Concepts of Database Management
9th Edition
ISBN: 9781337093422
Author: Joy L. Starks, Philip J. Pratt, Mary Z. Last
Publisher: Cengage Learning
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Chapter 2, Problem 28RQ
To determine
To describe the result of Division process in Relational Algebra.
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using r language
I need help to solve a simple problem using Grover’s algorithm, where the solution is not necessarily known beforehand. The problem is a 2×2 binary sudoku with two rules:
• No column may contain the same value twice.
• No row may contain the same value twice.
Each square in the sudoku is assigned to a variable as follows:
We want to design a quantum circuit that outputs a valid solution to this sudoku. While using Grover’s algorithm for this task is not necessarily practical, the goal is to demonstrate how classical decision problems can be converted into oracles for Grover’s algorithm.
Turning the Problem into a Circuit
To solve this, an oracle needs to be created that helps identify valid solutions. The first step is to construct a classical function within a quantum circuit that checks whether a given state satisfies the sudoku rules.
Since we need to check both columns and rows, there are four conditions to verify:
v0 ≠ v1 # Check top row
v2 ≠ v3 # Check bottom row…
using r language
Chapter 2 Solutions
Concepts of Database Management
Ch. 2 - Prob. 1RQCh. 2 - Prob. 2RQCh. 2 - Prob. 3RQCh. 2 - Prob. 4RQCh. 2 - Prob. 5RQCh. 2 - Prob. 6RQCh. 2 - Prob. 7RQCh. 2 - Prob. 8RQCh. 2 - Prob. 9RQCh. 2 - Prob. 10RQ
Ch. 2 - Prob. 11RQCh. 2 - Prob. 12RQCh. 2 - Prob. 13RQCh. 2 - Prob. 14RQCh. 2 - Prob. 15RQCh. 2 - Prob. 16RQCh. 2 - Prob. 17RQCh. 2 - Prob. 18RQCh. 2 - Prob. 19RQCh. 2 - Prob. 20RQCh. 2 - Prob. 21RQCh. 2 - Prob. 22RQCh. 2 - Prob. 23RQCh. 2 - Prob. 24RQCh. 2 - Prob. 25RQCh. 2 - Prob. 26RQCh. 2 - Prob. 27RQCh. 2 - Prob. 28RQCh. 2 - Prob. 29RQCh. 2 - Prob. 30RQCh. 2 - Prob. 1BCEQBECh. 2 - Prob. 2BCEQBECh. 2 - Prob. 3BCEQBECh. 2 - Prob. 4BCEQBECh. 2 - Prob. 5BCEQBECh. 2 - Prob. 6BCEQBECh. 2 - Prob. 7BCEQBECh. 2 - Prob. 8BCEQBECh. 2 - Prob. 9BCEQBECh. 2 - Prob. 10BCEQBECh. 2 - Prob. 11BCEQBECh. 2 - Prob. 12BCEQBECh. 2 - Prob. 13BCEQBECh. 2 - Prob. 14BCEQBECh. 2 - Prob. 15BCEQBECh. 2 - Prob. 16BCEQBECh. 2 - Prob. 17BCEQBECh. 2 - Prob. 18BCEQBECh. 2 - Prob. 1BCERACh. 2 - Prob. 2BCERACh. 2 - Prob. 3BCERACh. 2 - Prob. 4BCERACh. 2 - Prob. 5BCERACh. 2 - Prob. 6BCERACh. 2 - Prob. 7BCERACh. 2 - Prob. 1CATCCh. 2 - Prob. 2CATCCh. 2 - Prob. 3CATCCh. 2 - Prob. 4CATCCh. 2 - Prob. 5CATCCh. 2 - Prob. 6CATCCh. 2 - Prob. 7CATCCh. 2 - Prob. 8CATCCh. 2 - Prob. 9CATCCh. 2 - Prob. 10CATCCh. 2 - Prob. 11CATCCh. 2 - Prob. 12CATCCh. 2 - Prob. 13CATCCh. 2 - Prob. 14CATCCh. 2 - Prob. 15CATCCh. 2 - Prob. 16CATCCh. 2 - Prob. 17CATCCh. 2 - Prob. 18CATCCh. 2 - Prob. 1SPTCCh. 2 - Prob. 2SPTCCh. 2 - Prob. 3SPTCCh. 2 - Prob. 4SPTCCh. 2 - Prob. 5SPTCCh. 2 - Prob. 6SPTCCh. 2 - Prob. 7SPTCCh. 2 - Prob. 8SPTCCh. 2 - Prob. 9SPTCCh. 2 - Prob. 10SPTCCh. 2 - Prob. 11SPTCCh. 2 - Prob. 12SPTCCh. 2 - Prob. 13SPTCCh. 2 - Prob. 14SPTCCh. 2 - Prob. 15SPTCCh. 2 - Prob. 16SPTCCh. 2 - Prob. 17SPTCCh. 2 - Prob. 18SPTCCh. 2 - Prob. 19SPTC
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