Web Development and Design Foundations with HTML5 (9th Edition) (What's New in Computer Science)
9th Edition
ISBN: 9780134801148
Author: Terry Felke-Morris
Publisher: PEARSON
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Chapter 2, Problem 2MC
Program Description Answer
Configuring the next element or the portion of text for displaying on new line is done through the tag <br>.
Hence, the correct answer is option “C”.
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1. The main function creates 5 pixels with random red, green, and blue values. Complete the id_color function to return “red” if the red value is greater than the green and blue, “green” if the green value is greater than the red and blue, and “blue” if the blue value is greater than the red and green. If there is no clear maximum value (for example, if the red and green values are the same) return None. Do not change the main function.
1. The main function creates 5 pixels with random red, green, and blue values. Complete the id_color function to return “red” if the red value is greater than the green and blue, “green” if the green value is greater than the red and blue, and “blue” if the blue value is greater than the red and green. If there is no clear maximum value (for example, if the red and green values are the same) return None. Do not change the main function.
import imageimport random
def id_color(p):'''Returns the dominant color of pixel p'''pass#Your code here to determine the dominant color and return a string identifying it#Hint: get the red, green & blue values and use an if statement to determine which has the highest value
def main():'''Controls the program'''for i in range(5): #Loop 5 timesr = random.randrange(0, 256)g = random.randrange(0, 256)b = random.randrange(0, 256)print(r, g, b) #Show the pixel red, green & blue valuesnew_pixel = image.Pixel(r, g, b)print(id_color(new_pixel))
main()…
Why <FROM> tag used? What are the various Attributes of the <FORM> tag.
Chapter 2 Solutions
Web Development and Design Foundations with HTML5 (9th Edition) (What's New in Computer Science)
Ch. 2.6 - Prob. 1CPCh. 2.6 - Prob. 2CPCh. 2.6 - Prob. 3CPCh. 2.14 - Prob. 1CPCh. 2.14 - Prob. 2CPCh. 2.14 - Prob. 3CPCh. 2.17 - Prob. 1CPCh. 2.17 - Prob. 2CPCh. 2.17 - Prob. 3CPCh. 2 - Prob. 3MC
Ch. 2 - Prob. 2MCCh. 2 - Prob. 1MCCh. 2 - Prob. 4MCCh. 2 - Prob. 5MCCh. 2 - Prob. 6MCCh. 2 - Prob. 7MCCh. 2 - Prob. 8MCCh. 2 - Prob. 9MCCh. 2 - Prob. 10MCCh. 2 - Prob. 11FIBCh. 2 - ___________ can be used to display characters such...Ch. 2 - Prob. 13FIBCh. 2 - Prob. 14FIBCh. 2 - Prob. 15FIBCh. 2 - Prob. 16SACh. 2 - Prob. 1AYKCh. 2 - Prob. 2AYKCh. 2 - Prob. 3AYKCh. 2 - Prob. 1HOECh. 2 - Prob. 2HOECh. 2 - Prob. 3HOECh. 2 - Prob. 4HOECh. 2 - Prob. 5HOECh. 2 - Prob. 6HOECh. 2 - Prob. 7HOECh. 2 - Prob. 8HOECh. 2 - Prob. 9HOECh. 2 - Prob. 10HOECh. 2 - Prob. 1FWD
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