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MindTap Computing for Vermaat's Enhanced Discovering Computers, 1st Edition, [Instant Access], 1 term (6 months)
1st Edition
ISBN: 9781285845937
Author: Misty E. Vermaat
Publisher: Cengage Archive
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Expert Solution & Answer
Chapter 2, Problem 3.1E
Explanation of Solution
Justification:
“Yes”, every user has a data limit on mobile data plan.
Data limit:
- Data limit is about restricting the data speed...
Expert Solution & Answer
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make corrections of this program based on the errors shown. this is CIS 227 .
Create 6 users: Don, Liz, Shamir, Jose, Kate, and Sal.
Create 2 groups: marketing and research.
Add Shamir, Jose, and Kate to the marketing group.
Add Don, Liz, and Sal to the research group.
Create a shared directory for each group.
Create two files to put into each directory:
spreadsheetJanuary.txt
meetingNotes.txt
Assign access permissions to the directories:
Groups should have Read+Write access
Leave owner permissions as they are
“Everyone else” should not have any access
Submit for grade:
Screenshot of /etc/passwd contents showing your new users
Screenshot of /etc/group contents showing new groups with their members
Screenshot of shared directories you created with files and permissions
⚫ your circuit diagrams for your basic bricks, such as AND, OR, XOR gates and 1 bit multiplexers,
⚫ your circuit diagrams for your extended full adder, designed in Section 1 and
⚫ your circuit diagrams for your 8-bit arithmetical-logical unit, designed in Section 2.
1 An Extended Full Adder
In this Section, we are going to design an extended full adder circuit (EFA). That EFA takes 6 one bit inputs: aj, bj,
Cin, Tin, t₁ and to. Depending on the four possible combinations of values on t₁ and to, the EFA produces 3 one bit
outputs: sj, Cout and rout.
The EFA can be specified in principle by a truth table with 26 = 64 entries and 3 outputs. However, as the EFA
ignores certain inputs in certain cases, it is easier to work with the following overview specification, depending only
on t₁ and to in the first place:
t₁ to Description
00
Output Relationship
Ignored
Inputs
Addition Mode
2 Coutsjaj + bj + Cin, Tout= 0
Tin
0 1
Shift Left Mode
Sj = Cin,
Cout=bj, rout = 0
rin, aj
10
1 1
Shift Right…
Chapter 2 Solutions
MindTap Computing for Vermaat's Enhanced Discovering Computers, 1st Edition, [Instant Access], 1 term (6 months)
Ch. 2 - Prob. 1SGCh. 2 - Prob. 2SGCh. 2 - Prob. 3SGCh. 2 - Prob. 4SGCh. 2 - Prob. 5SGCh. 2 - Prob. 6SGCh. 2 - Prob. 7SGCh. 2 - Prob. 8SGCh. 2 - Prob. 9SGCh. 2 - Prob. 10SG
Ch. 2 - Prob. 11SGCh. 2 - Prob. 12SGCh. 2 - Prob. 13SGCh. 2 - Prob. 14SGCh. 2 - Prob. 15SGCh. 2 - Prob. 16SGCh. 2 - Prob. 17SGCh. 2 - Prob. 18SGCh. 2 - Prob. 19SGCh. 2 - Prob. 20SGCh. 2 - Prob. 21SGCh. 2 - Prob. 22SGCh. 2 - Prob. 23SGCh. 2 - Prob. 24SGCh. 2 - Prob. 25SGCh. 2 - Prob. 26SGCh. 2 - Prob. 27SGCh. 2 - Prob. 28SGCh. 2 - Prob. 29SGCh. 2 - Prob. 30SGCh. 2 - Prob. 31SGCh. 2 - Prob. 32SGCh. 2 - Prob. 33SGCh. 2 - Prob. 34SGCh. 2 - Prob. 35SGCh. 2 - Prob. 36SGCh. 2 - Prob. 37SGCh. 2 - Prob. 38SGCh. 2 - Prob. 39SGCh. 2 - Prob. 40SGCh. 2 - Prob. 41SGCh. 2 - Prob. 42SGCh. 2 - Prob. 43SGCh. 2 - Prob. 44SGCh. 2 - Prob. 45SGCh. 2 - Prob. 46SGCh. 2 - Prob. 47SGCh. 2 - Prob. 48SGCh. 2 - Prob. 49SGCh. 2 - Prob. 1TFCh. 2 - Prob. 2TFCh. 2 - Prob. 3TFCh. 2 - Prob. 4TFCh. 2 - Prob. 5TFCh. 2 - Prob. 6TFCh. 2 - Prob. 7TFCh. 2 - Prob. 8TFCh. 2 - Prob. 9TFCh. 2 - Prob. 10TFCh. 2 - Prob. 11TFCh. 2 - Prob. 12TFCh. 2 - Prob. 1MCCh. 2 - Prob. 2MCCh. 2 - Prob. 3MCCh. 2 - Prob. 4MCCh. 2 - Prob. 5MCCh. 2 - Prob. 6MCCh. 2 - Prob. 7MCCh. 2 - Prob. 8MCCh. 2 - Prob. 1MCh. 2 - Prob. 2MCh. 2 - Prob. 3MCh. 2 - Prob. 4MCh. 2 - Prob. 5MCh. 2 - Prob. 6MCh. 2 - Prob. 7MCh. 2 - Prob. 8MCh. 2 - Prob. 9MCh. 2 - Prob. 10MCh. 2 - Prob. 2CTCh. 2 - Prob. 3CTCh. 2 - Prob. 4CTCh. 2 - Prob. 5CTCh. 2 - Prob. 6CTCh. 2 - Prob. 7CTCh. 2 - Prob. 8CTCh. 2 - Prob. 9CTCh. 2 - Prob. 10CTCh. 2 - Prob. 11CTCh. 2 - Prob. 12CTCh. 2 - Prob. 13CTCh. 2 - Prob. 14CTCh. 2 - Prob. 15CTCh. 2 - Prob. 16CTCh. 2 - Prob. 17CTCh. 2 - Prob. 18CTCh. 2 - Prob. 19CTCh. 2 - Prob. 20CTCh. 2 - Prob. 21CTCh. 2 - Prob. 22CTCh. 2 - Prob. 23CTCh. 2 - Prob. 24CTCh. 2 - Prob. 25CTCh. 2 - Prob. 26CTCh. 2 - Prob. 27CTCh. 2 - Prob. 1PSCh. 2 - Prob. 2PSCh. 2 - Prob. 3PSCh. 2 - Prob. 4PSCh. 2 - Prob. 5PSCh. 2 - Prob. 6PSCh. 2 - Prob. 7PSCh. 2 - Prob. 8PSCh. 2 - Prob. 9PSCh. 2 - Prob. 10PSCh. 2 - Prob. 11PSCh. 2 - Prob. 1.1ECh. 2 - Prob. 1.2ECh. 2 - Prob. 1.3ECh. 2 - Prob. 2.1ECh. 2 - Prob. 2.2ECh. 2 - Prob. 2.3ECh. 2 - Prob. 3.1ECh. 2 - Prob. 3.2ECh. 2 - Prob. 3.3ECh. 2 - Prob. 4.1ECh. 2 - Prob. 4.2ECh. 2 - Prob. 4.3ECh. 2 - Prob. 5.1ECh. 2 - Prob. 5.2ECh. 2 - Prob. 5.3ECh. 2 - Prob. 1IRCh. 2 - Prob. 2IRCh. 2 - Prob. 3IRCh. 2 - Prob. 4IRCh. 2 - Prob. 1CTQCh. 2 - Prob. 2CTQCh. 2 - Prob. 3CTQ
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