UNIVERSITY PHYSICS,VOL.1 (OER)
UNIVERSITY PHYSICS,VOL.1 (OER)
18th Edition
ISBN: 2810021150053
Author: OpenStax
Publisher: XANEDU
Textbook Question
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Chapter 2, Problem 2.1CYU

Check Your Understanding

The recommended daily amount of vitamin B3 or niacin, C6NH5 O2, for women who are not pregnant or nursing, is 14 mg. Find the number of molecule of niacin in that amount.

Expert Solution & Answer
Check Mark
To determine

The number of molecules of niacin in 14mg of C6NH5O2.

Answer to Problem 2.1CYU

The number of molecules of niacin in 14mg of C6NH5O2 is 6.85×1019molecules.

Explanation of Solution

Given:

The amount of vitamin B3, niacin or C6NH5O2 is m=14mg.

The number of mole of carbon is nc=6.

The number of mole of hydrogen is nh=5.

The number of mole of nitrogen is nnit=1mole.

The number of mole of oxygen is no=2mole.

Formula used:

The molar mass of niacin is given by

  mn=ncmc+nhmh+nnitmnit+nomo

The number of moles is given by

  n=mmm

The number of molecule is given by

  N=nNA

Calculation:

The molar mass of carbon is mc=12g/mole.

The molar mass of hydrogen is mh=1g/mole.

The molar mass of nitrogen is mnit=14g/mole.

The molar mass of oxygen is mo=16g/mole.

The molar mass of niacin is calculated as follows:

  mn=ncmc+nhmh+nnitmnit+nomo=6(12g/mole)+5(1g/mole)+1(14g/mole)+2(16g/mole)=(72g/mole)+(5g/mole)+(14g/mole)+(32g/mole)=123g/mole

The number of moles is calculated as follows:

  n=mmm=( 14mg)( 123g/ mole )=( 14mg)( 1g 1000mg )( 123g/ mole )=1.138×104mole

The Avogadro number is NA=6.02 × 1023molecules/mole.

The number of molecule is calculated as follows:

  N=nNA=(1.138× 10 4mole)(6.02 ×  10 23molecules/mole)=6.85×1019molecules

Conclusion:

Thus, the number of molecules of niacin in 14mg of C6NH5O2 is 6.85×1019molecules.

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Chapter 2 Solutions

UNIVERSITY PHYSICS,VOL.1 (OER)

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