EBK CHEMICAL PRINCIPLES IN THE LABORATO
EBK CHEMICAL PRINCIPLES IN THE LABORATO
11th Edition
ISBN: 9781305446366
Author: SLOWINSKI
Publisher: YUZU
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Chapter 2, Problem 2ASA
Interpretation Introduction

Interpretation:

The reason as to why the samples can often be separated into their components by chromatography is to be stated.

Concept introduction:

Chromatography is the technique used to identify the components of a mixture. The separation of mixture is based upon the polarity of the components present in the mixture. The division of the distance covered by the component of a compound to the distance covered by solvent in the chromatography technique is known as the Rf value. The full form of Rf value is retention value.

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13. (11pts total) Consider the arrows pointing at three different carbon-carbon bonds in the molecule depicted below. Bond B 2°C. +2°C. cleavage Bond A •CH3 + 26.← Cleavage 2°C. + Bond C +3°C• CH3 2C Cleavage E 2°C. 26. weakest bond Intact molecule Strongest 3°C 20. Gund Largest argest a. (2pts) Which bond between A-C is weakest? Which is strongest? Place answers in appropriate boxes. C Weakest bond A Produces Most Bond Strongest Bond Strongest Gund produces least stable radicals Weakest Stable radical b. (4pts) Consider the relative stability of all cleavage products that form when bonds A, B, AND C are homolytically cleaved/broken. Hint: cleavage products of bonds A, B, and C are all carbon radicals. i. Which ONE cleavage product is the most stable? A condensed or bond line representation is fine. 13°C. formed in bound C cleavage ii. Which ONE cleavage product is the least stable? A condensed or bond line representation is fine. • CH3 methyl radical Formed in Gund A Cleavage c.…

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EBK CHEMICAL PRINCIPLES IN THE LABORATO

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