ELEMENTARY SURVEYING (LOOSELEAF)
15th Edition
ISBN: 9780134604701
Author: GHILANI
Publisher: PEARSON
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Chapter 2, Problem 2.24P
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6. A simply supported beam is subjected to uniformly distributed loads: a service dead load
WD =
5 kips/ft and a service live load w₁ =7 kips/ft. Use the load combination w₁ = 1.2WD +
1.6WL. Note that the shear force is expressed as V₂ = w₁ (-/-- x) where x is the distance from a
support. (65pts total)
The beam also has the following properties.
f = 4ksi,
fy = fyt = 60 ksi,
b = 18 in,
h = 26 in,
d = 24.5 in,
20ft
No. 4 bars, U-stirrups used, Normalweight concrete
(1) Calculate the required spacing of stirrups. (15pts)
(2) Calculate the maximum spacing. Also, determine the location along the beam where the
maximum spacing can be applied (i.e., the distance from support). (10pts)
(3) Show the stirrup designs along with the shear force diagram. Indicate the numbers and
spacings of stirrups. A transition between the required spacing and the maximum spacing is
unnecessary. (15pts)
(4) Assume the live load decreases, and, as a result, the factored shear force is 30 kips. Discuss
whether…
Chapter 2 Solutions
ELEMENTARY SURVEYING (LOOSELEAF)
Ch. 2 - List the five types of measurements that form the...Ch. 2 - Prob. 2.2PCh. 2 - Prob. 2.3PCh. 2 - Prob. 2.4PCh. 2 - Prob. 2.5PCh. 2 - Prob. 2.6PCh. 2 - Prob. 2.7PCh. 2 - Prob. 2.8PCh. 2 - Prob. 2.9PCh. 2 - Prob. 2.10P
Ch. 2 - Prob. 2.11PCh. 2 - Prob. 2.12PCh. 2 - Prob. 2.13PCh. 2 - Prob. 2.14PCh. 2 - Prob. 2.15PCh. 2 - Prob. 2.16PCh. 2 - Prob. 2.17PCh. 2 - Prob. 2.18PCh. 2 - Prob. 2.19PCh. 2 - Prob. 2.20PCh. 2 - Prob. 2.21PCh. 2 - Prob. 2.22PCh. 2 - Prob. 2.23PCh. 2 - Prob. 2.24PCh. 2 - Prob. 2.25PCh. 2 - Prob. 2.26PCh. 2 - Prob. 2.27PCh. 2 - Prob. 2.28PCh. 2 - Prob. 2.29PCh. 2 - Prob. 2.30PCh. 2 - Prob. 2.31PCh. 2 - Prob. 2.32P
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- 5. A singly reinforced beam has a width b = 16 in., a height h = 20 in., and an effective depth d = 18.5 in. The beam is reinforced with six No. 8 bars. The beam is subjected to a positive bending moment, causing the bottom of the beam to experience tension. (65pts total) The material properties are as follows: f = 5 ksi, fy = 60 ksi d 888 Six no. 8 bars (1) Find the bending moment [kips-in] that can cause tension cracks. Use the following parameters regarding the equivalent transformed section. Do not consider load and resistance factors. (15pts) - Neutral axis: 10.7 in. from the top face of beam - Moment of inertia: 12,550 in² around the neutral axis - Modulus of rupture: fƒ„ = 7.5√ƒ! [psi] (i.e., the concrete tensile stress for crack initiation) (2) Find the service moment strength [kips-in]. The allowable stress of concrete and steel is 0.45f, and 0.5fy, respectively. Do not consider load and resistance factors. (15pts) (3) Calculate the nominal moment strength M, and the design…arrow_forwardQ2) Determine the bar forces and reactions of the truss. ABD= 4 in², A= 2 in² and E=30000 kips/in². A D 20 ft 60 kips 15 ft Barrow_forwardL h Water Fig. P4 Hinge Farrow_forward
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