Chapter 2, Problem 2.50E

Interpretation Introduction

(a)

Interpretation:

The statements for the given formula that are equivalent to Statements 1-6 is to be stated.

Concept introduction:

The chemical formula of a compound represents the type of elements present in that compound. The subscript corresponding to the element represents the number of atoms of an element present in one molecule of a compound.

Answer to Problem 2.50E

The statements that are equivalent to Statements 1-6 for ${\text{C}}_4{\text{H}}_{10}\text{O}$ are as follows:

1. There are $8\text{C}$ atom, $20\text{H}$ atoms and $2\text{O}$ atoms present in $2$ molecules of ${\text{C}}_4{\text{H}}_{10}\text{O}$.

2. There are $40\text{C}$ atom, $100\text{H}$ atoms and $10\text{O}$ atoms present in $10$ molecules of ${\text{C}}_4{\text{H}}_{10}\text{O}$.

3. There are $400\text{C}$ atom, $100\text{H}$ atoms and $100\text{O}$ atoms present in $100$ molecules of ${\text{C}}_4{\text{H}}_{10}\text{O}$.

4. There are $24.08\times {10}^{23}\text{C}$, $60.2\times {10}^{23}\text{H}$ atoms and $6.02\times {10}^{23}\text{O}$ atoms present in $6.02\times {10}^{23}$ molecules of ${\text{C}}_4{\text{H}}_{10}\text{O}$.

5. There are $4\text{mol}\text{C}$, $10\text{mol}\text{H}$ and $1\text{mole}\text{O}$ present in $1\text{mol}{\text{C}}_{\text{4}}{\text{H}}_{\text{10}}\text{O}$.

6. There is $48.04\text{g}\text{C}$, $10.00\text{g}\text{H}$ and $16.00\text{g}\text{O}$ present in $74.04\text{g}$ of ${\text{C}}_4{\text{H}}_{10}\text{O}$.

Explanation of Solution

For the given compound ethyl ether $\left({\text{C}}_4{\text{H}}_{10}\text{O}\right)$, the statements that equivalent to Statements 1-6 are as follows:

According to Statement 1, $2$ molecules of ethyl ether $\left({\text{C}}_4{\text{H}}_{10}\text{O}\right)$, contains $8\text{C}$ atoms, $20\text{H}$ atoms and $2\text{O}$ atoms.

According to Statement 2, $10$ molecules of ethyl ether $\left({\text{C}}_4{\text{H}}_{10}\text{O}\right)$, contains $40\text{C}$ atoms, $100\text{H}$ atoms and $10\text{O}$ atoms.

According to Statement 3, $100$ molecules of ethyl ether $\left({\text{C}}_4{\text{H}}_{10}\text{O}\right)$, contains $400\text{C}$ atoms, $1000\text{H}$ atoms and $100\text{O}$ atoms.

According to Statement 4, $6.02\times {10}^{23}$ molecules of ethyl ether $\left({\text{C}}_4{\text{H}}_{10}\text{O}\right)$, contains $24.08\times {10}^{23}\text{C}$, $60.2\times {10}^{23}\text{H}$ and $6.02\times {10}^{23}\text{O}$ atom.

According to Statement 5, one mole of ethyl ether $\left({\text{C}}_4{\text{H}}_{10}\text{O}\right)$, contains $4\text{mol}\text{C}$ atoms, $10\text{mol}\text{H}$ atoms, and $1\text{mole}\text{O}$ atoms.

According to Statement 6, $74.04\text{g}$ of ethyl ether $\left({\text{C}}_4{\text{H}}_{10}\text{O}\right)$, contains $48.04\text{g}\text{C}$, $10.00\text{g}\text{H}$ and $16.00\text{g}\text{O}$.

Conclusion

The statements that are equivalent to Statements 1-6 for ${\text{C}}_4{\text{H}}_{10}\text{O}$ are as follows:

1. There are $8\text{C}$ atom, $20\text{H}$ atoms and $2\text{O}$ atoms present in $2$ molecules of ${\text{C}}_4{\text{H}}_{10}\text{O}$.

2. There are $40\text{C}$ atom, $100\text{H}$ atoms and $10\text{O}$ atoms present in $10$ molecules of ${\text{C}}_4{\text{H}}_{10}\text{O}$.

3. There are $400\text{C}$ atom, $100\text{H}$ atoms and $100\text{O}$ atoms present in $100$ molecules of ${\text{C}}_4{\text{H}}_{10}\text{O}$.

4. There are $24.08\times {10}^{23}\text{C}$, $60.2\times {10}^{23}\text{H}$ atoms and $6.02\times {10}^{23}\text{O}$ atoms present in $6.02\times {10}^{23}$ molecules of ${\text{C}}_4{\text{H}}_{10}\text{O}$.

5. There are $4\text{mol}\text{C}$ atoms, $10\text{mol}\text{H}$ atoms and $1\text{mole}\text{O}$ present in $1\text{mol}{\text{C}}_{\text{4}}{\text{H}}_{\text{10}}\text{O}$.

6. There is $48.04\text{g}\text{C}$, $10.00\text{g}\text{H}$ and $16.00\text{g}\text{O}$ present in $74.04\text{g}$ of ${\text{C}}_4{\text{H}}_{10}\text{O}$.

Interpretation Introduction

(b)

Interpretation:

The statements for the given formula that are equivalent to Statements 1-6 is to be stated.

Concept introduction:

The chemical formula of a compound represents the type of elements present in that compound. The subscript corresponding to the element represents the number of atoms of an element present in one molecule of a compound.

Answer to Problem 2.50E

The statements that are equivalent to Statements 1-6 for ${\text{C}}_{\text{2}}{\text{H}}_{\text{3}}{\text{O}}_{\text{2}}\text{F}$ are as follows:

1. There are $4\text{C}$ atom, $6\text{H}$ atoms $4\text{O}$ atoms and $2\text{F}$ atoms present in $2$ molecules of ${\text{C}}_{\text{2}}{\text{H}}_{\text{3}}{\text{O}}_{\text{2}}\text{F}$.

2. There are $20\text{C}$ atoms, $30\text{H}$ atoms, $20\text{O}$ atoms and $10\text{F}$ atoms present in $10$ molecules of ${\text{C}}_{\text{2}}{\text{H}}_{\text{3}}{\text{O}}_{\text{2}}\text{F}$.

3. There are $200\text{C}$ atoms, $300\text{H}$ atoms, $200\text{O}$ atoms and $100\text{F}$ atoms present in $100$ molecules of ${\text{C}}_{\text{2}}{\text{H}}_{\text{3}}{\text{O}}_{\text{2}}\text{F}$.

4. There are $12.04\times {10}^{23}\text{C}$ atom, $18.06\times {10}^{23}\text{H}$ atoms, $12.04\times {10}^{23}\text{O}$ atoms and $6.02\times {10}^{23}\text{F}$ atoms present in $6.02\times {10}^{23}$ molecules of ${\text{C}}_{\text{2}}{\text{H}}_{\text{3}}{\text{O}}_{\text{2}}\text{F}$.

5. There are $4\text{mol}\text{C}$, $10\text{mol}\text{H}$ and $1\text{mole}\text{O}$ present in $1\text{mol}{\text{C}}_{\text{2}}{\text{H}}_{\text{3}}{\text{O}}_{\text{2}}\text{F}$.

6. There is $24.02\text{g}\text{C}$, $3.00\text{g}\text{H}$, $32.00\text{g}\text{O}$ and $19.00\text{g}\text{F}$ present in $74.04\text{g}$ of ${\text{C}}_{\text{2}}{\text{H}}_{\text{3}}{\text{O}}_{\text{2}}\text{F}$.

Explanation of Solution

For the given compound fluoroacetic acid $\left({\text{C}}_{\text{2}}{\text{H}}_{\text{3}}{\text{O}}_{\text{2}}\text{F}\right)$, the statements that are equivalent to Statements 1-6 are as follows:

According to Statement 1, $2$ molecules of fluoroacetic acid $\left({\text{C}}_{\text{2}}{\text{H}}_{\text{3}}{\text{O}}_{\text{2}}\text{F}\right)$, contains $4\text{C}$ atoms, $6\text{H}$ atoms, $4\text{O}$ atoms and $2\text{F}$ atoms.

According to Statement 2, $10$ molecules of fluoroacetic acid $\left({\text{C}}_{\text{2}}{\text{H}}_{\text{3}}{\text{O}}_{\text{2}}\text{F}\right)$, contains $20\text{C}$ atoms, $30\text{H}$ atoms, $20\text{O}$ atoms and $10\text{F}$ atoms.

According to Statement 3, $100$ molecules of fluoroacetic acid $\left({\text{C}}_{\text{2}}{\text{H}}_{\text{3}}{\text{O}}_{\text{2}}\text{F}\right)$, contains $200\text{C}$ atoms, $300\text{H}$ atoms, $200\text{O}$ atoms and $100\text{F}$ atoms.

According to Statement 4, $6.02\times {10}^{23}$ molecules of fluoroacetic acid $\left({\text{C}}_{\text{2}}{\text{H}}_{\text{3}}{\text{O}}_{\text{2}}\text{F}\right)$, contain $12.04\times {10}^{23}\text{C}$ atom, $18.06\times {10}^{23}\text{H}$ atoms, $12.04\times {10}^{23}\text{O}$ atoms and $6.02\times {10}^{23}\text{F}$ atoms.

According to Statement 5, one mole of fluoroacetic acid $\left({\text{C}}_{\text{2}}{\text{H}}_{\text{3}}{\text{O}}_{\text{2}}\text{F}\right)$, contains $2\text{mol}\text{C}$ atom, $3\text{mol}\text{H}$ atoms, $2\text{mol}\text{O}$ atoms and $1\text{mol}\text{F}$ atoms.

According to Statement 1, $78.02\text{g}$ of fluoroacetic acid $\left({\text{C}}_{\text{2}}{\text{H}}_{\text{3}}{\text{O}}_{\text{2}}\text{F}\right)$, contains $24.02\text{g}\text{C}$, $3.00\text{g}\text{H}$ atoms, $32.00\text{g}\text{O}$ atoms and $19.00\text{g}\text{F}$ atoms.

Conclusion

The statements that are equivalent to Statements 1-6 for ${\text{C}}_{\text{2}}{\text{H}}_{\text{3}}{\text{O}}_{\text{2}}\text{F}$ are as follows:

1. There are $4\text{C}$ atom, $6\text{H}$ atoms $4\text{O}$ atoms and $2\text{F}$ atoms present in $2$ molecules of ${\text{C}}_{\text{2}}{\text{H}}_{\text{3}}{\text{O}}_{\text{2}}\text{F}$.

2. There are $20\text{C}$ atoms, $30\text{H}$ atoms, $20\text{O}$ atoms and $10\text{F}$ atoms present in $10$ molecules of ${\text{C}}_{\text{2}}{\text{H}}_{\text{3}}{\text{O}}_{\text{2}}\text{F}$.

3. There are $200\text{C}$ atoms, $300\text{H}$ atoms, $200\text{O}$ atoms and $100\text{F}$ atoms present in $100$ molecules of ${\text{C}}_{\text{2}}{\text{H}}_{\text{3}}{\text{O}}_{\text{2}}\text{F}$.

4. There are $12.04\times {10}^{23}\text{C}$ atom, $18.06\times {10}^{23}\text{H}$ atoms, $12.04\times {10}^{23}\text{O}$ atoms and $6.02\times {10}^{23}\text{F}$ atoms present in $6.02\times {10}^{23}$ molecules of ${\text{C}}_{\text{2}}{\text{H}}_{\text{3}}{\text{O}}_{\text{2}}\text{F}$.

5. There are $4\text{mol}\text{C}$, $10\text{mol}\text{H}$ and $1\text{mole}\text{O}$ present in $1\text{mol}{\text{C}}_{\text{2}}{\text{H}}_{\text{3}}{\text{O}}_{\text{2}}\text{F}$.

6. There is $24.02\text{g}\text{C}$, $3.00\text{g}\text{H}$, $32.00\text{g}\text{O}$ and $19.00\text{g}\text{F}$ present in $74.04\text{g}$ of ${\text{C}}_{\text{2}}{\text{H}}_{\text{3}}{\text{O}}_{\text{2}}\text{F}$.

Interpretation Introduction

(c)

Interpretation:

The statements for the given formula that are equivalent to Statements 1-6 is to be stated.

Concept introduction:

The chemical formula of a compound represents the type of elements present in that compound. The subscript corresponding to the element represents the number of atoms of an element present in one molecule of a compound.

Answer to Problem 2.50E

The statements that are equivalent to Statements 1-6 for ${\text{C}}_{\text{6}}{\text{H}}_7\text{N}$ are as follows:

1. There are $12\text{C}$ atom, $14\text{H}$ atoms and $2\text{N}$ atoms present in $2$ molecules of ${\text{C}}_{\text{6}}{\text{H}}_7\text{N}$.

2. There are $60\text{C}$ atom, $70\text{H}$ atoms and $10\text{N}$ atoms present in $10$ molecules of ${\text{C}}_{\text{6}}{\text{H}}_7\text{N}$.

3. There are $600\text{C}$ atoms, $700\text{H}$ atoms and $100\text{N}$ atoms present in $100$ molecules of ${\text{C}}_{\text{6}}{\text{H}}_7\text{N}$.

4. There are $36.12\times {10}^{23}\text{C}$ atoms $42.14\times {10}^{23}\text{H}$, atoms and $6.02\times {10}^{23}\text{N}$ atoms present in $6.02\times {10}^{23}$ molecules of ${\text{C}}_{\text{6}}{\text{H}}_7\text{N}$.

5. There are $6\text{mol}\text{C}$ atoms, $7\text{mol}\text{H}$ atoms, and $1\text{mole}\text{N}$ atoms present in $1\text{mol}{\text{C}}_{\text{6}}{\text{H}}_7\text{N}$.

6. There is $72.06\text{g}\text{C}$, $7.00\text{g}\text{H}$ and $14.00\text{g}\text{N}$ present in $96.06\text{g}$ of ${\text{C}}_{\text{6}}{\text{H}}_7\text{N}$.

Explanation of Solution

For the given compound aniline $\left({\text{C}}_{\text{6}}{\text{H}}_7\text{N}\right)$, the statements that are equivalent to Statements 1-6 are as follows:

According to Statement 1, $2$ molecules of aniline $\left({\text{C}}_{\text{6}}{\text{H}}_7\text{N}\right)$, contain $12\text{C}$ atoms, $14\text{H}$ atoms and $2\text{N}$ atoms.

According to Statement 2, $10$ molecules of aniline $\left({\text{C}}_{\text{6}}{\text{H}}_7\text{N}\right)$, contain $60\text{C}$ atoms, $70\text{H}$ atoms and $10\text{N}$ atoms.

According to Statement 3, $100$ molecules of aniline $\left({\text{C}}_{\text{6}}{\text{H}}_7\text{N}\right)$, contain $600\text{C}$ atoms, $700\text{H}$ atoms and $100\text{N}$ atoms.

According to Statement 4, $6.02\times {10}^{23}$ molecules of aniline $\left({\text{C}}_{\text{6}}{\text{H}}_7\text{N}\right)$, contain $36.12\times {10}^{23}\text{C}$ atoms $42.14\times {10}^{23}\text{H}$ atoms and $6.02\times {10}^{23}\text{N}$ atoms.

According to Statement 5, one mole of aniline $\left({\text{C}}_{\text{6}}{\text{H}}_7\text{N}\right)$, contain $6\text{mol}\text{C}$ atoms, $7\text{mol}\text{H}$ atoms, and $1\text{mole}\text{N}$ atoms.

According to Statement 6, $96.06\text{g}$ of aniline $\left({\text{C}}_{\text{6}}{\text{H}}_7\text{N}\right)$, contain $72.06\text{g}\text{C}$, $7.00\text{g}\text{H}$ and $14.00\text{g}\text{N}$.

Conclusion

The statements equivalent to Statements 1-6 for ${\text{C}}_{\text{6}}{\text{H}}_7\text{N}$ are as follows:

1. There are $12\text{C}$ atom, $14\text{H}$ atoms and $2\text{N}$ atoms present in $2$ molecules of ${\text{C}}_{\text{6}}{\text{H}}_7\text{N}$.

2. There are $60\text{C}$ atom, $70\text{H}$ atoms and $10\text{N}$ atoms present in $10$ molecules of ${\text{C}}_{\text{6}}{\text{H}}_7\text{N}$.

3. There are $600\text{C}$ atoms, $700\text{H}$ atoms and $100\text{N}$ atoms present in $100$ molecules of ${\text{C}}_{\text{6}}{\text{H}}_7\text{N}$.

4. There are $36.12\times {10}^{23}\text{C}$ atoms $42.14\times {10}^{23}\text{H}$, atoms and $6.02\times {10}^{23}\text{N}$ atoms present in $6.02\times {10}^{23}$ molecules of ${\text{C}}_{\text{6}}{\text{H}}_7\text{N}$.

5. There are $6\text{mol}\text{C}$ atoms, $7\text{mol}\text{H}$ atoms, and $1\text{mole}\text{N}$ atoms present in $1\text{mol}{\text{C}}_{\text{6}}{\text{H}}_7\text{N}$.

6. There is $72.06\text{g}\text{C}$, $7.00\text{g}\text{H}$ and $14.00\text{g}\text{N}$ present in $96.06\text{g}$ of ${\text{C}}_{\text{6}}{\text{H}}_7\text{N}$.