Concept explainers
(a)
To determine: The four different conjugate bases that would be formed by the deprotonation of the four different OH groups in ascorbic acid.
Interpretation: The four different conjugate bases that would be formed by the deprotonation of the four different OH groups in ascorbic acid are to be shown.
Concept introduction: The delocalization of electrons due to presence of lone pair and double bond is called resonating structure. The structure is more stable if the resonating structures are more. When an acid donates a proton the species formed is known as conjugate base and when the base accepts a proton the species formed is known as conjugate acid.
(b)
To determine: The comparison between the stabilities of the resulting conjugate bases and the most acidic OH group of ascorbic acid.
Interpretation: The stabilities of the resulting conjugate bases are to be compared and the most acidic OH group of ascorbic acid is to be predicted.
Concept introduction: The acidity and basicity of a compound is influenced by the resonance. The amount of stability depends on the delocalization of the charge through the resonance.
(c)
To determine: The comparison between the most stable conjugate bases of ascorbic acid and acetic acid and an explanation corresponding to the fact that the two compounds have similar acidities even though ascorbic acid lacks carboxylic group.
Interpretation: The most stable conjugate bases of ascorbic acid and acetic acid are to be compared and an explanation corresponding to the fact that the two compounds have similar acidities even though ascorbic acid lacks carboxylic group is to be explained.
Concept introduction: The acidity and basicity of a compound is influenced by the resonance. The amount of stability depends on the delocalization of the charge through the resonance.
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Chapter 2 Solutions
Organic Chemistry Plus Masteringchemistry With Pearson Etext, Global Edition
- Part C IN H N. Br₂ (2 equiv.) AlBr3 Draw the molecule on the canvas by choosing buttons from the Tools (for bonds and + e (×) H± 12D T EXP. L CONT. דarrow_forward9. OA. Rank the expected boiling points of the compounds shown below from highest to lowest. Place your answer appropriately in the box. Only the answer in the box will be graded. (3) points) OH OH بر بد بدید 2 3arrow_forwardThere is an instrument in Johnson 334 that measures total-reflectance x-ray fluorescence (TXRF) to do elemental analysis (i.e., determine what elements are present in a sample). A researcher is preparing a to measure calcium content in a series of well water samples by TXRF with an internal standard of vanadium (atomic symbol: V). She has prepared a series of standard solutions to ensure a linear instrument response over the expected Ca concentration range of 40-80 ppm. The concentrations of Ca and V (ppm) and the instrument response (peak area, arbitrary units) are shown below. Also included is a sample spectrum. Equation 1 describes the response factor, K, relating the analyte signal (SA) and the standard signal (SIS) to their respective concentrations (CA and CIS). Ca, ppm V, ppm SCa, arb. units SV, arb. units 20.0 10.0 14375.11 14261.02 40.0 10.0 36182.15 17997.10 60.0 10.0 39275.74 12988.01 80.0 10.0 57530.75 14268.54 100.0…arrow_forward
- A mixture of 0.568 M H₂O, 0.438 M Cl₂O, and 0.710 M HClO are enclosed in a vessel at 25 °C. H₂O(g) + C₁₂O(g) = 2 HOCl(g) K = 0.0900 at 25°C с Calculate the equilibrium concentrations of each gas at 25 °C. [H₂O]= [C₁₂O]= [HOCI]= M Σ Marrow_forwardWhat units (if any) does the response factor (K) have? Does the response factor (K) depend upon how the concentration is expressed (e.g. molarity, ppm, ppb, etc.)?arrow_forwardProvide the structure, circle or draw, of the monomeric unit found in the biological polymeric materials given below. HO OH amylose OH OH 행 3 HO cellulose OH OH OH Ho HOarrow_forward
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