Chapter 2, Problem 22CRP

Explanation of Solution

Determine the condition of machine with its program counter containing $0\times \text{00}$:

The address content of the program is shown as follows:

$\begin{array}{c}\text{01}\text{25}\\ \text{02}\text{B0}\\ \text{03}\text{35}\\ \text{04}\text{04}\\ \text{05}\text{C0}\\ \text{06}\text{00}\end{array}$

The program counter instruction register is as follows:

$\begin{array}{l}\text{00}\text{25B0}\\ \text{02}\text{3504}\\ \text{04}\text{B000}\\ \text{00}\text{25B0}\end{array}$

$\begin{array}{l}\text{02}\text{3504}\\ \text{04}\text{B000}\\ \text{00}\text{25B0}\\ \text{02}\text{3504}\end{array}$

$\begin{array}{l}\text{04}\text{B000}\\ \mathrm{..}\\ \mathrm{..}\\ \mathrm{..}\end{array}$

Explanation:

• The address $\text{B0}$ is placed in register $5$ because of the first instruction of the program provided for the execution