Explanation Given data: Time taken by the car to travel first 15 m is t = 2.4 s . Formula used: The following kinematic equations are used in this problem: Δ x = u t + 1 2 a t 2 (1) v 2 − u 2 = 2 a ( Δ x ) (2) Here, u is the initial velocity, v is the final velocity, Δ x is the displacement, t is the time interval, and a is the acceleration. Explanation: Since the car is started from its rest position, the initial velocity of the car is zero ( u = 0 ) for its first 15 m travel. Therefore, substitute 0 for initial velocity u in equation (1) to get reduced expression for displacement. Δ x = ( 0 ) t + 1 2 a t 2 Δ x = 1 2 a t 2 (3) Rearrange equation (3) to find the acceleration of the car, a = 2 s t 2 (4) Substitute 15 m for Δ x and 2.4 s for time t in equation (4), a = 2 ( 15 m ) ( 2.4 s ) 2 a = 5.21 m / s 2 Substitute 5.21 m / s 2 for acceleration a , 15 m for displacement Δ x , and 0 for initial velocity u in equation (2) to get final velocity of car at the end of first 15 m travel

College Physics: A Strategic Approach (4th Edition)

4th Edition

ISBN: 9780134609034

Author: Randall D. Knight (Professor Emeritus), Brian Jones, Stuart Field

Publisher: PEARSON

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Chapter 2, Problem 26MCQ

To determine

The time taken by the car to travel next 15 m.

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College Physics: A Strategic Approach (4th Edition)

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