ELEM PRIN OF CHEMICAL PROC(LL)+NEXTGEN
ELEM PRIN OF CHEMICAL PROC(LL)+NEXTGEN
20th Edition
ISBN: 9781119761006
Author: FELDER
Publisher: WILEY
Question
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Chapter 2, Problem 2.13P
Interpretation Introduction

(a)

Interpretation:

How many panels are required.

Concept introduction:

Kilowatt hour is a commercial unit of energy which is widely used in electrical application.

Kilowatt hour can be calculated by multiplying 1000 W with 3600 s. The consumption by home and other small business are measured in kilowatt hour while the consumption by medium and large-scale industries are measured in Megawatt hour.

Applying conversion factor to find the value of kWh as follows:

1kWh=1000×60×60=3600000J

Interpretation Introduction

(b)

Interpretation:  What would be total cost saving

Concept introduction:

Kilowatt hour is a commercial unit of energy which is widely used in electrical application.

Kilowatt hour can be calculated by multiplying 1000 W with 3600 s. The consumption by home and other small business are measured in kilowatt hour while the consumption by medium and large-scale industries are measured in Megawatt hour.

Applying conversion factor to find the value of kWh as follows:

1kWh=1000×60×60=3600000J

Interpretation Introduction

(c)

Interpretation:  Motivation to decide to install the solar panels

Concept introduction:

Kilowatt hour is a commercial unit of energy which is widely used in electrical application.

Kilowatt hour can be calculated by multiplying 1000 W with 3600 s. The consumption by home

and other small business are measured in kilowatt hour while the consumption by medium and

large-scale industries are measured in Megawatt hour.

Applying conversion factor to find the value of kWh as follows:

1kWh=1000×60×60=3600000J

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