Chapter 2, Problem 2.6P

Interpretation Introduction

(a)

Interpretation:

The number of atoms of aluminum contained in one square inch of the foil is to be calculated.

Concept IntroductionRelation to calculate a number of atoms contained in one square inch of the foil is given by:

  $N_{A/c}=\frac{m{N}_A}{A_{A1}}$

Where,

  $M=$ mass of aluminum

  $N_A$ = Avogadro's number

  $A_A$ = Atomic mass of aluminum

Interpretation Introduction

(b)

Interpretation:

The number of atoms per $c{m}^3$ inlead and lithium should be calculated and compared.

Concept Introduction:

By using properties of the crystal structure, the number of atoms per $c{m}^3$ can be determined:

  $N_{A/c}=\frac{\rho \times N_A}{Atomicmass}$ ------------(1)

Where,

  $\begin{array}{l}\rho =densityofelement\\ N_A=Avogadorsnumber\end{array}$