Publisher: Cengage Learning
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Chapter 2, Problem 3DRQ
To determine
The suitable material used for coating on an aluminum part to improve wear and abrasion resistance.
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04
Q4
A waste effluent of 1.25 m/s with BOD, 183 mg/L, DO=0 mg/L and T
= 20 °C is to be discharged into a river of 8 m³/s flow, BOD, = 2mg/L, DO
-9.14 mg/L and T= 15 °C. At 20 °C, (K₁) is 0.3/day and (K2) is 0.9/day.
The average velocity of the river is 0.8 m/s. 1) Is DO min within the
environmental limitations? 2) At what distance is the maximum deficit
located. 3) Draw the oxygen sag curve? Given the saturation concentration
at 15 °C and at mixed temperature = 10.15 mg/L
Calculate 1- the effluent BOD, of a two-stage trickling filter with the
following flows, BOD, and dimensions? Q-5000 m³/day, influent
BOD,-280 mg/L, volume of first filter-1000 m³, volume of second
filter-800 m³, filter depth-2 m, r₁=1, z=1.25. Also, 2- calculate organic
loading rate (BOD, kg/day) 3- Hydraulic loading (m³/m²/d), 4- efficiency
of each stage 5- overall removal efficiency.
Q3: Determine the force in each member of the shown truss, and state whether they are tension
or compression.
40 kN
3 m
10 kN
A
25-1.25
m
m
-3.5 m-
3 m
B
Chapter 2 Solutions
Materials Science And Engineering Properties
Ch. 2 - Prob. 1CQCh. 2 - Prob. 2CQCh. 2 - Prob. 3CQCh. 2 - Prob. 4CQCh. 2 - Prob. 5CQCh. 2 - Prob. 6CQCh. 2 - Prob. 7CQCh. 2 - Prob. 8CQCh. 2 - Prob. 9CQCh. 2 - Prob. 10CQ
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- Q3 Design a secondary clarifier for an activated sludge process with a recycle rate of 25 percent, a MLSS conc. 2500 mg/L, peak flow 9,000 m²/day, depth of tank 3 m and solid loading rate = 4 kg/m²/hrarrow_forwardA- Design grit removal chamber for a W.W.P with hourly flow equal 5000 m'h 410 markarrow_forward05 An average operating data for conventional activated sludge treatment plant is as follows: (1) Wastewater flow, Q-50000m/d (2) Volume of aeration tank, V-12000m (3) Influent BOD, Y.- 300 mg/1 (4) Effluent BOD, YE - 25 mg/1 (5) Mixed liquor suspended solids (MLSS), X₁ = 2500mg/1 (6) Effluent suspended solids, Xg30mg/1 (7) Waste sludge suspended solids, X-9700mg/1 (8) Quantity of waste sludge, Q., -220m³/d Based on the information above data, determine: (a) Aeration period (hrs.) (b) Food to microorganism ratio (F/M) (kg BOD per day/kg MLSS) (c) Percentage efficiency of BOD removal (d) Sludge age (days)arrow_forward
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