(a)
Interpretation:
Formula for rubidium nitrate has to be written.
Concept Introduction:
The nomenclature of inorganic compounds involves following rules:
- The prefixes on each atom indicates the number of that atoms in the compound.
- The number written on the subscript of the anion is numerically equal to the charge on the cation and vice versa.
- Subscripts are discarded when the numerical charge on cation and anion are equal.
- When a metal has more than one positive oxidation state, its lowest oxidation number has name of the metal ion ending with ‘ous’ and highest oxidation number has name of the metal ion ending with ‘ic’. This rule is applicable when oxidation number of metal is not more than three.
- If a metal ion has multiple number of oxidation states more than three, then Roman numeral has to be used within square brackets to indicate the oxidation number of metal ion.
- Nomenclature of binary acids and oxoacids are not similar. Binary acids are named based on the non-metal atom present in them. Oxoacids are named on the basis of polyatomic anion present in them.
(a)
Answer to Problem 2.59QP
Formula for rubidium nitrite is written as
Explanation of Solution
Nitrite is
(b)
Interpretation:
Formula for Potassium sulfide has to be written.
Concept Introduction:
Refer to part (a)
(b)
Answer to Problem 2.59QP
Formula for Potassium sulfide is written as
Explanation of Solution
Sulfide is
(c)
Interpretation:
Formula for Sodium hydrogen sulfide has to be written.
Concept Introduction:
Refer to part (a)
(c)
Answer to Problem 2.59QP
Formula for Sodium hydrogen sulfide is written as
Explanation of Solution
Hydrogen sulfide is
(d)
Interpretation:
Formula for the given compound has to be written.
Concept Introduction:
Refer to part (a)
(d)
Answer to Problem 2.59QP
Formula of the compound Magnesium phosphate is written as
Explanation of Solution
The cation and anion in Magnesium phosphate are magnesium ion
Thus the formula of the compound Magnesium phosphate is written as
(e)
Interpretation:
Formula for the given compound has to be written.
Concept Introduction:
Refer to part (a)
(e)
Answer to Problem 2.59QP
Formula of the compound Calcium hydrogen phsophate is written as
Explanation of Solution
The cation and anion in Calcium hydrogen phosphate are calcium ion
Hence the formula is
The formula can be simplified and written as the same number in subscript gets called and thus the formula of the compound Magnesium phosphate is written as
(f)
Interpretation:
Formula for the given compound has to be written.
Concept Introduction:
Refer to part (a)
(f)
Answer to Problem 2.59QP
Formula of the compound Potassium dihydrogen phosphate is written as
Explanation of Solution
With reference to table 2.3 in the text book, anions and cations formed by various elements are named.
The cation and anion in Potassium dihydrogen phosphate are potassium ion
Hence the formula is
The formula can be simplified and written as the same number in subscript gets called and thus the formula of the compound Magnesium phosphate is written as
(g)
Interpretation:
Formula for the given compound has to be written.
Concept Introduction:
Refer to part (a)
(g)
Answer to Problem 2.59QP
Formula for the compound Iodine heptafluoride is written as
Explanation of Solution
The prefix hepta means seven. Thus seven F atoms are bonded to Iodine I. Hence the formula is
(h)
Interpretation:
Formula for the given compound has to be written.
Concept Introduction:
Refer to part (a)
(h)
Answer to Problem 2.59QP
Formula for the compound Ammonium sulfate is written as
Explanation of Solution
The cation and anion in Ammonium sulfate are ammonium ion
Hence the formula is
(i)
Interpretation:
Formula for the given compound has to be written.
Concept Introduction:
Refer to part (a)
(i)
Answer to Problem 2.59QP
Formula of the compound Silver perchlorate is written as
Explanation of Solution
The cation and anion in Silver perchlorate are silver ion
Hence the formula is
(j)
Interpretation:
Formula for the given compound has to be written.
Concept Introduction:
Refer to part (a)
(j)
Answer to Problem 2.59QP
Formula of Boron trichloride is written as
Explanation of Solution
Boron trichloride is three Cl atoms bonded with Boron.
Hence the formula is
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Chapter 2 Solutions
Chemistry
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- An element (A) has 5 isotopes. The masses (and abundances) of the isotopes 46A, 47A, 48A, 50A are 4595263 u (7.25 %), 46.9518 u (6.44 %), 47.9479 u (63.72 %), and 49.9448 u (5.18 %) respectively. If the element Ahas an atomic mass of 47.87 u, and the last isotope 49A has a percent abundance in the ratio of 3.361 that of SA, what is the mass of 49A?arrow_forwardName the following ionic compounds: (a) Li2O, (b) FeCl3,(c) NaClO, (d) CaSO3, (e) Cu1OH22, (f ) Fe1NO322,(g) Ca1CH3COO22, (h) Cr21CO323, (i) K2CrO4, (j) 1NH422SO4.arrow_forward3. (a) Magnesium oxide was formed when the metal burns in air. (i) If 1.25 g of magnesium oxide contains 0.754 g of magnesium, determine the mass ratio of magnesium magnesium oxide. (ii) Calculate the weight of magnesium in 534 g of magnesium oxide.arrow_forward
- Chemistry: The Molecular ScienceChemistryISBN:9781285199047Author:John W. Moore, Conrad L. StanitskiPublisher:Cengage LearningGeneral Chemistry - Standalone book (MindTap Cour...ChemistryISBN:9781305580343Author:Steven D. Gammon, Ebbing, Darrell Ebbing, Steven D., Darrell; Gammon, Darrell Ebbing; Steven D. Gammon, Darrell D.; Gammon, Ebbing; Steven D. Gammon; DarrellPublisher:Cengage Learning