Two thin rods are fastened to the inside of a circular ring as shown in Figure P2.42. One rod of length D is vertical, and the other of length L makes an angle θ with the horizontal. The two rods and the ring lie in a vertical plane. Two small beads are free to slide without friction along the rods. (a) If the two beads are released from rest simultaneously from the positions shown, use your intuition and guess which bead reaches the bottom first. (b) Find an expression for the time interval required for the red head to fall from point Ⓐ to point Ⓒ in terms of g and D . (c) Find an expression for the time interval required for the blue bead to slide from point Ⓑ to point Ⓒ in terms of g , L , and θ . (d) Show that the two time intervals found in parts (b) and (c) are equal. Hint: What is the angle between the chords of the circle Ⓐ Ⓑ and Ⓑ Ⓒ? (e) Do these results surprise you? Was your intuitive guess in part (a) correct? This problem was inspired by an article by Thomas B. Greenslade, Jr., “Galileo’s Paradox,” Phys . Teach . 46 , 294 (May 2008). Figure P2.42
Two thin rods are fastened to the inside of a circular ring as shown in Figure P2.42. One rod of length D is vertical, and the other of length L makes an angle θ with the horizontal. The two rods and the ring lie in a vertical plane. Two small beads are free to slide without friction along the rods. (a) If the two beads are released from rest simultaneously from the positions shown, use your intuition and guess which bead reaches the bottom first. (b) Find an expression for the time interval required for the red head to fall from point Ⓐ to point Ⓒ in terms of g and D . (c) Find an expression for the time interval required for the blue bead to slide from point Ⓑ to point Ⓒ in terms of g , L , and θ . (d) Show that the two time intervals found in parts (b) and (c) are equal. Hint: What is the angle between the chords of the circle Ⓐ Ⓑ and Ⓑ Ⓒ? (e) Do these results surprise you? Was your intuitive guess in part (a) correct? This problem was inspired by an article by Thomas B. Greenslade, Jr., “Galileo’s Paradox,” Phys . Teach . 46 , 294 (May 2008). Figure P2.42
Solution Summary: The author analyzes the first guess on which bead reaches the bottom first. The blue travels a shorter distance with an acceleration of gmathrm
Two thin rods are fastened to the inside of a circular ring as shown in Figure P2.42. One rod of length D is vertical, and the other of length L makes an angle θ with the horizontal. The two rods and the ring lie in a vertical plane. Two small beads are free to slide without friction along the rods. (a) If the two beads are released from rest simultaneously from the positions shown, use your intuition and guess which bead reaches the bottom first. (b) Find an expression for the time interval required for the red head to fall from point Ⓐ to point Ⓒ in terms of g and D. (c) Find an expression for the time interval required for the blue bead to slide from point Ⓑ to point Ⓒ in terms of g, L, and θ. (d) Show that the two time intervals found in parts (b) and (c) are equal. Hint: What is the angle between the chords of the circle Ⓐ Ⓑ and Ⓑ Ⓒ? (e) Do these results surprise you? Was your intuitive guess in part (a) correct? This problem was inspired by an article by Thomas B. Greenslade, Jr., “Galileo’s Paradox,” Phys. Teach. 46, 294 (May 2008).
The figure (Figure 1) shows representations of six
thermodynamic states of the same ideal gas sample.
Figure
1 of 1
Part A
■Review | Constants
Rank the states on the basis of the pressure of the gas sample at each state.
Rank pressure from highest to lowest. To rank items as equivalent, overlap them.
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highest
0
☐ ☐ ☐ ☐ ☐ ☐
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B
F
A
D
E
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Part A
m
2πkT
) 3/2
Calculate the integral (v) = f vƒ (v)dv. The function f(v) describing the actual distribution of molecular speeds is called the Maxwell-Boltzmann distribution,
=
ƒ(v) = 4π (· v²e-mv²/2kT
. (Hint: Make the change of variable v² =x and use the tabulated integral foxne
integer and a is a positive constant.)
Express your answer in terms of the variables T, m, and appropriate constants.
-ax dx
n!
-
an+1
where n is a positive
(v)
=
ΕΠΙ ΑΣΦ
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