(a) The time when the velocity is greatest. 48 s. Given: The graph is given, Solution: According to the given graph, At time, t = 48 s The velocity is, v = 40 m/s Conclusion: Hence, the velocity is greatest at time 48s. (b) The time duration where the velocity is constant. 88 s to 108 s. Given: The graph is given, Solution: According to the given graph, At time t = 88 s to 108 s The velocity in the given graph is zero because the line is flat and horizontal. So, velocity will be constant. v = 0 m/s Conclusion: Hence, the velocity is constant at time 88 s to 108 s. (c) The time duration where the acceleration is constant. 88 s to 108 s. Given: The graph is given, Solution: According to the given graph, At time t = 0 s to 40 s The velocity and time graph has a straight line, so, the derivative of straight will be constant. The derivative of velocity with respect to time is called acceleration. d v = ( 35 − 15 ) m/s d v = 20 m/s d t = ( 40 − 0 ) s a = d v d t a = 20 m/s 40 m a = 0.5 m/s 2 So, the acceleration is constant. At time t = 88 s to 108 s The velocity from 88 s to 108 s is zero. Now, the derivative of velocity with respect to time is called acceleration. So, the velocity is zero, and the derivative of velocity will also be zero, which indicates the acceleration is constant. a = d v d t a = 0 Conclusion: Hence, the acceleration is constant at time 88 s to 108 s. (d.) The time duration where the acceleration is highest. 50 s to 80 s. Given: The graph is given, Solution: According to the given graph, At time t = 50 s to 80 s The velocity and time curve has steeper from 50 s to 80 s so, the acceleration is greatest in this duration. Conclusion: Hence, the acceleration is greatest at time 50 s to 80 s.

A convex mirror (f.=-6.20cm) and a concave minor (f2=8.10 cm) distance of 15.5cm are facing each other and are separated by a An object is placed between the mirrors and is 7.8cm from each mirror. Consider the light from the object that reflects first from the convex mirror and then from the concave mirror. What is the distance of the image (dia) produced by the concave mirror? cm.

An amusement park spherical mirror shows park spherical mirror shows anyone who stands 2.80m in front of it an upright image one and a half times the person's height. What is the focal length of the minor? m.

An m = 69.0-kg person running at an initial speed of v = 4.50 m/s jumps onto an M = 138-kg cart initially at rest (figure below). The person slides on the cart's top surface and finally comes to rest relative to the cart. The coefficient of kinetic friction between the person and the cart is 0.440. Friction between the cart and ground can be ignored. (Let the positive direction be to the right.) m M (a) Find the final velocity of the person and cart relative to the ground. (Indicate the direction with the sign of your answer.) m/s (b) Find the friction force acting on the person while he is sliding across the top surface of the cart. (Indicate the direction with the sign of your answer.) N (c) How long does the friction force act on the person? S (d) Find the change in momentum of the person. (Indicate the direction with the sign of your answer.) N.S Find the change in momentum of the cart. (Indicate the direction with the sign of your answer.) N.S (e) Determine the displacement of the…