Bundle: Principles Of Geotechnical Engineering, Loose-leaf Version, 9th + Mindtap Engineering, 1 Term (6 Months) Printed Access Card
9th Edition
ISBN: 9781337583848
Author: Braja M. Das, Khaled Sobhan
Publisher: Cengage Learning
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Question
Chapter 2, Problem 2.3P
(a)
To determine
Calculate the uniformity coefficient
(b)
To determine
State the sands A, B, and C are well-graded or a poorly-graded.
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Design a typical girder for the floor system shown in the figure below. In addition to the weight of the beam, the dead
load consists of a 5-inch-thick reinforced concrete slab (normal-weight concrete). The live load is 85 psf, and there is a
20-psf partition load. Do not check deflections. Assume that the girder is supporting beams on each side, and assume
that the beams weigh 35 lb / ft. Let all the loads on the girder act as a uniform load (be sure to include the weight of
the beams).
30'
A
-4 @ 5' = 20'
Use the table below.
-
Mn (ft-kips) Mn/ (ft-kips) | Vn (kips) Vn/v (kips)
Shape
W21 × 48
398
265
216
144
W12 × 58
324
216
132
87.8
W16 × 45
309
205
167
111
W18 × 40
294
196
169
113
a. Use LRFD.
Calculate the required moment strength and the maximum shear.
(Express your answers to three significant figures.)
Mu
-
Vu
Select a shape:
-Select-
b. Use ASD.
ft-kips
kips
Calculate the required moment strength and the maximum shear.
(Express your answers to three significant figures.)
Ma =…
Water in a tank is used to control the water pressure in a pipe as shown in Figure P5 below.
Find the pressure in the pipe at A if h = 200 mm and the mercury is at the elevation shown
(between points B and C). Assume standard atmospheric pressure and neglect the diameter
of the pipe. Express your answer in kPa.
Select a W-shape for the following conditions:
Beam spacing = 12 ft
Span length = 25 ft
Slab and deck combination weight = 43 psf
Partition load = 20 psf
Ceiling weight = 5 psf
Flooring weight = 2 psf
Live load 160 psf
Fy
= 50 ksi
The maximum live load deflection cannot exceed L/340.
Shape
Mp (ft-kips) M₁/ (ft-kips) Vn (kips) Vn/v (kips) Ix (in.
Vn/n, (kips) I. (in.)
W14 × 61
383
254
156
104
640
W21 × 44
358
238
217
145
843
W16 × 50
345
230
186
124
659
W18 × 46
340
226
195
130
712
a. Use LRFD.
Calculate the required moment of inertia, the required moment strength, and the maximum shear.
(Express your answers to three significant figures.)
Ix
=
in.
4
Μι
=
Vu
Select a shape:
-Select-
b. Use ASD.
ft-kips
kips
Calculate the required moment of inertia, the required moment strength, and the maximum shear.
(Express your answers to three significant figures.)
Ix
Ma
=
Va =
Select a shape:
-Select-
4
in.
ft-kips
kips
Chapter 2 Solutions
Bundle: Principles Of Geotechnical Engineering, Loose-leaf Version, 9th + Mindtap Engineering, 1 Term (6 Months) Printed Access Card
Ch. 2 - For a gravel with D60 = 0.48 mm, D30 = 0.25 mm,...Ch. 2 - Prob. 2.2PCh. 2 - Prob. 2.3PCh. 2 - The following are the results of a sieve analysis....Ch. 2 - Repeat Problem 2.4 with the following data. 2.4...Ch. 2 - Repeat Problem 2.4 with the following data. 2.4...Ch. 2 - Repeat Problem 2.4 with the following data. 2.4...Ch. 2 - The following are the results of a sieve and...Ch. 2 - Repeat Problem 2.8 using the following data. 2.8...Ch. 2 - Repeat Problem 2.8 using the following data. 2.8...
Ch. 2 - The grain-size characteristics of a soil are given...Ch. 2 - Repeat Problem 2.11 with the following data. 2.11...Ch. 2 - Repeat Problem 2.11 with the following data. 2.11...Ch. 2 - A hydrometer test has the following result: Gs =...Ch. 2 - Repeat Problem 2.14 with the following values: Gs...Ch. 2 - Three groups of students from the Geotechnical...Ch. 2 - Refer to Problem 2.C.1. Results of the sieve...
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- The beam shown in the figure below has continuous lateral support of both flanges. The uniform load is a service load consisting of 70% dead load and 30% live load. The dead load includes the weight of the beam. 6 k/ft +9 18' If A992 steel is used, is a W12 × 35 adequate? For A992 steel: Fy = 50 ksi. bf h For W12 x 35: = 6.31, = 36.2 in., Zx 2tf tw (Express your answers to three significant figures.) a. Use LRFD. Mu Фомп = ft-kips ft-kips A W12 × 35 is -Select- b. Use ASD. Ma = ft-kips Mn ft-kips 26 A W12 × 35 is -Select- = +6→ 51.2 in. 3arrow_forwardVerify the value of Zx for a W10 × 30 that is tabulated in the dimensions and properties tables in Part 1 of the Manual. For W10 × 30: Ag Use the table below. - 8.84 in.2, d 10.5 in. AISC Manual Label y (in.) WT 9 × 25 2.12 WT 8 × 25 1.89 WT 7 × 24 1.35 WT 6 × 25 1.17 WT 5 × 15 1.10 (Express your answer to three significant figures.) Zx = 3 in.arrow_forwarddetermine the horizontal displacement of joint A of the truss. Each member has a cross sectional area of A=300mm2, E=200GPa. Use the method of virtual work and show all workingarrow_forward
- For the frame shown below, determine the vertical displacement at C. Assume that flexural rigidities AB and BC segments are EI and 2EI, respectively. Use the method of virtual work and show all working.arrow_forwardDETERMINE THE BEARINGS OF THE POLYGON/TRAVERSEarrow_forward54 7h de зк +F B + 8 8 Ө 6 A=Sin² E=290ooks for diagonal members A= 30.25in² E = 1800 ksi for hoizontal & Vertical members For Primary Structure revive roller@c, make Da roller and cut BF For redundant structures Redundant " " 2 склес しん Ik @D 3 14 @ BF しん ↑arrow_forward
- A3.2- The 4.5m long cantilever beam is subjected to the specified uniformly distributed dead load 7.0 kN/m (including self-weight) and to the specified uniformly distributed live load 8.0 kN/m. The beam is made of normal density concrete containing maximum 20mm aggregate size with f'c = 25 MPa. Design the shear reinforcement for the beam using U-stirrups and fy = 400 MPa. Figure 2 WDL = 7.0 kN/m WLL=8.0 kN/m 4.5 m 450 mm' 380 mm *250 mm 3-30M Cross-sectionarrow_forwardA3.1- A simply supported beam is subjected to factored concentrated load of 400 kN at mid-span. The beam has a 10m span and a rectangular cross-section with bw = 350mm, effective depth d = 520mm, and total height h = 620mm. a) Ignor the self-weight of the beam and design the required shear reinforcement for the beam. Use 10M U-stirrups. b) Sketch the beam elevation and show the stirrups. Given: The beam is reinforced with 5-25M longitudinal bars f'c = 30 MPa fy = 400 MPa Maximum aggregate size: 20mm Figure 1 P= 400 kN k 5.0 m + 5.0 m 620 mm 520 mm 350 mm + Cross-sectionarrow_forward+ 54 7h de зк +F 8 B 8 Ө 6 For Primary Structure remove and cut BF For redundant structures Redundant " " 2 склес しん Ik @D 3 14 @ BF しん ↑ A=Sin² E=290ooks for diagonal members A= 30.25in² E = 1800 ksi for hoizontal & Vertical members roller@G, make Da rollerarrow_forward
- An urban freeway is to be designed using the following information. AADT = 52,600 veh/day K (proportion of AADT occurring during the peak hour): D (proportion of peak hour traffic traveling in the peak direction): Trucks: 0.11 0.65 8% of peak hour volume PHF = 0.94 Lane width: Shoulder width: Total ramp density: Terrain: 12 ft 10 ft 0.5 interchange/mile; all interchanges are to be cloverleaf interchanges rolling Determine the number of lanes in the peak direction required to provide LOS C. (Assume commuter traffic and assume no RVs.) lanes Show all calculations required. (Calculate your answers for the peak direction only. Enter fy the peak hour volume in veh/h, the free flow speed in mi/h, the demand flow rate in pc/h/In, the mean speed in mi/h, and the density in pc/mi/In.) fHV peak hour volume free flow speed demand flow rate mean speed veh/h mi/h pc/h/In mi/h density pc/mi/Inarrow_forwardThe beam shown in the figure below is a W16 × 31 of A992 steel and has continuous lateral support. The two concentrated loads are service live loads. Neglect the weight of the beam and determine whether the beam is adequate. Suppose that P = 56 k. For W16 x 31: d=15.9 in., t = 0.275 in., h/t = 51.6, and M = M₁ = 203 ft-kip, M/ P P = = Mp/ =135 ft-kip. 6' W16 x 31 a. Use LRFD. Calculate the required moment strength, the allowable shear strength, and the maximum shear. (Express your answers to three significant figures.) = Mu QvVn Vu = = Beam is -Select- b. Use ASD. ft-kip kips kips Calculate the required moment strength, the allowable shear strength, and the maximum shear. (Express your answers to three significant figures.) Ma = Vn/b Va = = Beam is -Select- ft-kip kips kipsarrow_forward***Please answer all parts. They are part of a single question and not different questions altogether. I will like the solution as well. Thank you!arrow_forward
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