Chapter 2, Problem 2.48QP

(a)

Interpretation Introduction

Interpretation:

The given compound $KClO$ has to be named.

Concept Introduction:

Generally the ionic compound consists of cation and anion.

Cation: When electrons are removed from the atom that results to form positively charged ion called cation.

Anion: Addition of electron to atom results to form negatively charged ion called anion.

The nomenclature of inorganic compounds involves following rules:

• Generally many ionic compounds are binary in which the metal cations are named first which then followed by naming nonmetallic anion.
• In ionic compound the metal cations generally hold their metal name itself and the metal anions hold their respective metal name with suffix $\text{"-ide"}$ with it.
• The prefixes on each atom indicate the number of those atoms in the compound.
• The number written on the subscript of the anion is numerically equal to the charge on the cation and vice versa.
• Subscripts are discarded when the numerical charge on cation and anion are equal.
• When a metal has more than one positive oxidation state, its lowest oxidation number has name of the metal ion ending with ‘ous’ and highest oxidation number has name of the metal ion ending with ‘ic’. This rule is applicable when oxidation number of metal is not more than three.
• If a metal ion has multiple numbers of oxidation states more than three, then Roman numeral has to be used within square brackets to indicate the oxidation number of metal ion.
• Nomenclature of binary acids and oxoacids are not similar. Binary acids are named based on the non-metal atom present in them. Oxoacids are named on the basis of polyatomic anion present in them.
• Naming binary molecular compounds is also similar to binary ionic compounds.
• The first element is named as such while second element is added with prefix which describes the number of respective atoms present.

Answer to Problem 2.48QP

The given compound $KClO$ is named as Potassium hypochlorite.

Explanation of Solution

$KClO$ has potassium $K$, chlorine $Cl$ and oxygen $O$ atoms. Cation of the compound is $K^{+}$ and anion of the compound is $Cl{O}^{-}$. With reference to table 2.3 in the text book, their names are potassium ion and chlorate ion respectively. Hence the compound is named as Potassium hypochlorite since hypochlorite is polyatomic ion which has one less oxygen atom with it compared to chlorite ion –$Cl{O}_2^{-}$.

(b)

Interpretation Introduction

Interpretation:

The given compound $A{g}_{2}C{O}_3$ has to be named.

Concept Introduction:

Generally the ionic compound consists of cation and anion.

Cation: When electrons are removed from the atom that results to form positively charged ion called cation.

Anion: Addition of electron to atom results to form negatively charged ion called anion.

The nomenclature of inorganic compounds involves following rules:

• For ionic compounds first, metal cations are named first which then followed by nonmetallic anion.
• In ionic compound the metal cations generally hold their metal name itself and the metal anions hold their respective metal name with suffix $\text{"-ide"}$ with it.
• The prefixes on each atom indicate the number of those atoms in the compound.
• The number written on the subscript of the anion is numerically equal to the charge on the cation and vice versa.
• Subscripts are discarded when the numerical charge on cation and anion are equal.
• When a metal has more than one positive oxidation state, its lowest oxidation number has name of the metal ion ending with ‘ous’ and highest oxidation number has name of the metal ion ending with ‘ic’. This rule is applicable when oxidation number of metal is not more than three.
• If a metal ion has multiple numbers of oxidation states more than three, then Roman numeral has to be used within square brackets to indicate the oxidation number of metal ion.
• Nomenclature of binary acids and oxoacids are not similar. Binary acids are named based on the non-metal atom present in them. Oxoacids are named on the basis of polyatomic anion present in them.
• Naming binary molecular compounds is also similar to binary ionic compounds.
• The first element is named as such while second element is added with prefix which describes the number of respective atoms present.

Answer to Problem 2.48QP

The given compound $A{g}_{2}C{O}_3$ is named as Silver carbonate.

Explanation of Solution

With reference to rules, anions and cations formed by various elements are named.

$A{g}_{2}C{O}_3$ has cation $A{g}^{+}$ and anion $C{O}_3^{2-}$. Their names are silver ion and carbonate ion. Hence the compound is named as silver carbonate.

(c)

Interpretation Introduction

Interpretation:

The given compound $FeC{l}_2$ has to be named.

Concept Introduction:

The nomenclature of inorganic compounds involves following rules:

Generally the ionic compound consists of cation and anion.

Cation: When electrons are removed from the atom that results to form positively charged ion called cation.

Anion: Addition of electron to atom results to form negatively charged ion called anion.

The nomenclature of inorganic compounds involves following rules:

• For ionic compounds first, metal cations are named first which then followed by nonmetallic anion.
• In ionic compound the metal cations generally hold their metal name itself and the metal anions hold their respective metal name with suffix $\text{"-ide"}$ with it.
• The prefixes on each atom indicate the number of those atoms in the compound.
• The number written on the subscript of the anion is numerically equal to the charge on the cation and vice versa.
• Subscripts are discarded when the numerical charge on cation and anion are equal.
• When a metal has more than one positive oxidation state, its lowest oxidation number has name of the metal ion ending with ‘ous’ and highest oxidation number has name of the metal ion ending with ‘ic’. This rule is applicable when oxidation number of metal is not more than three.
• If a metal ion has multiple numbers of oxidation states more than three, then Roman numeral has to be used within square brackets to indicate the oxidation number of metal ion.
• Nomenclature of binary acids and oxoacids are not similar. Binary acids are named based on the non-metal atom present in them. Oxoacids are named on the basis of polyatomic anion present in them.
• Naming binary molecular compounds is also similar to binary ionic compounds.
• The first element is named as such while second element is added with prefix which describes the number of respective atoms present.

Answer to Problem 2.48QP

The given compound $FeC{l}_2$ is named as Iron $\left(II\right)$ chloride.

Explanation of Solution

With reference to rules, anions and cations formed by various elements are named.

The cation and anion in $FeC{l}_2$ are $F{e}^{2+}$ and $C{l}^{-}$ respectively. Their names are iron ion and chloride ion respectively. The charge of iron ion is $+2$ which has to be included in name in roman numerals.

Therefore, compound is named as iron $\left(II\right)$ chloride.

(d)

Interpretation Introduction

Interpretation:

The given compound $KMn{O}_4$ has to be named.

Concept Introduction:

Generally the ionic compound consists of cation and anion.

Cation: When electrons are removed from the atom that results to form positively charged ion called cation.

Anion: Addition of electron to atom results to form negatively charged ion called anion.

The nomenclature of inorganic compounds involves following rules:

• For ionic compounds first, metal cations are named first which then followed by nonmetallic anion.
• In ionic compound the metal cations generally hold their metal name itself and the metal anions hold their respective metal name with suffix $\text{"-ide"}$ with it.
• The prefixes on each atom indicate the number of those atoms in the compound.
• The number written on the subscript of the anion is numerically equal to the charge on the cation and vice versa.
• Subscripts are discarded when the numerical charge on cation and anion are equal.
• When a metal has more than one positive oxidation state, its lowest oxidation number has name of the metal ion ending with ‘ous’ and highest oxidation number has name of the metal ion ending with ‘ic’. This rule is applicable when oxidation number of metal is not more than three.
• If a metal ion has multiple numbers of oxidation states more than three, then Roman numeral has to be used within square brackets to indicate the oxidation number of metal ion.
• Nomenclature of binary acids and oxoacids are not similar. Binary acids are named based on the non-metal atom present in them. Oxoacids are named on the basis of polyatomic anion present in them.
• Naming binary molecular compounds is also similar to binary ionic compounds.
• The first element is named as such while second element is added with prefix which describes the number of respective atoms present.

Answer to Problem 2.48QP

The given compound $KMn{O}_4$ is named as Potassium permanganate.

Explanation of Solution

With reference to rules, anions and cations formed by various elements are named.

The cation and anion in $KMn{O}_4$ are $K^{+}$ and $Mn{O}_4^{-}$ respectively. Their names are potassium ion and permanganate ion respectively.

The compound is named as potassium permanganate.

(e)

Interpretation Introduction

Interpretation:

The given compound $CsCl{O}_3$ has to be named.

Concept Introduction:

Generally the ionic compound consists of cation and anion.

Cation: When electrons are removed from the atom that results to form positively charged ion called cation.

Anion: Addition of electron to atom results to form negatively charged ion called anion.

The nomenclature of inorganic compounds involves following rules:

• For ionic compounds first, metal cations are named first which then followed by nonmetallic anion.
• In ionic compound the metal cations generally hold their metal name itself and the metal anions hold their respective metal name with suffix $\text{"-ide"}$ with it.
• The prefixes on each atom indicate the number of those atoms in the compound.
• The number written on the subscript of the anion is numerically equal to the charge on the cation and vice versa.
• Subscripts are discarded when the numerical charge on cation and anion are equal.
• When a metal has more than one positive oxidation state, its lowest oxidation number has name of the metal ion ending with ‘ous’ and highest oxidation number has name of the metal ion ending with ‘ic’. This rule is applicable when oxidation number of metal is not more than three.
• If a metal ion has multiple numbers of oxidation states more than three, then Roman numeral has to be used within square brackets to indicate the oxidation number of metal ion.
• Nomenclature of binary acids and oxoacids are not similar. Binary acids are named based on the non-metal atom present in them. Oxoacids are named on the basis of polyatomic anion present in them.
• Naming binary molecular compounds is also similar to binary ionic compounds.
• The first element is named as such while second element is added with prefix which describes the number of respective atoms present.

Answer to Problem 2.48QP

The given compound $CsCl{O}_3$ is named as Cesium chlorate.

Explanation of Solution

With reference to rules, anions and cations formed by various elements are named.

The cation and anion in $CsCl{O}_3$ are $C{s}^{+}$ and $Cl{O}_3^{-}$ respectively. Their names are cesium ion and chlorate ion respectively.

The compound is named as cesium chlorate.

(f)

Interpretation Introduction

Interpretation:

The given compound $HIO$ has to be named.

Concept Introduction:

Generally the ionic compound consists of cation and anion.

Cation: When electrons are removed from the atom that results to form positively charged ion called cation.

Anion: Addition of electron to atom results to form negatively charged ion called anion.

The nomenclature of inorganic compounds involves following rules:

• For ionic compounds first, metal cations are named first which then followed by nonmetallic anion.
• In ionic compound the metal cations generally hold their metal name itself and the metal anions hold their respective metal name with suffix $\text{"-ide"}$ with it.
• The prefixes on each atom indicate the number of those atoms in the compound.
• The number written on the subscript of the anion is numerically equal to the charge on the cation and vice versa.
• Subscripts are discarded when the numerical charge on cation and anion are equal.
• When a metal has more than one positive oxidation state, its lowest oxidation number has name of the metal ion ending with ‘ous’ and highest oxidation number has name of the metal ion ending with ‘ic’. This rule is applicable when oxidation number of metal is not more than three.
• If a metal ion has multiple numbers of oxidation states more than three, then Roman numeral has to be used within square brackets to indicate the oxidation number of metal ion.
• Nomenclature of binary acids and oxoacids are not similar. Binary acids are named based on the non-metal atom present in them. Oxoacids are named on the basis of polyatomic anion present in them.
• Naming binary molecular compounds is also similar to binary ionic compounds.
• The first element is named as such while second element is added with prefix which describes the number of respective atoms present.

Answer to Problem 2.48QP

The given compound $HIO$ is named as Hypoiodous acid.

Explanation of Solution

With reference to rules, anions and cations formed by various elements are named.

Oxoacids are named on the basis of polyatomic anion present in them. The polyatomic anion in $HIO$ is $I{O}^{-}$ and its name is hypoiodous. Name of the compound is hypoiodous acid.

(g)

Interpretation Introduction

Interpretation:

The given compound $FeO$ has to be named.

Concept Introduction:

Generally the ionic compound consists of cation and anion.

Cation: When electrons are removed from the atom that results to form positively charged ion called cation.

Anion: Addition of electron to atom results to form negatively charged ion called anion.

The nomenclature of inorganic compounds involves following rules:

• For ionic compounds first, metal cations are named first which then followed by nonmetallic anion.
• In ionic compound the metal cations generally hold their metal name itself and the metal anions hold their respective metal name with suffix $\text{"-ide"}$ with it.
• The prefixes on each atom indicate the number of those atoms in the compound.
• The number written on the subscript of the anion is numerically equal to the charge on the cation and vice versa.
• Subscripts are discarded when the numerical charge on cation and anion are equal.
• When a metal has more than one positive oxidation state, its lowest oxidation number has name of the metal ion ending with ‘ous’ and highest oxidation number has name of the metal ion ending with ‘ic’. This rule is applicable when oxidation number of metal is not more than three.
• If a metal ion has multiple numbers of oxidation states more than three, then Roman numeral has to be used within square brackets to indicate the oxidation number of metal ion.
• Nomenclature of binary acids and oxoacids are not similar. Binary acids are named based on the non-metal atom present in them. Oxoacids are named on the basis of polyatomic anion present in them.
• Naming binary molecular compounds is also similar to binary ionic compounds.
• The first element is named as such while second element is added with prefix which describes the number of respective atoms present.

Answer to Problem 2.48QP

The given compound $FeO$ is named as Iron $\left(II\right)$ oxide.

Explanation of Solution

With reference to rules, anions and cations formed by various elements are named.

The cation and anion in $FeO$ are $F{e}^{2+}$ and $O_2^{-}$ respectively. Their names are iron ion and oxide ion respectively. The charge of iron ion is $+2$ which have to be included as roman numerals.

The compound is named as Iron $\left(II\right)$ oxide.

(h)

Interpretation Introduction

Interpretation:

The given compound $F{e}_2{O}_3$ has to be named.

Concept Introduction:

Generally the ionic compound consists of cation and anion.

Cation: When electrons are removed from the atom that results to form positively charged ion called cation.

Anion: Addition of electron to atom results to form negatively charged ion called anion.

The nomenclature of inorganic compounds involves following rules:

• For ionic compounds first, metal cations are named first which then followed by nonmetallic anion.
• In ionic compound the metal cations generally hold their metal name itself and the metal anions hold their respective metal name with suffix $\text{"-ide"}$ with it.
• The prefixes on each atom indicate the number of those atoms in the compound.
• The number written on the subscript of the anion is numerically equal to the charge on the cation and vice versa.
• Subscripts are discarded when the numerical charge on cation and anion are equal.
• When a metal has more than one positive oxidation state, its lowest oxidation number has name of the metal ion ending with ‘ous’ and highest oxidation number has name of the metal ion ending with ‘ic’. This rule is applicable when oxidation number of metal is not more than three.
• If a metal ion has multiple numbers of oxidation states more than three, then Roman numeral has to be used within square brackets to indicate the oxidation number of metal ion.
• Nomenclature of binary acids and oxoacids are not similar. Binary acids are named based on the non-metal atom present in them. Oxoacids are named on the basis of polyatomic anion present in them.
• Naming binary molecular compounds is also similar to binary ionic compounds.
• The first element is named as such while second element is added with prefix which describes the number of respective atoms present.

Answer to Problem 2.48QP

The given compound $F{e}_2{O}_3$ is named as Iron $\left(\text{III}\right)$ oxide.

Explanation of Solution

With reference to rules, anions and cations formed by various elements are named.

The cation and anion in $F{e}_2{O}_3$ are $F{e}^{3+}$ and $O_2^{-}$ respectively. Their names are iron ion and oxide ion respectively. The charge of iron ion $+3$ which has to be included as Roman numeral.

The compound is named as Iron $\left(\text{III}\right)$ oxide.

(i)

Interpretation Introduction

Interpretation:

The given compound $TiC{l}_4$ has to be named.

Concept Introduction:

Generally the ionic compound consists of cation and anion.

Cation: When electrons are removed from the atom that results to form positively charged ion called cation.

Anion: Addition of electron to atom results to form negatively charged ion called anion.

The nomenclature of inorganic compounds involves following rules:

• For ionic compounds first, metal cations are named first which then followed by nonmetallic anion.
• In ionic compound the metal cations generally hold their metal name itself and the metal anions hold their respective metal name with suffix $\text{"-ide"}$ with it.
• The prefixes on each atom indicate the number of those atoms in the compound.
• The number written on the subscript of the anion is numerically equal to the charge on the cation and vice versa.
• Subscripts are discarded when the numerical charge on cation and anion are equal.
• When a metal has more than one positive oxidation state, its lowest oxidation number has name of the metal ion ending with ‘ous’ and highest oxidation number has name of the metal ion ending with ‘ic’. This rule is applicable when oxidation number of metal is not more than three.
• If a metal ion has multiple numbers of oxidation states more than three, then Roman numeral has to be used within square brackets to indicate the oxidation number of metal ion.
• Nomenclature of binary acids and oxoacids are not similar. Binary acids are named based on the non-metal atom present in them. Oxoacids are named on the basis of polyatomic anion present in them.
• Naming binary molecular compounds is also similar to binary ionic compounds.
• The first element is named as such while second element is added with prefix which describes the number of respective atoms present.

Answer to Problem 2.48QP

The given compound $TiC{l}_4$ is named as Titanium $\left(IV\right)$ chloride.

Explanation of Solution

With reference to rules, anions and cations formed by various elements are named.

The cation and anion in $TiC{l}_4$ are $T{i}^{4+}$ and $C{l}^{-}$ respectively. Their names are titanium ion and chloride ion respectively. The charge of titanium is $\text{+4}$ which should be written in roman numerals.

The compound is named as Titanium $\left(IV\right)$ chloride.

(j)

Interpretation Introduction

Interpretation:

The given compound $NaH$ has to be named.

Concept Introduction:

Generally the ionic compound consists of cation and anion.

Cation: When electrons are removed from the atom that results to form positively charged ion called cation.

Anion: Addition of electron to atom results to form negatively charged ion called anion.

The nomenclature of inorganic compounds involves following rules:

• For ionic compounds first, metal cations are named first which then followed by nonmetallic anion.
• In ionic compound the metal cations generally hold their metal name itself and the metal anions hold their respective metal name with suffix $\text{"-ide"}$ with it.
• The prefixes on each atom indicate the number of those atoms in the compound.
• The number written on the subscript of the anion is numerically equal to the charge on the cation and vice versa.
• Subscripts are discarded when the numerical charge on cation and anion are equal.
• When a metal has more than one positive oxidation state, its lowest oxidation number has name of the metal ion ending with ‘ous’ and highest oxidation number has name of the metal ion ending with ‘ic’. This rule is applicable when oxidation number of metal is not more than three.
• If a metal ion has multiple numbers of oxidation states more than three, then Roman numeral has to be used within square brackets to indicate the oxidation number of metal ion.
• Nomenclature of binary acids and oxoacids are not similar. Binary acids are named based on the non-metal atom present in them. Oxoacids are named on the basis of polyatomic anion present in them.
• Naming binary molecular compounds is also similar to binary ionic compounds.
• The first element is named as such while second element is added with prefix which describes the number of respective atoms present.

Answer to Problem 2.48QP

The given compound $NaH$ is named as Sodium hydride.

Explanation of Solution

With reference to rules, anions and cations formed by various elements are named.

The cation and anion in $NaH$ are $N{a}^{+}$ and $H^{-}$ respectively. Their names are sodium ion and hydride ion respectively.

The compound is named as sodium hydride.

(k)

Interpretation Introduction

Interpretation:

The given compound $L{i}_{3}N$ has to be named.

Concept Introduction:

Generally the ionic compound consists of cation and anion.

Cation: When electrons are removed from the atom that results to form positively charged ion called cation.

Anion: Addition of electron to atom results to form negatively charged ion called anion.

The nomenclature of inorganic compounds involves following rules:

• For ionic compounds first, metal cations are named first which then followed by nonmetallic anion.
• In ionic compound the metal cations generally hold their metal name itself and the metal anions hold their respective metal name with suffix $\text{"-ide"}$ with it.
• The prefixes on each atom indicate the number of those atoms in the compound.
• The number written on the subscript of the anion is numerically equal to the charge on the cation and vice versa.
• Subscripts are discarded when the numerical charge on cation and anion are equal.
• When a metal has more than one positive oxidation state, its lowest oxidation number has name of the metal ion ending with ‘ous’ and highest oxidation number has name of the metal ion ending with ‘ic’. This rule is applicable when oxidation number of metal is not more than three.
• If a metal ion has multiple numbers of oxidation states more than three, then Roman numeral has to be used within square brackets to indicate the oxidation number of metal ion.
• Nomenclature of binary acids and oxoacids are not similar. Binary acids are named based on the non-metal atom present in them. Oxoacids are named on the basis of polyatomic anion present in them.
• Naming binary molecular compounds is also similar to binary ionic compounds.
• The first element is named as such while second element is added with prefix which describes the number of respective atoms present.

Answer to Problem 2.48QP

The given compound $L{i}_{3}N$ is named as Lithium nitride.

Explanation of Solution

With reference to rules, anions and cations formed by various elements are named.

The cation and anion in $L{i}_{3}N$ are $L{i}^{+}$ and $N^{3-}$ respectively. Their names are lithium ion and nitride ion respectively.

The compound is named as Lithium nitride.

(l)

Interpretation Introduction

Interpretation:

The given compound $N{a}_{2}O$ has to be named.

Concept Introduction:

Generally the ionic compound consists of cation and anion.

Cation: When electrons are removed from the atom that results to form positively charged ion called cation.

Anion: Addition of electron to atom results to form negatively charged ion called anion.

The nomenclature of inorganic compounds involves following rules:

• For ionic compounds first, metal cations are named first which then followed by nonmetallic anion.
• In ionic compound the metal cations generally hold their metal name itself and the metal anions hold their respective metal name with suffix $\text{"-ide"}$ with it.
• The prefixes on each atom indicate the number of those atoms in the compound.
• The number written on the subscript of the anion is numerically equal to the charge on the cation and vice versa.
• Subscripts are discarded when the numerical charge on cation and anion are equal.
• When a metal has more than one positive oxidation state, its lowest oxidation number has name of the metal ion ending with ‘ous’ and highest oxidation number has name of the metal ion ending with ‘ic’. This rule is applicable when oxidation number of metal is not more than three.
• If a metal ion has multiple numbers of oxidation states more than three, then Roman numeral has to be used within square brackets to indicate the oxidation number of metal ion.
• Nomenclature of binary acids and oxoacids are not similar. Binary acids are named based on the non-metal atom present in them. Oxoacids are named on the basis of polyatomic anion present in them.
• Naming binary molecular compounds is also similar to binary ionic compounds.
• The first element is named as such while second element is added with prefix which describes the number of respective atoms present.

Answer to Problem 2.48QP

The given compound $N{a}_{2}O$ is named as Sodium oxide.

Explanation of Solution

With reference to rules, anions and cations formed by various elements are named.

The cation and anion in $N{a}_{2}O$ are $N{a}^{+}$ and $O^{2-}$ respectively. Their names are sodium ion and oxide ion respectively.

The compound is named as Sodium oxide.

(m)

Interpretation Introduction

Interpretation:

The given compound $N{a}_2{O}_2$ has to be named.

Concept Introduction:

Generally the ionic compound consists of cation and anion.

Cation: When electrons are removed from the atom that results to form positively charged ion called cation.

Anion: Addition of electron to atom results to form negatively charged ion called anion.

The nomenclature of inorganic compounds involves following rules:

• For ionic compounds first, metal cations are named first which then followed by nonmetallic anion.
• In ionic compound the metal cations generally hold their metal name itself and the metal anions hold their respective metal name with suffix $\text{"-ide"}$ with it.
• The prefixes on each atom indicate the number of those atoms in the compound.
• The number written on the subscript of the anion is numerically equal to the charge on the cation and vice versa.
• Subscripts are discarded when the numerical charge on cation and anion are equal.
• When a metal has more than one positive oxidation state, its lowest oxidation number has name of the metal ion ending with ‘ous’ and highest oxidation number has name of the metal ion ending with ‘ic’. This rule is applicable when oxidation number of metal is not more than three.
• If a metal ion has multiple numbers of oxidation states more than three, then Roman numeral has to be used within square brackets to indicate the oxidation number of metal ion.
• Nomenclature of binary acids and oxoacids are not similar. Binary acids are named based on the non-metal atom present in them. Oxoacids are named on the basis of polyatomic anion present in them.
• Naming binary molecular compounds is also similar to binary ionic compounds.
• The first element is named as such while second element is added with prefix which describes the number of respective atoms present.

Answer to Problem 2.48QP

The given compound $N{a}_2{O}_2$ is named as Sodium peroxide.

Explanation of Solution

With reference to rules, anions and cations formed by various elements are named.

The cation and anion in $N{a}_2{O}_2$ are $N{a}^{+}$ and $O_2^2{}^{-}$ respectively. Their names are sodium ion and peroxide ion respectively.

The compound is named as Sodium peroxide.

(n)

Interpretation Introduction

Interpretation:

The given compound $FeC{l}_3.6H_{2}O$ has to be named.

Concept Introduction:

Generally the ionic compound consists of cation and anion.

Cation: When electrons are removed from the atom that results to form positively charged ion called cation.

Anion: Addition of electron to atom results to form negatively charged ion called anion.

The nomenclature of inorganic compounds involves following rules:

• For ionic compounds first, metal cations are named first which then followed by nonmetallic anion.
• In ionic compound the metal cations generally hold their metal name itself and the metal anions hold their respective metal name with suffix $\text{"-ide"}$ with it.
• The prefixes on each atom indicate the number of those atoms in the compound.
• The number written on the subscript of the anion is numerically equal to the charge on the cation and vice versa.
• Subscripts are discarded when the numerical charge on cation and anion are equal.
• When a metal has more than one positive oxidation state, its lowest oxidation number has name of the metal ion ending with ‘ous’ and highest oxidation number has name of the metal ion ending with ‘ic’. This rule is applicable when oxidation number of metal is not more than three.
• If a metal ion has multiple numbers of oxidation states more than three, then Roman numeral has to be used within square brackets to indicate the oxidation number of metal ion.
• Nomenclature of binary acids and oxoacids are not similar. Binary acids are named based on the non-metal atom present in them. Oxoacids are named on the basis of polyatomic anion present in them.
• Naming binary molecular compounds is also similar to binary ionic compounds.
• The first element is named as such while second element is added with prefix which describes the number of respective atoms present.

Answer to Problem 2.48QP

The given compound $FeC{l}_3.6H_{2}O$ is named as Iron $\left(III\right)$ chloride hexahydrate.

Explanation of Solution

With reference to rules, anions and cations formed by various elements are named.

The compound $FeC{l}_3.6H_{2}O$ has cation $F{e}^{3+}$ and anion $C{l}^{-}$. With reference to rules, the names of the ions are iron ion and chloride ion respectively. The charge of iron ion is $\text{+3}$ which have to be included as roman numerals. The given formula says that 6 water molecules are bonded to the molecule. Hence name of the compound is Iron $\left(III\right)$ chloride hexahydrate.

(o)

Interpretation Introduction

Interpretation:

The given compound ${\text{AsO}}_{\text{4}}^{\text{3-}}$ has to be named.

Concept Introduction:

Generally the ionic compound consists of cation and anion.

Cation: When electrons are removed from the atom that results to form positively charged ion called cation.

Anion: Addition of electron to atom results to form negatively charged ion called anion.

The nomenclature of inorganic compounds involves following rules:

• For ionic compounds first, metal cations are named first which then followed by nonmetallic anion.
• In ionic compound the metal cations generally hold their metal name itself and the metal anions hold their respective metal name with suffix $\text{"-ide"}$ with it.
• The prefixes on each atom indicate the number of those atoms in the compound.
• The number written on the subscript of the anion is numerically equal to the charge on the cation and vice versa.
• Subscripts are discarded when the numerical charge on cation and anion are equal.
• When a metal has more than one positive oxidation state, its lowest oxidation number has name of the metal ion ending with ‘ous’ and highest oxidation number has name of the metal ion ending with ‘ic’. This rule is applicable when oxidation number of metal is not more than three.
• If a metal ion has multiple numbers of oxidation states more than three, then Roman numeral has to be used within square brackets to indicate the oxidation number of metal ion.
• Nomenclature of binary acids and oxoacids are not similar. Binary acids are named based on the non-metal atom present in them. Oxoacids are named on the basis of polyatomic anion present in them.
• Naming binary molecular compounds is also similar to binary ionic compounds.
• The first element is named as such while second element is added with prefix which describes the number of respective atoms present.

Answer to Problem 2.48QP

The given compound ${\text{AsO}}_{\text{4}}^{\text{3-}}$ is named as Arsenate.

Explanation of Solution

With reference to rules, anions and cations formed by various elements are named.

The given anionic compound ${\text{AsO}}_{\text{4}}^{\text{3-}}$ is named as Arsenate.

(p)

Interpretation Introduction

Interpretation:

The given compound $HS{O}_3^{-}$ has to be named.

Concept Introduction:

Generally the ionic compound consists of cation and anion.

Cation: When electrons are removed from the atom that results to form positively charged ion called cation.

Anion: Addition of electron to atom results to form negatively charged ion called anion.

The nomenclature of inorganic compounds involves following rules:

• For ionic compounds first, metal cations are named first which then followed by nonmetallic anion.
• In ionic compound the metal cations generally hold their metal name itself and the metal anions hold their respective metal name with suffix $\text{"-ide"}$ with it.
• The prefixes on each atom indicate the number of those atoms in the compound.
• The number written on the subscript of the anion is numerically equal to the charge on the cation and vice versa.
• Subscripts are discarded when the numerical charge on cation and anion are equal.
• When a metal has more than one positive oxidation state, its lowest oxidation number has name of the metal ion ending with ‘ous’ and highest oxidation number has name of the metal ion ending with ‘ic’. This rule is applicable when oxidation number of metal is not more than three.
• If a metal ion has multiple numbers of oxidation states more than three, then Roman numeral has to be used within square brackets to indicate the oxidation number of metal ion.
• Nomenclature of binary acids and oxoacids are not similar. Binary acids are named based on the non-metal atom present in them. Oxoacids are named on the basis of polyatomic anion present in them.
• Naming binary molecular compounds is also similar to binary ionic compounds.
• The first element is named as such while second element is added with prefix which describes the number of respective atoms present.

Answer to Problem 2.48QP

The given compound $HS{O}_3^{-}$ is named as hydrogen sulfite.

Explanation of Solution

With reference to the rules, anions and cations formed by various elements are named.

The anionic compound $HS{O}_3^{-}$ has hydrogen and $S{O}_3^{-}$ is referred as sulfite. Therefore, the name of the compound is hydrogen sulfite.