Explanation Given: The diameter of container ( D ) is 150 mm. The diameter of pipe ( d ) is 50 mm. Depth of the pipe is 300 mm The volume of pipe ( V ) is 0.00075 m 3 Diameter of the container ( d ) is 150 mm . Calculation: Calculate the height of kerosene ( h k e ) using the relation. h k e = h + h g l h k e = h + ( 300 mm × 10 − 3 ) m = h + 0.3 Here, the height of kerosene above glycerin is h and the height of glycerin from point B to point C is h g l . Refer Appendix A, “Physical Properties of Liquids at Standard Atmospheric Pressure 101.3 kPa, and 20 ° C (SI Units)”. The density of kerosene ( ρ k e ) as 814 kg / m 3 The density of glycerin ( ρ g l ) as 1 , 260 kg / m 3 . Calculate the unit weight of kerosene ( γ k e ) . γ k e = ρ k e g γ k e = 814 g Calculate the unit weight of glycerin ( γ g l ) . γ g l = ρ g l g γ g l = 1 , 260 g The pressure at point C ( p C ) and point A ( p A ) are equal to atmospheric pressure ( p a t m ) . p A = p C = p a t m Draw the schematic diagram of the container and pipe and show the dimensions as in Figure (1).

2nd Edition

ISBN: 8220106714287

Author: HIBBELER

Publisher: PEARSON

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Chapter 2, Problem 27P

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The volume of kerosene which can be poured into the pipe

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