Applied Fluid Mechanics: Global Edition
7th Edition
ISBN: 9781292019611
Author: Robert Mott
Publisher: Pearson Higher Education
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Chapter 2, Problem 2.76PP
To determine
The equivalent viscosity of oil in SUS.
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Complete the following problems. Show your work/calculations, save as.pdf and upload to the
assignment in Blackboard.
missing information to present a completed program. (Hint: You may have to look up geometry
for the center drill and standard 0.5000 in twist drill to know the required depth to drill).
1. What are the x and y dimensions for the center position of holes 1,2, and 3 in the part shown in
Figure 26.2 (below)?
6.0000
Zero
reference
point
7118
1.0005
1.0000
1.252
Bore
6.0000
.7118
Cbore
0.2180 deep
(3 holes)
2.6563 1.9445
Figure 26.2
026022 (8lot and Drill Part)
(Setup Instructions---
(UNITS: Inches
(WORKPIECE NAT'L SAE 1020 STEEL
(Workpiece: 3.25 x 2.00 x0.75 in. Plate
(PRZ Location 054:
'
XY 0.0 - Upper Left of Fixture
TOP OF PART 2-0
(Tool List
( T02 0.500 IN 4 FLUTE FLAT END MILL
#4 CENTER DRILL
Dashed line indicates-
corner of original stock
( T04
T02
3.000 diam. slot
0.3000 deep.
0.3000 wide
Intended toolpath-tangent-
arc entry and exit sized to
programmer's judgment…
A program to make the part depicted in Figure 26.A has been created, presented in figure 26.B, but some information still needs to be filled in. Compute the tool locations, depths, and other missing information to present a completed program. (Hint: You may have to look up geometry for the center drill and standard 0.5000 in twist drill to know the required depth to drill).
We consider a laminar flow induced by an impulsively started infinite flat
plate. The y-axis is normal to the plate. The x- and z-axes form a plane parallel
to the plate. The plate is defined by y = 0. For time t <0, the plate and the flow
are at rest. For t≥0, the velocity of the plate is parallel to the 2-coordinate;
its value is constant and equal to uw. At infinity, the flow is at rest. The flow
induced by the motion of the plate is independent of z.
(a) From the continuity equation, show that v=0 everywhere in the flow and
the resulting momentum equation is
მu
Ət
Note that this equation has the form of a diffusion equation (the same form as
the heat equation).
(b) We introduce the new variables T, Y and U such that
T=kt, Y=k/2y, U = u
where k is an arbitrary constant. In the new system of variables, the solution
is U(Y,T). The solution U(Y,T) is expressed by a function of Y and T and the
solution u(y, t) is expressed by a function of y and t. Show that the functions are
identical.…
Chapter 2 Solutions
Applied Fluid Mechanics: Global Edition
Ch. 2 - Define shear stress as it applies to a moving...Ch. 2 - Define velocity gradient.Ch. 2 - State the mathematical definition for dynamic...Ch. 2 - Which would have the greater dynamic viscosity, a...Ch. 2 - State the standard units for dynamic viscosity in...Ch. 2 - State the standard units for dynamic viscosity in...Ch. 2 - State the equivalent units for poise in terms of...Ch. 2 - Why are the units of poise and centipoise...Ch. 2 - State the mathematical definition for kinematic...Ch. 2 - State the standard units for kinematic viscosity...
Ch. 2 - State the standard units for kinematic viscosity...Ch. 2 - State the equivalent units for stoke in terms of...Ch. 2 - Why are the units of stoke and centistoke...Ch. 2 - Define a Newtonian fluid.Ch. 2 - Define a non-Newtonian fluid.Ch. 2 - Give five examples of Newtonian fluids.Ch. 2 - Give four examples of the types of fluids that are...Ch. 2 - Appendix D iS gives dynamic viscosity for a...Ch. 2 - Appendix D gives dynamic viscosity for a variety...Ch. 2 - Appendix D gives dynamic viscosity for a variety...Ch. 2 - Appendix D iS gives dynamic viscosity for a...Ch. 2 - Appendix D iS gives dynamic viscosity for a...Ch. 2 - Appendix D gives dynamic viscosity for a variety...Ch. 2 - Appendix D gives dynamic viscosity for a variety...Ch. 2 - Appendix D gives dynamic viscosity for a variety...Ch. 2 - Appendix D gives dynamic viscosity for a variety...Ch. 2 - Appendix D gives dynamic viscosity for a variety...Ch. 2 - Appendix D gives dynamic viscosity for a variety...Ch. 2 - Appendix D gives dynamic viscosity for a variety...Ch. 2 - Appendix D gives dynamic viscosity for a variety...Ch. 2 - Appendix D gives dynamic viscosity for a variety...Ch. 2 - Appendix D gives dynamic viscosity for a variety...Ch. 2 - Appendix D gives dynamic viscosity for a variety...Ch. 2 - Appendix D gives dynamic viscosity for a variety...Ch. 2 - Appendix D gives dynamic viscosity for a variety...Ch. 2 - Appendix D gives dynamic viscosity for a variety...Ch. 2 - If you want to choose a fluid that exhibits a...Ch. 2 - Which type of viscosity measurement method uses...Ch. 2 - In the rotating-drum viscometer, describe how the...Ch. 2 - In the rotating-drum viscometer, describe how the...Ch. 2 - What measurements must be taken to determine...Ch. 2 - Define the term terminal velocity as it applies to...Ch. 2 - What measurements must be taken to determine...Ch. 2 - Describe the basic features of the Saybolt...Ch. 2 - Are the results of the Saybolt viscometer tests...Ch. 2 - Does the Saybolt viscometer produce data related...Ch. 2 - Which type of viscometer is prescribed by SAE for...Ch. 2 - Describe the difference between an SAE 20 oil and...Ch. 2 - What grades of SAE oil are suitable for...Ch. 2 - What grades of SAE oil are suitable for...Ch. 2 - If you were asked to check the viscosity of an oil...Ch. 2 - If you were asked to check the viscosity of an oil...Ch. 2 - Prob. 2.53PPCh. 2 - The viscosity of a lubricating oil is given as 500...Ch. 2 - Using the data from Table 2.5. report the minimum,...Ch. 2 - Convert a dynamic viscosity measurement of 4500 cP...Ch. 2 - Convert a kinematic viscosity measurement of 5.6...Ch. 2 - The viscosity of an oil is given as 80 SUS at...Ch. 2 - Convert a viscosity measurement of 6.5x103 Pa.s...Ch. 2 - An oil container indicates that it has a viscosity...Ch. 2 - In a falling-ball viscometer, a steel ball 1.6 mm...Ch. 2 - A capillary tube viscometer similar to that shown...Ch. 2 - In a falling-ball viscometer, a steel ball with a...Ch. 2 - A capillary type viscometer similar to that shown...Ch. 2 - A fluid has a kinematic viscosity of 15.0 mm2/s at...Ch. 2 - A fluid has a kinematic viscosity of 55.3 mm2/s at...Ch. 2 - A fluid has a kinematic viscosity of 188 mm2/s at...Ch. 2 - A fluid has a kinematic viscosity of 244 mm2/s at...Ch. 2 - A fluid has a kinematic viscosity of 153mm2/s at...Ch. 2 - A fluid has a kinematic viscosity of 205mm2/s at...Ch. 2 - An oil is tested using a Saybolt viscometer and...Ch. 2 - An oil is tested using a Saybolt viscometer and...Ch. 2 - Prob. 2.73PPCh. 2 - Prob. 2.74PPCh. 2 - An oil is tested using a Saybolt viscometer and...Ch. 2 - Prob. 2.76PPCh. 2 - Convert all of the kinematic viscosity data in...Ch. 2 - Use a spreadsheet to display the values of...
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- Part A: Suppose you wanted to drill a 1.5 in diameter hole through a piece of 1020 cold-rolled steel that is 2 in thick, using an HSS twist drill. What values if feed and cutting speed will you specify, along with an appropriate allowance? Part B: How much time will be required to drill the hole in the previous problem using the HSS drill?arrow_forward1.1 m 1.3 m B 60-mm diameter Brass 40-mm diameter Aluminum PROBLEM 2.52 - A rod consisting of two cylindrical portions AB and BC is restrained at both ends. Portion AB is made of brass (E₁ = 105 GPa, α = 20.9×10°/°C) and portion BC is made of aluminum (Ę₁ =72 GPa, α = 23.9×10/°C). Knowing that the rod is initially unstressed, determine (a) the normal stresses induced in portions AB and BC by a temperature rise of 42°C, (b) the corresponding deflection of point B.arrow_forward30 mm D = 40 MPa -30 mm B C 80 MPa PROBLEM 2.69 A 30-mm square was scribed on the side of a large steel pressure vessel. After pressurization, the biaxial stress condition at the square is as shown. For E = 200 GPa and v=0.30, determine the change in length of (a) side AB, (b) side BC, (c) diagnonal AC.arrow_forward
- Please solve in detail this problem thank youarrow_forward0,5 mm 450 mm 350 mm Bronze A = 1500 mm² E = 105 GPa प 21.6 × 10-PC Aluminum A = 1800 mm² £ = 73 GPa = a 23.2 × 10-PC PROBLEM 2.58 Knowing that a 0.5-mm gap exists when the temperature is 24°C, determine (a) the temperature at which the normal stress in the aluminum bar will be equal to -75 MPa, (b) the corresponding exact length of the aluminum bar.arrow_forward0.5 mm 450 mm -350 mm Bronze Aluminum A 1500 mm² A 1800 mm² E 105 GPa E 73 GPa K = 21.6 X 10 G < = 23.2 × 10-G PROBLEM 2.59 Determine (a) the compressive force in the bars shown after a temperature rise of 82°C, (b) the corresponding change in length of the bronze bar.arrow_forward
- The truss shown below sits on a roller at A and a pin at E. Determine the magnitudes of the forces in truss members GH, GB, BC and GC. State whether they are in tension or compression or are zero force members.arrow_forwardA weight (W) hangs from a pulley at B that is part of a support frame. Calculate the maximum possible mass of the weight if the maximum permissible moment reaction at the fixed support is 100 Nm. Note that a frictionless pin in a slot is located at C.arrow_forwardIt is the middle of a winter snowstorm. Sally and Jin take shelter under an overhang. The loading of the snow on top of the overhang is shown in the figure below. The overhang is attached to the wall at points A and B with pin supports. Another pin is at C. Determine the reactions of the pin supports at A and B. Express them in Cartesian vector form.arrow_forward
- Recall that the CWH equation involves two important assumptions. Let us investigate how these assumptions affect the accuracy of state trajectories under the control inputs optimized in (a) and (b). (c.1): Discuss the assumptions about the chief and deputy orbits that are necessary for deriving CWH.arrow_forwardPROBLEM 2.50 1.8 m The concrete post (E-25 GPa and a = 9.9 x 10°/°C) is reinforced with six steel bars, each of 22-mm diameter (E, = 200 GPa and a, = 11.7 x 10°/°C). Determine the normal stresses induced in the steel and in the concrete by a temperature rise of 35°C. 6c " 0.391 MPa 240 mm 240 mm 6₁ = -9.47 MPaarrow_forwardFor some viscoelastic polymers that are subjected to stress relaxation tests, the stress decays with time according to a(t) = a(0) exp(-4) (15.10) where σ(t) and o(0) represent the time-dependent and initial (i.e., time = 0) stresses, respectively, and t and T denote elapsed time and the relaxation time, respectively; T is a time-independent constant characteristic of the material. A specimen of a viscoelastic polymer whose stress relaxation obeys Equation 15.10 was suddenly pulled in tension to a measured strain of 0.5; the stress necessary to maintain this constant strain was measured as a function of time. Determine E (10) for this material if the initial stress level was 3.5 MPa (500 psi), which dropped to 0.5 MPa (70 psi) after 30 s.arrow_forward
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