ENGINEERING ECONOMY W/CNCT ACCESS
ENGINEERING ECONOMY W/CNCT ACCESS
8th Edition
ISBN: 9781260933505
Author: Blank
Publisher: MCG
Question
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Chapter 2, Problem 26P

(1):

To determine

Calculate future value factor to the annual value.

(1):

Expert Solution
Check Mark

Explanation of Solution

Option (a):

Interest rate (i) is 19% and time period (n) is 20.

The future value factor to the annual value (FA) through linear interpolate can be calculated as follows. The interest rate lies between (i1)18% and (i2) 20%.

FA=(1+i1)n1i1((ii1)100(i2i1)100((1+i1)n1i1(1+i2)n1i2))=(1+0.18)2010.18((0.0190.18)100(0.20.18)100((1+0.18)2010.18(1+0.2)2010.2))=27.39310.18((0.01)100(0.02)100(27.39310.1838.337610.2))=146.6278(12(146.6278186.688))=146.6278(12(146.6278186.688))=146.6278(20.301)=166.6579

The future value factor to the annual value is 166.6579.

Option (b):

The future value factor to the annual value (FA) through formula can be calculated as follows:

FA=(1+i)n1i=(1+0.19)2010.19=32.429410.19=165.4179

The future value factor to the annual value is 165.4749.

Option (c):

The future value factor to the annual value (FA) through spreadsheet can be done as follows:

=-FV(i,n,,1)

=-FV(19%,20,,1) This function gives the value of 165.41802.

(2):

To determine

Calculate present value factor to the equivalent annual value.

(2):

Expert Solution
Check Mark

Explanation of Solution

Option (a):

Interest rate (i) is 26% and time period (n) is 15.

The present value factor to the equivalent annual value (PA) through linear interpolate can be calculated as follows. The interest rate is lies between (i1) 25% and (i2) 27%.

PA=(1+i1)n1i1(1+i1)n((ii1)100(i2i1)100((1+i1)n1i1(1+i1)n(1+i2)n1i2(1+i2)n))=(1+0.25)1510.25(1+0.25)15((0.260.25)100(0.270.25)100((1+0.25)1510.25(1+0.25)15(1+0.27)1510.27(1+0.27)15))=28.421710.25(28.4217)((0.01)100(0.02)100(28.421710.25(28.4217)36.062510.27(36.0625)))=27.42177.1054(12(27.42177.105435.06259.7369))=3.8593(0.5(3.85933.601))=3.8593(0.1292)=3.7301

The present value factor to the equivalent annual value is 3.7301.

Option (b):

The present value factor to the equivalent annual value (PA) through formula can be calculated as follows:

PA=(1+i)n1i(1+i)n=(1+0.26)1510.26(1+0.26)15=32.030110.26(32.0301)=31.03018.3278=3.7261

The present value factor to the equivalent annual value is 3.7261.

Option (c):

The present value factor to the equivalent annual value (PA) through spreadsheet can be done as follows:

=-PV(i,n,,1)

=-PV267%,15,,1) This function gives the value of 3.72607.

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As indicated in the attached image, U.S. earnings for high- and low-skill workers as measured by educational attainment began diverging in the 1980s. The remaining questions in this problem set use the model for the labor market developed in class to walk through potential explanations for this trend.  1. Assume that there are just two types of workers, low- and high-skill. As a result, there are two labor markets: supply and demand for low-skill workers and supply and demand for high-skill workers. Using two carefully drawn labor-market figures, show that an increase in the demand for high skill workers can explain an increase in the relative wage of high-skill workers.  2. Using the same assumptions as in the previous question, use two carefully drawn labor-market figures to show that an increase in the supply of low-skill workers can explain an increase in the relative wage of high-skill workers.

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ENGINEERING ECONOMY W/CNCT ACCESS

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