PRACT STAT W/ ACCESS 6MO LOOSELEAF
PRACT STAT W/ ACCESS 6MO LOOSELEAF
4th Edition
ISBN: 9781319215361
Author: BALDI
Publisher: Macmillan Higher Education
Question
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Chapter 2, Problem 2.1AYK

(a)

To determine

To construct: the dot plot for the given data and comment about the shape, center and spread of the data.

(a)

Expert Solution
Check Mark

Answer to Problem 2.1AYK

Shape = Right skewed

Center = 290

Explanation of Solution

Given:

    164478.7251.3351.7173448.9300.6
    362272.4740.2329327.2270.5332.1
    288.8176.1282.2236.1358.2270.5290.7

Calculations:

The dot plot for the given dataset:

  PRACT STAT W/ ACCESS 6MO LOOSELEAF, Chapter 2, Problem 2.1AYK

The shape of the given data is Right skewed, center of the data is 290.

(b)

To determine

To calculate: the mean and medina for the given data and compare it with the dot plot’s center.

(b)

Expert Solution
Check Mark

Answer to Problem 2.1AYK

Mean = 319.25

Median = 290.7

Explanation of Solution

Formula used:

  Mean = xinMedian = { ( n + 1 2 ) Th tern,When n is odd ( n 2 ) Th term + ( n 2 +1 ) Th term 2,When n is even}

Calculation:

  Mean = 6704.221=319.25

  Median = ( 21+1 2)Th term=11Th term=290.7

The center value based on the dot plot is near to 290 and the center value median is 290.7, they are almost the same. The mean value of the data is 319.25.

The median is considered as the best measure of central tendency because the data is right skewed and when the data is skewed then median is considered best as it does not get affected by the extreme values.

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To  evaluate  the  success  of  a  1-year  experimental  program  designed  to  increase  the  mathematical achievement of underprivileged high school seniors, a random sample of participants in the program will be selected and their mathematics scores will be compared with the previous year’s  statewide  average  of  525  for  underprivileged  seniors.  The  researchers  want  to  determine  whether the experimental program has increased the mean achievement level over the previous year’s statewide average. If alpha=.05, what sample size is needed to have a probability of Type II error of at most .025 if the actual mean is increased to 550? From previous results, sigma=80.
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