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Student Solutions Manual to accompany Atkins' Physical Chemistry 11th edition
11th Edition
ISBN: 9780198807773
Author: ATKINS
Publisher: Oxford University Press
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Question
Chapter 2, Problem 2D.4AE
Interpretation Introduction
Interpretation: The pressure that must be applied to increase the density of water has to be calculated.
Concept introduction: The isothermal compressibility of a gas is used to express the fractional decrement in the volume of a gas and small amount of increment in the pressure of a gas at constant temperature. It is denoted by κT. The expression that is used to show the isothermal compressibility of a gas is given as,
κT=−ΔVVΔp
Expert Solution & Answer
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Students have asked these similar questions
Use the References to access important values if needed for this question.
What is the IUPAC name of each of the the following?
0
CH3CHCNH₂
CH3
CH3CHCNHCH2CH3
CH3
You have now performed a liquid-liquid extraction protocol in Experiment 4. In doing so, you
manipulated and exploited the acid-base chemistry of one or more of the compounds in your
mixture to facilitate their separation into different phases. The key to understanding how liquid-
liquid extractions work is by knowing which layer a compound is in, and in what protonation state.
The following liquid-liquid extraction is different from the one you performed in Experiment
4, but it uses the same type of logic. Your task is to show how to separate apart Compound
A and Compound B.
. Complete the following flowchart of a liquid-liquid extraction. Handwritten work is
encouraged.
•
Draw by hand (neatly) only the appropriate organic compound(s) in the boxes.
.
Specify the reagent(s)/chemicals (name is fine) and concentration as required in Boxes 4
and 5.
•
Box 7a requires the solvent (name is fine).
•
Box 7b requires one inorganic compound.
• You can neatly complete this assignment by hand and…
b) Elucidate compound D w) mt at 170 nd shows c-1 stretch at 550cm;'
The compound has the ff electronic transitions: 0%o* and no a*
1H NMR Spectrum
(CDCl3, 400 MHz)
3.5
3.0
2.5
2.0
1.5
1.0
0.5 ppm
13C{H} NMR Spectrum
(CDCl3, 100 MHz)
Solvent
80
70
60
50
40
30
20
10
0 ppm
ppm
¹H-13C me-HSQC Spectrum
ppm
(CDCl3, 400 MHz)
5
¹H-¹H COSY Spectrum
(CDCl3, 400 MHz)
0.5
10
3.5
3.0
2.5
2.0
1.5 1.0
10
15
20
20
25
30
30
-35
-1.0
1.5
-2.0
-2.5
3.0
-3.5
0.5
ppm
3.5
3.0
2.5
2.0
1.5
1.0
0.5
ppm
Chapter 2 Solutions
Student Solutions Manual to accompany Atkins' Physical Chemistry 11th edition
Ch. 2 - Prob. 2A.1STCh. 2 - Prob. 2B.1STCh. 2 - Prob. 2B.2STCh. 2 - Prob. 2C.1STCh. 2 - Prob. 2C.2STCh. 2 - Prob. 2D.1STCh. 2 - Prob. 2D.2STCh. 2 - Prob. 2A.1DQCh. 2 - Prob. 2A.2DQCh. 2 - Prob. 2A.3DQ
Ch. 2 - Prob. 2A.4DQCh. 2 - Prob. 2A.5DQCh. 2 - Prob. 2A.1AECh. 2 - Prob. 2A.1BECh. 2 - Prob. 2A.2AECh. 2 - Prob. 2A.2BECh. 2 - Prob. 2A.3AECh. 2 - Prob. 2A.3BECh. 2 - Prob. 2A.4AECh. 2 - Prob. 2A.4BECh. 2 - Prob. 2A.5AECh. 2 - Prob. 2A.5BECh. 2 - Prob. 2A.6AECh. 2 - Prob. 2A.6BECh. 2 - Prob. 2A.1PCh. 2 - Prob. 2A.2PCh. 2 - Prob. 2A.3PCh. 2 - Prob. 2A.4PCh. 2 - Prob. 2A.5PCh. 2 - Prob. 2A.6PCh. 2 - Prob. 2A.7PCh. 2 - Prob. 2A.8PCh. 2 - Prob. 2A.9PCh. 2 - Prob. 2A.10PCh. 2 - Prob. 2B.1DQCh. 2 - Prob. 2B.2DQCh. 2 - Prob. 2B.1AECh. 2 - Prob. 2B.1BECh. 2 - Prob. 2B.2AECh. 2 - Prob. 2B.2BECh. 2 - Prob. 2B.3AECh. 2 - Prob. 2B.3BECh. 2 - Prob. 2B.4AECh. 2 - Prob. 2B.4BECh. 2 - Prob. 2B.1PCh. 2 - Prob. 2B.2PCh. 2 - Prob. 2B.3PCh. 2 - Prob. 2B.4PCh. 2 - Prob. 2B.5PCh. 2 - Prob. 2C.1DQCh. 2 - Prob. 2C.2DQCh. 2 - Prob. 2C.3DQCh. 2 - Prob. 2C.4DQCh. 2 - Prob. 2C.1AECh. 2 - Prob. 2C.1BECh. 2 - Prob. 2C.2AECh. 2 - Prob. 2C.2BECh. 2 - Prob. 2C.3AECh. 2 - Prob. 2C.3BECh. 2 - Prob. 2C.4AECh. 2 - Prob. 2C.4BECh. 2 - Prob. 2C.5AECh. 2 - Prob. 2C.5BECh. 2 - Prob. 2C.6AECh. 2 - Prob. 2C.6BECh. 2 - Prob. 2C.7AECh. 2 - Prob. 2C.7BECh. 2 - Prob. 2C.8AECh. 2 - Prob. 2C.8BECh. 2 - Prob. 2C.1PCh. 2 - Prob. 2C.2PCh. 2 - Prob. 2C.3PCh. 2 - Prob. 2C.4PCh. 2 - Prob. 2C.5PCh. 2 - Prob. 2C.6PCh. 2 - Prob. 2C.7PCh. 2 - Prob. 2C.8PCh. 2 - Prob. 2C.9PCh. 2 - Prob. 2C.10PCh. 2 - Prob. 2C.11PCh. 2 - Prob. 2D.1DQCh. 2 - Prob. 2D.2DQCh. 2 - Prob. 2D.1AECh. 2 - Prob. 2D.1BECh. 2 - Prob. 2D.2AECh. 2 - Prob. 2D.2BECh. 2 - Prob. 2D.3AECh. 2 - Prob. 2D.3BECh. 2 - Prob. 2D.4AECh. 2 - Prob. 2D.4BECh. 2 - Prob. 2D.5AECh. 2 - Prob. 2D.5BECh. 2 - Prob. 2D.1PCh. 2 - Prob. 2D.2PCh. 2 - Prob. 2D.3PCh. 2 - Prob. 2D.4PCh. 2 - Prob. 2D.5PCh. 2 - Prob. 2D.6PCh. 2 - Prob. 2D.7PCh. 2 - Prob. 2D.8PCh. 2 - Prob. 2D.9PCh. 2 - Prob. 2E.1DQCh. 2 - Prob. 2E.2DQCh. 2 - Prob. 2E.1AECh. 2 - Prob. 2E.1BECh. 2 - Prob. 2E.2AECh. 2 - Prob. 2E.2BECh. 2 - Prob. 2E.3AECh. 2 - Prob. 2E.3BECh. 2 - Prob. 2E.4AECh. 2 - Prob. 2E.4BECh. 2 - Prob. 2E.5AECh. 2 - Prob. 2E.5BECh. 2 - Prob. 2E.1PCh. 2 - Prob. 2E.2PCh. 2 - Prob. 2.1IACh. 2 - Prob. 2.3IACh. 2 - Prob. 2.4IACh. 2 - Prob. 2.5IACh. 2 - Prob. 2.6IACh. 2 - Prob. 2.7IA
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- Part I. a) Elucidate the structure of compound A using the following information. • mass spectrum: m+ = 102, m/2=57 312=29 • IR spectrum: 1002.5 % TRANSMITTANCE Ngg 50 40 30 20 90 80 70 60 MICRONS 5 8 9 10 12 13 14 15 16 19 1740 cm M 10 0 4000 3600 3200 2800 2400 2000 1800 1600 13 • CNMR 'H -NMR Peak 8 ppm (H) Integration multiplicity a 1.5 (3H) triplet b 1.3 1.5 (3H) triplet C 2.3 1 (2H) quartet d 4.1 1 (2H) quartet & ppm (c) 10 15 28 60 177 (C=0) b) Elucidate the structure of compound B using the following information 13C/DEPT NMR 150.9 MHz IIL 1400 WAVENUMBERS (CM-1) DEPT-90 DEPT-135 85 80 75 70 65 60 55 50 45 40 35 30 25 20 ppm 1200 1000 800 600 400arrow_forward• Part II. a) Elucidate The structure of compound c w/ molecular formula C10 11202 and the following data below: • IR spectra % TRANSMITTANCE 1002.5 90 80 70 60 50 40 30 20 10 0 4000 3600 3200 2800 2400 2000 1800 1600 • Information from 'HAMR MICRONS 8 9 10 11 14 15 16 19 25 1400 WAVENUMBERS (CM-1) 1200 1000 800 600 400 peak 8 ppm Integration multiplicity a 2.1 1.5 (3H) Singlet b 3.6 1 (2H) singlet с 3.8 1.5 (3H) Singlet d 6.8 1(2H) doublet 7.1 1(2H) doublet Information from 13C-nmR Normal carbon 29ppm Dept 135 Dept -90 + NO peak NO peak 50 ppm 55 ppm + NO peak 114 ppm t 126 ppm No peak NO peak 130 ppm t + 159 ppm No peak NO peak 207 ppm по реак NO peakarrow_forwardCould you redraw these and also explain how to solve them for me pleasarrow_forward
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