Explanation Given data: The simplified velocity graph for Olympic sprinter Carl Lewis starting a 100 m dash is shown in Figure P2.25. Formula used: Write the expression for acceleration. a x = Δ v x Δ t (1) Here, Δ v x is change in velocity, and Δ t is time interval. Explanation: From Figure, the velocity graph first increasing slope from time interval 0 s − 0.9 s , second increasing slope from time interval 0.9 s − 2.4 s and third increasing slope from time interval 2.4 s − 3.5 s Modify Figure P2.25 as shown in Figure 1. Find the value of Δ v x in time interval between 0 s − 0.9 s . Δ v ( 0 s − 0.9 s ) = v 0.9 − v 0 = 5.5 m s − 0 m s = 5.5 m s Find the value of Δ t in time interval between 0 s − 0.9 s . Δ t ( 0 s − 0.9 s ) = t 0.9 − t 0 = 0.9 s − 0 s = 0.9 s Modify equation (1) as follows. a ( A ) = Δ v ( 0 s − 0.9 s ) Δ t ( 0 s − 0.9 s ) Substitute 5.5 m s for Δ v ( 0 s − 0.9 s ) and 0.9 s for Δ t ( 0 s − 0.9 s ) , a ( A ) = 5.5 m s 0.9 s = 6.1 m s 2 Find the value of Δ v x in time interval between 0.9 s − 2.4 s . Δ v ( 0.9 s − 2.4 s ) = v 2.4 − v 0.9 = 9.3 m s − 5.5 m s = 3.8 m s Find the value of Δ t in time interval between 0.9 s − 2.4 s . Δ t ( 0.9 s − 2.4 s ) = t 2.4 − t 0.9 = 2.4 s − 0

4th Edition

ISBN: 8220106755235

Author: Field

Publisher: PEARSON

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Question

Chapter 2, Problem 25P

To determine

To estimate: The acceleration during interval A , the acceleration during interval B and the acceleration during interval C.

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Chapter 2, Problem 24P

Chapter 2, Problem 26P

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