Loose Leaf For Introduction To Computing Systems: From Bits & Gates To C & Beyond
Loose Leaf For Introduction To Computing Systems: From Bits & Gates To C & Beyond
3rd Edition
ISBN: 9781260424744
Author: Yale N. Patt, Sanjay Patel
Publisher: McGraw-Hill Education
Question
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Chapter 2, Problem 30E

a.

Program Plan Intro

AND function:

  • AND function needs two inputs and produces one output.
  • It is also known as binary logical function.
  • If either of the inputs or both the inputs are “0”, then one-bit AND operation produces the output as “0”.
  • If both inputs are “1”, then AND operation produces the output as “1”.
  • The following diagram depicts the AND operation,

Loose Leaf For Introduction To Computing Systems: From Bits & Gates To C & Beyond, Chapter 2, Problem 30E

b.

Explanation of Solution

101 AND 110:

The truth table for AND operation is as follows,

XYX AND Y
000
010
100
111

Explanation for the truth table:

  • In the above table, “X” and “Y” are inputs, and “Z” is output.
  • When “X=0”, and “Y=0”, the output is “0”, because both the inputs “X” and “Y” contains the value “0”.
  • When “X=0”, and “Y=1”, the output is “0”, because one of the input “X” contains the value “0”.
  • When “X=1”, and “Y=0”, the output is “0”, because one of the input “Y” contains the value “0”...

c.

Explanation of Solution

11100000 AND 10110100:

The truth table for AND operation is as follows,

XYX AND Y
000
010
100
111

Explanation for the truth table:

  • In the above table, “X” and “Y” are inputs, and “Z” is output.
  • When “X=0”, and “Y=0”, the output is “0”, because both the inputs “X” and “Y” contains the value “0”.
  • When “X=0”, and “Y=1”, the output is “0”, because one of the input “X” contains the value “0”.
  • When “X=1”, and “Y=0”, the output is “0”, because one of the input “Y” contains the value “0”...

d.

Explanation of Solution

00011111 AND 10110100:

The truth table for AND operation is as follows,

XYX AND Y
000
010
100
111

Explanation for the truth table:

  • In the above table, “X” and “Y” are inputs, and “Z” is output.
  • When “X=0”, and “Y=0”, the output is “0”, because both the inputs “X” and “Y” contains the value “0”.
  • When “X=0”, and “Y=1”, the output is “0”, because one of the input “X” contains the value “0”.
  • When “X=1”, and “Y=0”, the output is “0”, because one of the input “Y” contains the value “0”...

e.

Explanation of Solution

(0011 AND 0110) AND 1101:

The truth table for AND operation is as follows,

XYX AND Y
000
010
100
111

Explanation for the truth table:

  • In the above table, “X” and “Y” are inputs, and “Z” is output.
  • When “X=0”, and “Y=0”, the output is “0”, because both the inputs “X” and “Y” contains the value “0”.
  • When “X=0”, and “Y=1”, the output is “0”, because one of the input “X” contains the value “0”.
  • When “X=1”, and “Y=0”, the output is “0”, because one of the input “Y” contains the value “0”.
  • When “X=1”, and “Y=1”, the output is “1”, because both the inputs “X” and “Y” contains the value “1”...

f.

Explanation of Solution

0011 AND (0110 AND 1101):

The truth table for AND operation is as follows,

XYX AND Y
000
010
100
111

Explanation for the truth table:

  • In the above table, “X” and “Y” are inputs, and “Z” is output.
  • When “X=0”, and “Y=0”, the output is “0”, because both the inputs “X” and “Y” contains the value “0”.
  • When “X=0”, and “Y=1”, the output is “0”, because one of the input “X” contains the value “0”.
  • When “X=1”, and “Y=0”, the output is “0”, because one of the input “Y” contains the value “0”.
  • When “X=1”, and “Y=1”, the output is “1”, because both the inputs “X” and “Y” contains the value “1”...

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