EBK ASTRONOMY TODAY
9th Edition
ISBN: 9780134583662
Author: Chaisson
Publisher: PEARSON CO
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Chapter 2, Problem 3D
To determine
The basic flaw in the Ptolemaic model of the universe as per our current knowledge.
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5). A conductor of radius r, length & and resistivity p has resistance R. It is melted down and formed into
a new conductor, also cylindrical, with one fourth the length of the original conductor. The resistance of
the new conductor is
a.
1
R
161
b.
1
R
C.
R
d. 4R
e. 16R
8). Determine the magnitude and sense (direction) of the current in the 10-Q2 resistor when I = 1.8 A.
30 V
L
50 V
10 Ω
20 Ω
a.
1.6 A right to left
b. 1.6 A left to right
C.
1.2 A right to left
d. 1.2 A left to right
e.
1.8 A left to right
R
PG
7). Determine the current in the 10-V emf.
5.0 0
w
10 V
5.0 0
15 V
5.0 Ω
a.
2.3 A
b. 2.7 A
c.
1.3 A
d. 0.30 A
e.
2.5 A
Chapter 2 Solutions
EBK ASTRONOMY TODAY
Ch. 2 - Prob. 1DCh. 2 - Prob. 2DCh. 2 - Prob. 3DCh. 2 - Prob. 4DCh. 2 - Prob. 5DCh. 2 - Prob. 6DCh. 2 - Prob. 7DCh. 2 - Prob. 8DCh. 2 - Prob. 9DCh. 2 - Prob. 10D
Ch. 2 - Prob. 11DCh. 2 - Prob. 12DCh. 2 - Prob. 13DCh. 2 - Prob. 14DCh. 2 - Prob. 15DCh. 2 - Prob. 1MCCh. 2 - Prob. 2MCCh. 2 - Prob. 3MCCh. 2 - Prob. 4MCCh. 2 - Prob. 5MCCh. 2 - Prob. 6MCCh. 2 - Prob. 7MCCh. 2 - Prob. 8MCCh. 2 - Prob. 9MCCh. 2 - Prob. 10MCCh. 2 - Prob. 1PCh. 2 - Prob. 2PCh. 2 - Prob. 3PCh. 2 - Prob. 4PCh. 2 - Prob. 5PCh. 2 - Prob. 6PCh. 2 - Prob. 7PCh. 2 - Prob. 8P
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